Explanation Given: Mass of lithium is 2 .50 g . Volume of the solution is 1 .500 L . Formula used: Number of moles calculated by the formula, n = m M Where, n is the number of moles. m is the mass of the molecule. M is the molar mass of the molecule. M = n V Where, M is the molarity. n is the number of moles. V is the volume of the solution. Calculation: The molar mass of Li 2 O is, = ( 2×6 .94 g/mol ) + ( 16 g/mol ) = 29 .88 g/mol Number of moles calculated by the formula, n = m M Where, n is the number of moles. m is the mass of the molecule. M is the molar mass of the molecule. Substitute the value of mass of Li 2 O and molar mass of Li 2 O in the above formula. n = 2 .50 g 29 .88 g/mol = 0 .083 mol Molarity is calculated by the following formula, M = n V Where, M is the molarity. n is the number of moles. V is the volume of the solution. Substitute the value of number of moles of Li 2 O and volume of the solution in the above expression

14th Edition

ISBN: 9780136781509

Author: Brown

Publisher: PEARSON CO

See similar textbooks

Concept explainers

Ionic Equilibrium

Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibri…

Arrhenius Acid

Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.

Bronsted Lowry Base In Inorganic Chemistry

Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.

Videos

Question

Chapter 16, Problem 104AE

Interpretation Introduction

To determine: The value of pH for the given reaction.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 16, Problem 103AE

Chapter 16, Problem 105AE

Students have asked these similar questions

Help me understand this! Thank you in advance.

22.22 For each compound, indicate which group on the ring is more strongly activating and then draw a structural formula of the major product formed by nitration of the compound. Br CHO (a) CH3 (b) (c) CHO CH3 SO₂H (d) ☑ OCHS NO₂ (e) (f) CO₂H NHCOCH3 NHCOCH, (h) CHS 22.23 The following molecules each contain two aromatic rings. (b) 000-100- H3C (a) (c) Which ring in each undergoes electrophilic aromatic substitution more readily? Draw the major product formed on nitration.

V Consider this step in a radical reaction: Br: ? What type of step is this? Check all that apply. Draw the products of the step on the right-hand side of the drawing area below. If more than one set of products is possible, draw any set. Also, draw the mechanism arrows on the left-hand side of the drawing area to show how this happens. ⚫ionization termination initialization neutralization none of the abc Explanation Check 80 Ο F3 F1 F2 2 F4 01 % do5 $ 94 #3 X 5 C MacBook Air 25 F5 F6 66 ©2025 ˇ F7 29 & 7 8

Chapter 16 Solutions

EP CHEMISTRY:CENTRAL..-MOD.MASTERING

Ch. 16.2 - Practice Exercise 1 Consider the following...Ch. 16.2 - Prob. 16.1.2PE Ch. 16.2 - Prob. 16.2.1PE Ch. 16.2 - Practice Exercise 2 When lithium oxide (Li2O) is...Ch. 16.2 - Based on information in Figure 16.4, place the...Ch. 16.2 - Practice Exercise 2 For each reaction, use Figure...Ch. 16.3 - Practice Exercise 1 In a certain acidic solution...Ch. 16.3 - Practice Exercise 2 Indicate whether solutions...Ch. 16.3 - Prob. 16.5.1PE Ch. 16.3 - Prob. 16.5.2PE

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.