Chapter 16, Problem 16.102P

Interpretation Introduction

Interpretation:

The partial pressure of ${\text{NO}}_2$ has to be calculated.

Concept Introduction:

Mole fraction calculation:

$\text{Mole}\text{fraction}\text{of}\text{solute}\text{x}\text{in}\text{the}\text{mixture}\text{of}\text{x}\text{and}\text{y}\text{=}\frac{{\text{n}}_{\text{x}}}{{\text{n}}_{\text{x}}\text{+}{\text{n}}_{\text{y}}}$

Raoult’s law: Raoult’s law states that solvent partial pressure over a solution is equal to vapor pressure of pure solvent multiplied with mole fraction of the solvent.

  ${\text{P}}_{\text{1}}{\text{= χ}}_{\text{1}}{\text{P}}^{\text{°}}{}_{\text{1}}$

Where, ${\text{P}}_{\text{1}}=$ Partial pressure of solvent

${\text{P}}_{\text{1}}^{\circ }=$ Partial pressure of its pure solvent

  ${\text{χ}}_{\text{1}}=$ Mole fraction of the solvent

The solution that obeys Raoult’s law is defined as ideal solution.