When you speak after breathing helium, in which the speed of sound is much greater than in air, your voice sounds quite different. The frequencies emitted by your vocal cords do not change since they are determined by the mass and tension of your vocal cords. So what does change when your vocal tract is filled with helium rather than air?
When you speak after breathing helium, in which the speed of sound is much greater than in air, your voice sounds quite different. The frequencies emitted by your vocal cords do not change since they are determined by the mass and tension of your vocal cords. So what does change when your vocal tract is filled with helium rather than air?
When you speak after breathing helium, in which the speed of sound is much greater than in air, your voice sounds quite different. The frequencies emitted by your vocal cords do not change since they are determined by the mass and tension of your vocal cords. So what does change when your vocal tract is filled with helium rather than air?
Part A
m
2πkT
) 3/2
Calculate the integral (v) = f vƒ (v)dv. The function f(v) describing the actual distribution of molecular speeds is called the Maxwell-Boltzmann distribution,
=
ƒ(v) = 4π (· v²e-mv²/2kT
. (Hint: Make the change of variable v² =x and use the tabulated integral foxne
integer and a is a positive constant.)
Express your answer in terms of the variables T, m, and appropriate constants.
-ax dx
n!
-
an+1
where n is a positive
(v)
=
ΕΠΙ ΑΣΦ
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