EBK ENGINEERING FUNDAMENTALS: AN INTROD
5th Edition
ISBN: 8220100543401
Author: MOAVENI
Publisher: CENGAGE L
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Chapter 15.2, Problem 2BYG
To determine
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A3.1- A simply supported beam is subjected to factored concentrated load of 400 kN at
mid-span. The beam has a 10m span and a rectangular cross-section with bw = 350mm,
effective depth d = 520mm, and total height h = 620mm.
a) Ignor the self-weight of the beam and design the required shear reinforcement for the
beam. Use 10M U-stirrups.
b) Sketch the beam elevation and show the stirrups.
Given: The beam is reinforced with 5-25M longitudinal bars
f'c = 30 MPa
fy = 400 MPa
Maximum aggregate size: 20mm
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A=Sin² E=290ooks for
diagonal members
A= 30.25in² E = 1800 ksi
for hoizontal &
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roller@G, make Da roller
An urban freeway is to be designed using the following information.
AADT = 52,600 veh/day
K (proportion of AADT occurring during the peak hour):
D (proportion of peak hour traffic traveling in the peak direction):
Trucks:
0.11
0.65
8% of peak hour volume
PHF = 0.94
Lane width:
Shoulder width:
Total ramp density:
Terrain:
12 ft
10 ft
0.5 interchange/mile; all interchanges are to be cloverleaf interchanges
rolling
Determine the number of lanes in the peak direction required to provide LOS C. (Assume commuter traffic and assume no RVs.)
lanes
Show all calculations required. (Calculate your answers for the peak direction only. Enter fy the peak hour volume in veh/h, the free flow speed in mi/h, the demand flow rate in pc/h/In, the mean speed in mi/h, and the density in pc/mi/In.)
fHV
peak hour volume
free flow speed
demand flow rate
mean speed
veh/h
mi/h
pc/h/In
mi/h
density
pc/mi/In
Chapter 15 Solutions
EBK ENGINEERING FUNDAMENTALS: AN INTROD
Ch. 15.1 - Prob. 1BYGCh. 15.1 - Prob. 2BYGCh. 15.1 - Prob. 3BYGCh. 15.1 - Prob. 4BYGCh. 15.1 - Prob. 5BYGCh. 15.2 - Prob. 1BYGCh. 15.2 - Prob. 2BYGCh. 15.2 - Prob. 3BYGCh. 15.2 - What is an M-file?Ch. 15.5 - Prob. 1BYG
Ch. 15.5 - Prob. 2BYGCh. 15.5 - Prob. 3BYGCh. 15.5 - Prob. 4BYGCh. 15.5 - Prob. 5BYGCh. 15 - Prob. 1PCh. 15 - Prob. 2PCh. 15 - Prob. 3PCh. 15 - Prob. 4PCh. 15 - Prob. 5PCh. 15 - Prob. 6PCh. 15 - Prob. 7PCh. 15 - Prob. 8PCh. 15 - Prob. 9PCh. 15 - Prob. 10PCh. 15 - Prob. 11PCh. 15 - Prob. 12PCh. 15 - Prob. 13PCh. 15 - Prob. 14PCh. 15 - Prob. 15PCh. 15 - Prob. 16PCh. 15 - Prob. 17PCh. 15 - Prob. 18PCh. 15 - Prob. 19PCh. 15 - Prob. 20PCh. 15 - Prob. 21PCh. 15 - Prob. 22PCh. 15 - Prob. 23PCh. 15 - Prob. 24PCh. 15 - Prob. 25PCh. 15 - Prob. 26PCh. 15 - Prob. 27PCh. 15 - Prob. 28PCh. 15 - Prob. 29PCh. 15 - Prob. 30PCh. 15 - Prob. 31PCh. 15 - The Body Mass Index (BMI) is a way of determining...Ch. 15 - Prob. 33PCh. 15 - Prob. 34PCh. 15 - Prob. 35PCh. 15 - Prob. 36PCh. 15 - Prob. 37PCh. 15 - Prob. 38PCh. 15 - Prob. 39PCh. 15 - Prob. 40P
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- The beam shown in the figure below is a W16 × 31 of A992 steel and has continuous lateral support. The two concentrated loads are service live loads. Neglect the weight of the beam and determine whether the beam is adequate. Suppose that P = 56 k. For W16 x 31: d=15.9 in., t = 0.275 in., h/t = 51.6, and M = M₁ = 203 ft-kip, M/ P P = = Mp/ =135 ft-kip. 6' W16 x 31 a. Use LRFD. Calculate the required moment strength, the allowable shear strength, and the maximum shear. (Express your answers to three significant figures.) = Mu QvVn Vu = = Beam is -Select- b. Use ASD. ft-kip kips kips Calculate the required moment strength, the allowable shear strength, and the maximum shear. (Express your answers to three significant figures.) Ma = Vn/b Va = = Beam is -Select- ft-kip kips kipsarrow_forward***Please answer all parts. They are part of a single question and not different questions altogether. I will like the solution as well. Thank you!arrow_forwardConsider the geometric and traffic characteristics shown below. Approach (Width) Peak hour Approach Volumes: Left Turn Through Movement Right Turn Conflicting Pedestrian Volumes PHF For the following saturation flows: North (56 ft) South (56 ft) East (68 ft) West (68 ft) 165 105 200 166 442 395 585 538 162 157 191 200 900 1,200 1,200 900 0.95 0.95 0.95 0.95 Through lanes: 1,600 veh/h/in Through-right lanes: 1,400 veh/h/in Left lanes: 1,000 veh/h/in Left-through lanes: 1,200 veh/h/in Left-through-right lanes: 1,100 veh/h/in The total cycle length was 277 s. Now assume the saturation flow rates are 10% higher, that is, assume the following saturation flow rates: Through lanes: Through-right lanes: Left lanes: Left-through lanes: Left-through-right lanes: 1,760 veh/h/in 1,540 veh/h/in 1,100 veh/h/in 1,320 veh/h/in 1,210 veh/h/in Determine a suitable signal phasing system and phase lengths (in s) for the intersection using the Webster method. (Enter the sum of green and yellow times for…arrow_forward
