Chapter 16, Problem 16.17QE

Interpretation Introduction

Interpretation:

Chemical equation has to be written for the reaction of ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ with lithium hydroxide and also the numbers of millimoles of ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ that are needed to react with $\text{25}\text{.0 mL of 0}\text{.244 M LiOH}$ has to be calculated.

Concept introduction:

The mole of the solution can be calculated by using following formula

  $\begin{array}{l}\text{Molarity of the solution}\text{=}\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}}{\text{Volume}\text{of}\text{solution}\text{in}\text{litre}}\\ \text{Number}\text{of}\text{moles}\text{=}\text{Molarity of the solution}\text{×}\text{Volume}\text{of}\text{solution}\text{in}\text{litre}\end{array}$