EBK ELECTRIC MOTOR CONTROL
10th Edition
ISBN: 9780100784598
Author: Herman
Publisher: YUZU
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Textbook Question
Chapter 16, Problem 10SQ
What type of chemical is used to cause a pressure change in a bellows-type thermostat?
Expert Solution & Answer
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Students have asked these similar questions
Can you rewrite the solution because it is
unclear?
AM
(+) = 8(1+0.5 cos 1000kt +0.5 ros 2000 thts)
=
cos 10000 πt.
8 cos wat + 4 cos wit + 4 cos Wat coswet.
J4000 t
j11000rt
$14+) = 45
jqooort
+4e
+ e
+ e
j 12000rt.
12000 kt
+ e
+e
+e
Le
jsoort
-; goon t
te
+e
Dcw>
= 885(W- 100007) + 8 IS (W-10000) -
USB
Can you rewrite the solution because it is
unclear?
Q2
AM
①(+) = 8 (1+0.5 cos 1000πt +0.5 ros 2000kt)
$4+) = 45
=
*cos 10000 πt.
8 cos wat + 4 cosat + 4 cos Wat coswet.
j1000016
+4e
-j10000πt j11000Rt
j gooort -j 9000 πt
+
e
+e
j sooort
te
+e
J11000 t
+ e
te
j 12000rt.
-J12000 kt
+ с
= 8th S(W- 100007) + 8 IS (W-10000)
<&(w) =
USB
-5-5
-4-5-4
b) Pc 2² = 64
PSB =
42
+ 4
2
Pt Pc+ PSB =
y = Pe
c) Puss =
PLSB =
= 32
4² = 8 w
32+ 8 =
× 100% = 140
(1)³×2×2
31
= 20%
x 2 = 3w
302
USB
4.5 5 5.6 6
ms Ac = 4 mi
= 0.5
mz Ac = 4
५
M2
=
=0.5
A. Draw the waveform for the following binary sequence using Bipolar RZ, Bipolar NRZ, and
Manchester code.
Data sequence= (00110100)
B. In a binary PCM system, the output signal-to-quantization ratio is to be hold to a minimum of
50 dB. If the message is a single tone with fm-5 kHz. Determine:
1) The number of required levels, and the corresponding output signal-to-quantizing noise ratio.
2) Minimum required system bandwidth.
Chapter 16 Solutions
EBK ELECTRIC MOTOR CONTROL
Ch. 16 - What are some applications of temperature-actuated...Ch. 16 - How is the average electrician involved with...Ch. 16 - Should a metal be heated or cooled to make it...Ch. 16 - Prob. 4SQCh. 16 - Prob. 5SQCh. 16 - Why should electrical contacts never be permitted...Ch. 16 - Prob. 7SQCh. 16 - Prob. 8SQCh. 16 - Why are thermistors often used as solid-state...Ch. 16 - What type of chemical is used to cause a pressure...
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- An FM signal with 75 kHz deviation, has an input signal-to-noise ratio of 18 dB, with a modulating frequency of 15 kHz. 1) Find SNRO at demodulator o/p. 2) Find SNRO at demodulator o/p if AM is used with m=0.3. 3) Compare the performance in case 1) and 2).. Hint: for single tone AM-DSB-LC, SNR₁ = (2m²) (4)arrow_forwardFind Va and Vb using Nodal analysisarrow_forwardCalculate the nodal voltage in the circuitarrow_forward
- Calculate the mesh currents, find Ia, Ib, Ic. Apply mesh analysisarrow_forwardFind Va and Vb using Nodal analysisarrow_forward4. A battery operated sensor transmits to a receiver that is plugged in to a power outlet. The device is continuously operated. The battery is a 3.6 V coin-cell battery with a 245mAHr capacity. The application requires a bit rate of 36 Mbps and an error rate of less than 10^-3. The channel has a center frequency of 2.4 GHz, a bandwidth of 10 MHz and a noise power spectral density of 10^-14 W/Hz. The maximum distance is 36 meters and the losses in the channel attenuates the signal by 0.25 dB/meter. Your company has two families of chips that you can use. An M-ary ASK and an M-ary QAM chip. The have very different power requirements as shown in the table below. The total current for the system is the current required to achieve the desired Eb/No PLUS the current identified below: Hokies PSK Chip Set Operating Current NOT Including the required Eb/No for the application Hokies QAM Chip Set Operating Current NOT Including the required Eb/No for the application Chip ID M-ary Voltage (volts)…arrow_forward
- Using the 802.11a specifications given below, in Matlab (or similar tool) create the time domain signal for one OFDM symbol using QPSK modulation. See attached plot for the QPSK constellation. Your results should include the power measure in the time and frequency domain and comment on those results. BW 802.11a OFDM PHY Parameters 20 MHZ OBW Subcarrer Spacing Information Rate Modulation Coding Rate Total Subcarriers Data Subcarriers Pilot Subcarriers DC Subcarrier 16.6 MHZ 312.5 Khz (20MHz/64 Pt FFT) 6/9/12/18/24/36/48/54 Mbits/s BPSK, QPSK, 16QAM, 64QAM 1/2, 2/3, 3/4 52 (Freq Index -26 to +26) 48 4 (-21, -7, +7, +21) *Always BPSK Null (0 subcarrier) 52 subarriers -7 (48 Data, 4 Pilot (BPSK), 1 Null) -26 -21 0 7 21 +26 14 One Subcarrier 1 OFDM symbol 1 OFDM Burst -OBW 16.6 MHz BW 20 MHZ 1 constellation point = 52 subcarriers = one or more OFDM symbols 802.11a OFDM Physical Parameters Show signal at this point x bits do Serial Data d₁ S₁ Serial-to- Input Signal Parallel Converter IFFT…arrow_forwardFind Vb and Va using Mesh analysisarrow_forward1. The communication channel bandwidth is 25 MHz centered at 1GHz and has a noise power spectral density of 10^-9 W/Hz. The channel loss between the transmitter and receiver is 25dB. The application requires a bit rate of 200Mbps and BER of less than 10^-4. Excluding Mary FSK, Determine the minimum transmit power required.arrow_forward
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