Explanation A salt is formed when an acid and base react together. An acidic solution is a solution which denotes a proton. A basic solution is a solution which accepts a proton. A neutral solution is neither acidic nor basic. In order to classify a salt into acidic, basic or neutral we must remember that when a salt is formed between a strong acid and weak base, then it is a acidic solution. Similarly when a salt is between a weak acid and a strong base than it is a basic solution and when a salt is formed between a strong acid and strong base or weak acid or weak base,then it neutralizes each other and forms a neutral solution. In case if a salt solution has a weak base and weak acid, we can compare their dissociation constant value to classify it in acidic or basic solution. Given: a) Al ( NO 3 ) 3 Here NO − 3 ion is the conjugate base obtained from a strong acid HNO 3 HNO 3 ↔ H + + NO − 3 Now in the salt solution Al 3+ is the conjugate acid obtained from a weak base Al ( OH 3 ). Now this Al 3+ in water produces a proton. Al 3+ +3 H 2 O ↔ Al ( OH 3 )+ H + Here both the cation and anion produces proton and also the weak base Al ( OH 3 ). which gives Al 3+ and the strong acid HNO 3 which gives NO 3 . Therefore it is a salt which is formed between a strong acid and weak base. So it is a acidic solution Therefore, Al ( NO 3 ) 3 is a acidic solution b) C 2 H 5 NH 3 NO 2 Here C 2 H 5 NH + 3 is the conjugate acid of a weak base C 2 H 5 NH 2 and NO − 2 is the conjugate base of the weak acid HNO 2 . In order to classify we will compare their dissociation constant. Now for weak base C 2 H 5 NH 2 K b =4.5×10 −4 Now the conjugate acid of the weak base is C 2 H 5 NH + 3 . So we will calculate K a for the conjugate acid using the relation K a × K b = K w Where K w is the ionic product of water K a is the dissociation constant for C 2 H 5 NH + 3 K b is the dissociation constant for C 2 H 5 NH 2 K a = K w K b K a = 1 × 10 − 14 4.5 × 10 − 4 K a =2.22×10 −11 Similarly For weak acid HNO 2 K a =4×10 −4 Now the conjugate acid of the weak base is NO − 2 . So we will calculate K b for the conjugate acid using the relation K a × K b = K w Where K w is the ionic product of water K a is the dissociation constant for HNO 2 . K b is the dissociation constant for NO − 2 K a = K w K a K b = 1 × 10 − 14 4 × 10 − 4 K b =2.5×10 −11 After comparing we can see that NO − 2 is a better base than C 2 H 5 NH + 3 which is a acid as K b > K a Therefore the solution is basic c) K 2 CO 3 Here CO 2- 3 ion is the conjugate base obtained from a weak acid HCO − ...

Chemistry: Structure and Properties (2nd Edition)

2nd Edition

ISBN: 9780134293936

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 16, Problem 104E

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The given salt will form a solution that is acidic, basic or pH neutral

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Chapter 16, Problem 103E

Chapter 16, Problem 105E

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Chapter 16 Solutions

Chemistry: Structure and Properties (2nd Edition)

Ch. 16 - In the opening section of this chapter text, we...Ch. 16 - What are the general physical and chemical...Ch. 16 - What is a carboxylic acid? Give an example?Ch. 16 - What is the Arrhenius definition of an acid? Of a...Ch. 16 - What is a hydronium ion? Does H+ exist in solution...Ch. 16 - What is the Bronsted-Lowry definition of an acid?...Ch. 16 - Why is there more than one definition of acid-base...Ch. 16 - Describe amphoteric behavior and give an example.Ch. 16 - What is a conjugate acid-base pair? Provide an...Ch. 16 - Explain the difference between a strong acid and a...

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The given salt will form a solution that is acidic, basic or pH neutral

Solution Summary: The author explains that a salt is formed when an acid and base react together. A neutral solution is neither acidic nor basic.

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To determine: The given salt will form a solution that is acidic, basic or pH neutral

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Chapter 16 Solutions

To determine:

The given salt will form a solution that is acidic, basic or pH neutral