Introduction to Probability and Statistics
14th Edition
ISBN: 9781133103752
Author: Mendenhall, William
Publisher: Cengage Learning
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Chapter 15.6, Problem 15.34E
(a)
To determine
To find: Whether data provide sufficient evidence to indicate a difference in location for at least two of the population distributions of mean length corresponding to four locations.
(b)
To determine
To find: The p -value for the test.
(c)
To determine
To find: The p -value for the F -test that could be used in comparison of four location means
(d)
To determine
To compare: The p -values mentioned in part (b) and (c). Also, explain the implications.
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Microsoft Excel snapshot for random sampling: Also note the formula used for the last
column
02
x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51))
A
B
1
No.
States
2
1
ALABAMA
Rand No.
0.925957526
3
2
ALASKA
0.372999976
4
3
ARIZONA
0.941323044
5
4 ARKANSAS
0.071266381
Random Sample
CALIFORNIA
NORTH CAROLINA
ARKANSAS
WASHINGTON
G7
Microsoft Excel snapshot for systematic sampling:
xfx INDEX(SD52:50551, F7)
A
B
E
F
G
1
No.
States
Rand No. Random Sample
population
50
2
1 ALABAMA
0.5296685 NEW HAMPSHIRE
sample
10
3
2 ALASKA
0.4493186 OKLAHOMA
k
5
4
3 ARIZONA
0.707914 KANSAS
5
4 ARKANSAS 0.4831379 NORTH DAKOTA
6
5 CALIFORNIA 0.7277162 INDIANA
Random Sample
Sample Name
7
6 COLORADO 0.5865002 MISSISSIPPI
8
7:ONNECTICU 0.7640596 ILLINOIS
9
8 DELAWARE 0.5783029 MISSOURI
525
10
15
INDIANA
MARYLAND
COLORADO
Suppose the Internal Revenue Service reported that the mean tax refund for the year 2022 was $3401. Assume the standard deviation is $82.5 and that the amounts refunded follow a normal probability distribution. Solve the following three parts? (For the answer to question 14, 15, and 16, start with making a bell curve. Identify on the bell curve where is mean, X, and area(s) to be determined.
1.What percent of the refunds are more than $3,500?
2. What percent of the refunds are more than $3500 but less than $3579?
3. What percent of the refunds are more than $3325 but less than $3579?
A normal distribution has a mean of 50 and a standard deviation of 4. Solve the following three parts?
1. Compute the probability of a value between 44.0 and 55.0.
(The question requires finding probability value between 44 and 55. Solve it in 3 steps.
In the first step, use the above formula and x = 44, calculate probability value.
In the second step repeat the first step with the only difference that x=55.
In the third step, subtract the answer of the first part from the answer of the second part.)
2. Compute the probability of a value greater than 55.0.
Use the same formula, x=55 and subtract the answer from 1.
3. Compute the probability of a value between 52.0 and 55.0.
(The question requires finding probability value between 52 and 55. Solve it in 3 steps.
In the first step, use the above formula and x = 52, calculate probability value.
In the second step repeat the first step with the only difference that x=55.
In the third step, subtract the answer of the first part from the…
Chapter 15 Solutions
Introduction to Probability and Statistics
Ch. 15.2 - Prob. 15.1ECh. 15.2 - Prob. 15.2ECh. 15.2 - Prob. 15.3ECh. 15.2 - Prob. 15.4ECh. 15.2 - Prob. 15.5ECh. 15.2 - Prob. 15.6ECh. 15.2 - Prob. 15.7ECh. 15.2 - Prob. 15.8ECh. 15.2 - Prob. 15.10ECh. 15.2 - Prob. 15.12E
Ch. 15.3 - Prob. 15.13ECh. 15.3 - Prob. 15.14ECh. 15.3 - Prob. 15.15ECh. 15.3 - Prob. 15.16ECh. 15.3 - Prob. 15.17ECh. 15.3 - Prob. 15.18ECh. 15.3 - Prob. 15.19ECh. 15.3 - Prob. 15.20ECh. 15.5 - Prob. 15.21ECh. 15.5 - Prob. 15.22ECh. 15.5 - Prob. 15.23ECh. 15.5 - Prob. 15.24ECh. 15.5 - Prob. 15.25ECh. 15.5 - Prob. 15.26ECh. 15.5 - Prob. 15.28ECh. 15.5 - Prob. 15.30ECh. 15.6 - Prob. 15.32ECh. 15.6 - Prob. 15.33ECh. 15.6 - Prob. 15.34ECh. 15.6 - Prob. 15.35ECh. 15.6 - Prob. 15.37ECh. 15.7 - Prob. 15.38ECh. 15.7 - Prob. 15.39ECh. 15.7 - Prob. 15.40ECh. 15.7 - Prob. 15.41ECh. 15.7 - Prob. 15.42ECh. 15.8 - Prob. 15.43ECh. 15.8 - Prob. 15.44ECh. 15.8 - Prob. 15.45ECh. 15.8 - Prob. 15.46ECh. 15.8 - Prob. 15.50ECh. 15.8 - Prob. 15.51ECh. 15.8 - Prob. 15.53ECh. 15.8 - Prob. 15.54ECh. 15 - Prob. 15.55SECh. 15 - Prob. 15.56SECh. 15 - Identical Twins to compare two junior high...Ch. 15 - Identical Twins II Refer to Exercise 15.57. What...Ch. 15 - Prob. 15.59SECh. 15 - Meat Tenderizers An experiment was conducted to...Ch. 15 - Prob. 15.62SECh. 15 - Prob. 15.63SECh. 15 - Prob. 15.65SECh. 15 - Prob. 15.66SECh. 15 - Yield of Wheat Exercise 11.68 presented ananalysis...Ch. 15 - Prob. 15.68SECh. 15 - Prob. 15.69SECh. 15 - Prob. 15.70SECh. 15 - Prob. 15.71SECh. 15 - Prob. 15.72SECh. 15 - Prob. 15.73SECh. 15 - Prob. 15.74SECh. 15 - Prob. 15.75SECh. 15 - Prob. 15.77SECh. 15 - Prob. 15.78SECh. 15 - Prob. 15.79SECh. 15 - Prob. 1CSCh. 15 - Prob. 2CSCh. 15 - Prob. 3CS
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