Chapter 16, Problem 104E

Interpretation Introduction

Interpretation:

The molarity of potassium hydroxide solution of volume $\text{27}\text{.4 mL}$ titrated with $\text{21}\text{.6 mL}$ of $\text{0}\text{.138 M HBr}$ is to be calculated.

Concept introduction:

An acid base reaction is one of the types of reaction which is known as neutralization reaction. Molarity is used to express concentration of solutions. The n factor of any species is defined in different way depending upon the type of reaction. In an acid base reaction n-factor is defined as the number of replaceable ${\text{H}}^{\text{+}}$ of an acid and for a base it is the total charge present on a species after removing all metal ions. Equation which equates the equivalents of an acid and a base is given below.

$\underset{\text{equivalents of acid }}{\underbrace{{\text{n}}_{\text{1}}{\text{M}}_{\text{1}}\text{V}}}=\underset{\text{equivalents of base }}{\underbrace{{\text{n}}_{\text{2}}{\text{M}}_{\text{2}}{\text{V}}_{\text{2}}}}$