- Determine the minimum of the appropriate yellow interval (Y . approach speed limit: 45 mi/h approach grade: 3.2% downgrade assumed perception-reaction time: 1.0 sec assumed deceleration rate: 11.2 ft/sec² assumed average vehicle length: 20 ft width of intersection to be crossed: 56 ft min' in s) for a signal phase under the following conditions.arrow_forwardCompute the nominal shear strength of an M10 × 7.5 of A572 Grade 60 steel (Fy = 60 ksi). For M10 × 7.5: d = 9.99 in., tw = 0.13 in., h/tw Vn = x kips = 71.arrow_forwardA flexural member is fabricated from two flange plates 1/2 × 71/2 and a web plate 3/8 × 20. The yield stress of the steel is 50 ksi. a. Compute the plastic section modulus Z and the plastic moment Mp with respect to the major principal axis. (Express your answers to three significant figures.) Z = Mp = in. 3 ft-kips b. Compute the elastic section modulus S and the yield moment My with respect to the major principal axis. (Express your answers to three significant figures.) S = My = in.3 ft-kipsarrow_forward
- The beam shown in the figure below has lateral support at the ends only. The concentrated loads are live loads. Use A992 steel and select a shape. Do not check deflections. Use C = 1.0 (this is conservative). Suppose that PL = 20 k. PL PL Use the table below. Shape Mn Mn Vn Vn Ω Ων W12 × 58 216 144 132 87.8 W12 × 65 269 179 142 94.4 W12 × 72 308 205 159 106 W14 × 61 235 157 156 104 W14 × 68 280 187 174 116 W14 × 74 318 212 192 128 W16 × 67 276 184 193 129 18' a. Use LRFD. Calculate the factored-load moment (not including the beam weight). (Express your answer to three significant figures.) Mu = ft-kips Select a shape. -Select- b. Use ASD. Calculate the required flexural strength (not including the beam weight). (Express your answer to three significant figures.) Ma = Select a shape. -Select- ft-kipsarrow_forwardGiven a portion of a pipe network below. Determine the true discharge in each pipe using the Hardy-Cross method. Use the Darcy-Weisbach formula with f = 0.02 for all pipes.arrow_forwardFor the cantilever retaining wall shown in the figure below, let the following data be given: Wall dimensions: H = 6.5 m, x1 = 0.3 m, x2 = 0.6 m, x3 = 0.8 m, x4 =2m, x5 = 0.8 m, D= 1.5 m, a = 0° Soil properties: 1 = 17.58 kN/m³, 1 = 36°, Y2 = 19.65 kN/m³, 215°, c230 kN/m² For 2=15°: Ne 10.98; N₁ = 3.94; N₁ = = 2.65. H Calculate the factor of safety with respect to overturning, sliding, and bearing capacity. Use Y concrete = 24.58 kN/m³. Also, use k₁ = k₂ = 2/3 and Pp FS (sliding) (EV) tan(k102) + Bk2c₂ + Pp Pa cos a (Enter your answers to three significant figures.) = 0 in equation FS (overturning)= FS(sliding)= FS(bearing)arrow_forward
- A W16×67 of A992 steel has two holes in each flange for 7/8-inch-diameter bolts. For A992 steel: Fy = 50 ksi, F₁ = 65 ksi. For a W16×67: bƒ = 10.2 in., tf = 0.665 in., Zx =130 in.3 and S = 117 in.3 a. Assuming continuous lateral support, verify that the holes must be accounted for and determine the nominal flexural strength. (Express your answer to three significant figures.) Mn = ft-kips b. What is the percent reduction in strength? (Express your answer to three significant figures.) % Reduction =arrow_forwardA gravity retaining wall is shown in the figure below. Calculate the factor of safety with respect to overturning and sliding, given the following data: Wall dimensions: H = 6 m, x1 = 0.6 m, x2 = 2 m, x3 = 2m, x4 = 0.5 m, x5 = 0.75 m, x6 = 0.8 m, D= 1.5 m Soil properties: 1 = 17.5 kN/m³, ø₁ = 32°, 12 = 18 kN/m³, =22°, 40 kN/m² Y₁ H D x2 x3 x5 X6 Use the Rankine active earth pressure in your calculation. Use Yconcrete = 23.58 kN/m³. Also, use k₁ = k₂ = 2/3 and P₁ = 0 in the equation FS S(sliding) | tan(k102) + Bk₂c½ + Pp (Σν). Pa cos a (Enter your answers to three significant figures.) FS (overturning) FS (sliding)arrow_forwardQ4 Use b member Castigliano's second theorem to determine the structure shown Forces In figure below longer than + In IF required. For all members member EC IS 10mm E = 200 KN/mm² 200KN YE FV 100 KN A = 1800 mm² and 2 2m 3m B D 3m 8M *arrow_forward
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