In Example 16-9, rather than use the quadratic formul at o solve the quadratic c equation, we could have proceeded in the following way Substitute the value yielded by our failed assumption — x = 0.0010—into the denominator of the quadrati c equation: that is, use 10 00250 -0.00102 as the value of [CH 2 NH 2 ] and solve for a new value of x Use this second value of x to re-evaluate [CH 3 NH 3 ]: [CH 2 NH 3 ] = 10 00250 -second value of x2 Solve the simple quadratic equation far a third value of x and so on. After three or four tnals. you will find that the value of x no longer changes This is thanswer you are seeking (a) Complete the calculation of the pH of 0.0250 M CH 2 NH 2 by this method and show that the result is the same as that obtained by using the quadratic formula (b) Use this method to determine the pH of 0.500 M HCIO
In Example 16-9, rather than use the quadratic formul at o solve the quadratic c equation, we could have proceeded in the following way Substitute the value yielded by our failed assumption — x = 0.0010—into the denominator of the quadrati c equation: that is, use 10 00250 -0.00102 as the value of [CH 2 NH 2 ] and solve for a new value of x Use this second value of x to re-evaluate [CH 3 NH 3 ]: [CH 2 NH 3 ] = 10 00250 -second value of x2 Solve the simple quadratic equation far a third value of x and so on. After three or four tnals. you will find that the value of x no longer changes This is thanswer you are seeking (a) Complete the calculation of the pH of 0.0250 M CH 2 NH 2 by this method and show that the result is the same as that obtained by using the quadratic formula (b) Use this method to determine the pH of 0.500 M HCIO
Solution Summary: The author explains the ionization of a base B by comparing it with the result obtained by quadratic equation method.
In Example 16-9, rather than use the quadratic formul at o solve the quadratic c equation, we could have proceeded in the following way Substitute the value yielded by our failed assumption — x = 0.0010—into the denominator of the quadrati c equation: that is, use 10 00250 -0.00102 as the value of [CH2NH2 ] and solve for a new value of x Use this second value of x to re-evaluate [CH3NH3]: [CH2NH3] = 10 00250 -second value of x2 Solve the simple quadratic equation far a third value of x and so on. After three or four tnals. you will find that the value of x no longer changes This is thanswer you are seeking (a) Complete the calculation of the pH of 0.0250 M CH2NH2 by this method and show that the result is the same as that obtained by using the quadratic formula (b) Use this method to determine the pH of 0.500 M HCIO
6. Draw the molecular orbital diagram shown to determine which of the following is paramagnetic.
B22+
B22+, B2, C22, B22 and N22+
Molecular Orbital Diagram
B2
C22-
B22-
N22+
Which molecule is paramagnetic?
3. Put the following species in order of increasing bond length by using molecular orbital diagrams and
calculating their bond orders: F2, F2, F2+
Molecular Orbital Diagram
F2
F2
F2+
Bond Order
Shortest bond:
Longest bond
3. Put the following species in order of increasing bond length by using molecular orbital diagrams and
calculating their bond orders: F2, F2, F2+
Molecular Orbital Diagram
F2
F2
F2+
Bond Order
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