Explanation (i) The dissociation of the following compound is, NH 4 NO 3 ( a q ) ⇌ NH 4 + ( a q ) + NO 3 − ( a q ) The conjugate base of strong acid does not alter the pH . NO 3 − is a conjugate base of strong base. So, it does not affect the pH of the solution. NH 4 + is a conjugate acid of weak base. So, it decreases the pH . Hence, the pH of the solution is acidic. (ii) The dissociation of the following compound is, NaNO 3 ( a q ) ⇌ Na + ( a q ) + NO 3 − ( a q ) The conjugate base of strong acid does not alter the pH . NO 3 − is a conjugate base of strong base. So, it does not affect the pH of the solution. Na belongs to group I and it is extremely weak acid such that it not even reacts with water so, it does not alter the pH of the reaction. Hence, the pH of the solution is neutral. (iii) The dissociation of the following compound is, NH 4 C 2 H 3 O 2 ( a q ) ⇌ NH 4 + ( a q ) + C 2 H 3 O 2 − ( a q ) The conjugate base of strong acid does not alter the pH . NH 4 + is a conjugate acid of weak base. C 2 H 3 O 2 − is a conjugate base of weak acid, the ions are extremely weak acid such that it not even reacts with water so, they does not alter the pH of the reaction Hence, the pH of the solution is neutral

19th Edition

ISBN: 9781323849996

Author: Brown

Publisher: Pearson Custom Publishing

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Chapter 16, Problem 110AE

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To determine: The correct order of increasing acidity for the given compounds.

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Chapter 16, Problem 109AE

Chapter 16, Problem 111AE

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Chapter 16 Solutions

CHEMISTRY VOL. 2 W/MASTERING CHEM. >IC<

Ch. 16.2 - Practice Exercise 1 Consider the following...Ch. 16.2 - Prob. 16.1.2PE Ch. 16.2 - Prob. 16.2.1PE Ch. 16.2 - Practice Exercise 2 When lithium oxide (Li2O) is...Ch. 16.2 - Based on information in Figure 16.4, place the...Ch. 16.2 - Practice Exercise 2 For each reaction, use Figure...Ch. 16.3 - Practice Exercise 1 In a certain acidic solution...Ch. 16.3 - Practice Exercise 2 Indicate whether solutions...Ch. 16.3 - Prob. 16.5.1PE Ch. 16.3 - Prob. 16.5.2PE

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