The structure for a hydrocarbon with the following spectral characteristics is to be identified. Mass spectrum: M + at 120. 1 HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz). Concept introduction: The molecular ion peak gives the approximate molecular mass of the compound. In 1 HNMR spectrum aromatic protons give a broad peak in the range 6.5Î´-8.0Î´, the primary alkyl protons around 0.7Î´-1.3Î´, the secondary alkyl protons around 1.2Î´-1.6Î´, and a tertiary alkyl protons in between 1.4Î´-1.8Î´. The multiplicity of a signal gives an idea about the protons present in the adjacent carbons. To identify: The structure for a hydrocarbon with the following spectral characteristics. Mass spectrum: M + at 120. 1HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz).

Question

Want to see the full answer?

Answer 1

Question

Chapter 15.SE, Problem 40AP

Interpretation Introduction

Interpretation:

The structure for a hydrocarbon with the following spectral characteristics is to be identified.

Mass spectrum: M⁺ at 120.

¹HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz).

Concept introduction:

The molecular ion peak gives the approximate molecular mass of the compound. In ¹HNMR spectrum aromatic protons give a broad peak in the range 6.5Î´-8.0Î´, the primary alkyl protons around 0.7Î´-1.3Î´, the secondary alkyl protons around 1.2Î´-1.6Î´, and a tertiary alkyl protons in between 1.4Î´-1.8Î´. The multiplicity of a signal gives an idea about the protons present in the adjacent carbons.

To identify:

The structure for a hydrocarbon with the following spectral characteristics.

Mass spectrum: M⁺ at 120. 1HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Please use the information from the spectrum to answer these questions

Don't used hand raiting

Don't used Ai solution and don't used hand raiting

Answer 2

Question

Chapter 15.SE, Problem 40AP

Interpretation Introduction

Interpretation:

The structure for a hydrocarbon with the following spectral characteristics is to be identified.

Mass spectrum: M⁺ at 120.

¹HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz).

Concept introduction:

The molecular ion peak gives the approximate molecular mass of the compound. In ¹HNMR spectrum aromatic protons give a broad peak in the range 6.5Î´-8.0Î´, the primary alkyl protons around 0.7Î´-1.3Î´, the secondary alkyl protons around 1.2Î´-1.6Î´, and a tertiary alkyl protons in between 1.4Î´-1.8Î´. The multiplicity of a signal gives an idea about the protons present in the adjacent carbons.

To identify:

The structure for a hydrocarbon with the following spectral characteristics.

Mass spectrum: M⁺ at 120. 1HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 15.SE, Problem 40AP

Interpretation Introduction

Interpretation:

The structure for a hydrocarbon with the following spectral characteristics is to be identified.

Mass spectrum: M⁺ at 120.

¹HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz).

Concept introduction:

The molecular ion peak gives the approximate molecular mass of the compound. In ¹HNMR spectrum aromatic protons give a broad peak in the range 6.5Î´-8.0Î´, the primary alkyl protons around 0.7Î´-1.3Î´, the secondary alkyl protons around 1.2Î´-1.6Î´, and a tertiary alkyl protons in between 1.4Î´-1.8Î´. The multiplicity of a signal gives an idea about the protons present in the adjacent carbons.

To identify:

The structure for a hydrocarbon with the following spectral characteristics.

Mass spectrum: M⁺ at 120. 1HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 15.SE, Problem 40AP

Interpretation Introduction

Interpretation:

The structure for a hydrocarbon with the following spectral characteristics is to be identified.

Mass spectrum: M⁺ at 120.

¹HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz).

Concept introduction:

The molecular ion peak gives the approximate molecular mass of the compound. In ¹HNMR spectrum aromatic protons give a broad peak in the range 6.5Î´-8.0Î´, the primary alkyl protons around 0.7Î´-1.3Î´, the secondary alkyl protons around 1.2Î´-1.6Î´, and a tertiary alkyl protons in between 1.4Î´-1.8Î´. The multiplicity of a signal gives an idea about the protons present in the adjacent carbons.

To identify:

The structure for a hydrocarbon with the following spectral characteristics.

Mass spectrum: M⁺ at 120. 1HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 15.SE, Problem 40AP

Interpretation Introduction

Interpretation:

The structure for a hydrocarbon with the following spectral characteristics is to be identified.

Mass spectrum: M⁺ at 120.

¹HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz).

Concept introduction:

The molecular ion peak gives the approximate molecular mass of the compound. In ¹HNMR spectrum aromatic protons give a broad peak in the range 6.5Î´-8.0Î´, the primary alkyl protons around 0.7Î´-1.3Î´, the secondary alkyl protons around 1.2Î´-1.6Î´, and a tertiary alkyl protons in between 1.4Î´-1.8Î´. The multiplicity of a signal gives an idea about the protons present in the adjacent carbons.

To identify:

The structure for a hydrocarbon with the following spectral characteristics.

Mass spectrum: M⁺ at 120. 1HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz).

Answer 6

Chapter 15.SE, Problem 40AP

Interpretation Introduction

Interpretation:

The structure for a hydrocarbon with the following spectral characteristics is to be identified.

Mass spectrum: M⁺ at 120.

¹HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz).

Concept introduction:

The molecular ion peak gives the approximate molecular mass of the compound. In ¹HNMR spectrum aromatic protons give a broad peak in the range 6.5Î´-8.0Î´, the primary alkyl protons around 0.7Î´-1.3Î´, the secondary alkyl protons around 1.2Î´-1.6Î´, and a tertiary alkyl protons in between 1.4Î´-1.8Î´. The multiplicity of a signal gives an idea about the protons present in the adjacent carbons.

To identify:

The structure for a hydrocarbon with the following spectral characteristics.

Mass spectrum: M⁺ at 120. 1HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz).

Answer 7

Chapter 15.SE, Problem 40AP

Interpretation Introduction

Interpretation:

The structure for a hydrocarbon with the following spectral characteristics is to be identified.

Mass spectrum: M⁺ at 120.

¹HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz).

Concept introduction:

The molecular ion peak gives the approximate molecular mass of the compound. In ¹HNMR spectrum aromatic protons give a broad peak in the range 6.5Î´-8.0Î´, the primary alkyl protons around 0.7Î´-1.3Î´, the secondary alkyl protons around 1.2Î´-1.6Î´, and a tertiary alkyl protons in between 1.4Î´-1.8Î´. The multiplicity of a signal gives an idea about the protons present in the adjacent carbons.

To identify:

The structure for a hydrocarbon with the following spectral characteristics.

Mass spectrum: M⁺ at 120. 1HNMR spectrum: 7.25Î´ (5H, broad singlet); 2.90Î´ (1H, septet, J=7 Hz); 1.22Î´ (6H, doublet, J=7 Hz).

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 11

Ch. 15.1 - Prob. 1P Ch. 15.1 - Give IUPAC names for the following compounds:Ch. 15.1 - Prob. 3P Ch. 15.2 - Pyridine is a flat, hexagonal molecule with bond...Ch. 15.3 - Prob. 5P Ch. 15.4 - Draw the five resonance structures of the...Ch. 15.4 - Prob. 7P Ch. 15.4 - Prob. 8P Ch. 15.5 - Prob. 9P Ch. 15.5 - Prob. 10P

Solution Summary: The author explains the structure of a hydrocarbon with the following spectral characteristics.

Concept explainers

Videos

Want to see the full answer?

Chapter 15 Solutions