In Example 16-9, rather than use the quadratic formul at o solve the quadratic c equation, we could have proceeded in the following way Substitute the value yielded by our failed assumption — x = 0.0010—into the denominator of the quadrati c equation: that is, use 10 00250 -0.00102 as the value of [CH 2 NH 2 ] and solve for a new value of x Use this second value of x to re-evaluate [CH 3 NH 3 ]: [CH 2 NH 3 ] = 10 00250 -second value of x2 Solve the simple quadratic equation far a third value of x and so on. After three or four tnals. you will find that the value of x no longer changes This is thanswer you are seeking (a) Complete the calculation of the pH of 0.0250 M CH 2 NH 2 by this method and show that the result is the same as that obtained by using the quadratic formula (b) Use this method to determine the pH of 0.500 M HCIO
In Example 16-9, rather than use the quadratic formul at o solve the quadratic c equation, we could have proceeded in the following way Substitute the value yielded by our failed assumption — x = 0.0010—into the denominator of the quadrati c equation: that is, use 10 00250 -0.00102 as the value of [CH 2 NH 2 ] and solve for a new value of x Use this second value of x to re-evaluate [CH 3 NH 3 ]: [CH 2 NH 3 ] = 10 00250 -second value of x2 Solve the simple quadratic equation far a third value of x and so on. After three or four tnals. you will find that the value of x no longer changes This is thanswer you are seeking (a) Complete the calculation of the pH of 0.0250 M CH 2 NH 2 by this method and show that the result is the same as that obtained by using the quadratic formula (b) Use this method to determine the pH of 0.500 M HCIO
Solution Summary: The author explains the ionization of a base B by comparing it with the result obtained by quadratic equation method.
In Example 16-9, rather than use the quadratic formul at o solve the quadratic c equation, we could have proceeded in the following way Substitute the value yielded by our failed assumption — x = 0.0010—into the denominator of the quadrati c equation: that is, use 10 00250 -0.00102 as the value of [CH2NH2 ] and solve for a new value of x Use this second value of x to re-evaluate [CH3NH3]: [CH2NH3] = 10 00250 -second value of x2 Solve the simple quadratic equation far a third value of x and so on. After three or four tnals. you will find that the value of x no longer changes This is thanswer you are seeking (a) Complete the calculation of the pH of 0.0250 M CH2NH2 by this method and show that the result is the same as that obtained by using the quadratic formula (b) Use this method to determine the pH of 0.500 M HCIO
Name the molecules & Identify any chiral center
CH3CH2CH2CHCH₂CH₂CH₂CH₂
OH
CH₂CHCH2CH3
Br
CH3
CH3CHCH2CHCH2CH3
CH3
Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electrons-pushing arrows for the following reaction or mechanistic step(s).
Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electrons-pushing arrows for the following reaction or mechanistic step(s).
Chapter 16 Solutions
General Chemistry: Principles and Modern Applications (11th Edition)
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