EP STATISTICS F/BUS.+ECON.-ACCESS 18 WK
13th Edition
ISBN: 9780135960912
Author: MCCLAVE
Publisher: PEARSON CO
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Textbook Question
Chapter 15.2, Problem 15.1LM
Under what circumstances is the sign test preferred to the t-test for making inferences about the
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Compute the relative risk of falling for the two groups (did not stop walking vs. did stop). State/interpret your result verbally.
Microsoft Excel include formulas
Question 1
The data shown in Table 1 are and R values for 24 samples of size n = 5 taken from a process producing
bearings. The measurements are made on the inside diameter of the bearing, with only the last three decimals
recorded (i.e., 34.5 should be 0.50345).
Table 1: Bearing Diameter Data
Sample Number
I
R
Sample Number
I R
1
34.5
3
13
35.4
8
2
34.2
4
14
34.0
6
3
31.6
4
15
37.1
5
4
31.5
4
16
34.9
7
5
35.0
5
17
33.5
4
6
34.1
6
18
31.7
3
7
32.6
4
19
34.0
8
8
33.8
3
20
35.1
9
34.8
7
21
33.7
2
10
33.6
8
22
32.8
1
11
31.9
3
23
33.5
3
12
38.6 9
24
34.2
2
(a) Set up and R charts on this process. Does the process seem to be in statistical control? If necessary,
revise the trial control limits. [15 pts]
(b) If specifications on this diameter are 0.5030±0.0010, find the percentage of nonconforming bearings pro-
duced by this process. Assume that diameter is normally distributed. [10 pts]
1
Chapter 15 Solutions
EP STATISTICS F/BUS.+ECON.-ACCESS 18 WK
Ch. 15.2 - Under what circumstances is the sign test...Ch. 15.2 - What is the probability that a randomly selected...Ch. 15.2 - Use Table I of Appendix D to calculate the...Ch. 15.2 - Consider the following sample of 10 measurements....Ch. 15.2 - Suppose you wish to conduct a test of the research...Ch. 15.2 - Accidents at construction sites. Refer to the...Ch. 15.2 - Salaries of experienced MBA graduates. According...Ch. 15.2 - Caffeine in Starbucks coffee. Researchers at the...Ch. 15.2 - Short-sale stock returns. The Securities and...Ch. 15.2 - Lobster trap placement. Refer to the Bulletin of...
Ch. 15.2 - Repair and replacement costs of water pipes. Refer...Ch. 15.2 - Performance of stock screeners. Refer to Exercise...Ch. 15.2 - Radon exposure in Egyptian tombs. Refer to the...Ch. 15.2 - Prob. 15.14ACICh. 15.3 - Prob. 15.15LMCh. 15.3 - Specify the test statistic and the rejection...Ch. 15.3 - Prob. 15.17LMCh. 15.3 - Prob. 15.18LMCh. 15.3 - Prob. 15.19ACBCh. 15.3 - Prob. 15.21ACBCh. 15.3 - Prob. 15.22ACBCh. 15.3 - The X-Factor in golf performance. Many golf...Ch. 15.3 - Prob. 15.24ACICh. 15.3 - Prob. 15.25ACICh. 15.3 - Prob. 15.26ACICh. 15.3 - Does rudeness really matter in the workplace?...Ch. 15.3 - Prob. 15.28ACICh. 15.4 - Prob. 15.29LMCh. 15.4 - Prob. 15.30LMCh. 15.4 - Prob. 15.31LMCh. 15.4 - Prob. 15.32LMCh. 15.4 - Twinned drill holes. Refer to the Exploration and...Ch. 15.4 - Prob. 15.34ACBCh. 15.4 - Prob. 15.35ACBCh. 15.4 - Prob. 15.36ACBCh. 15.4 - Prob. 15.37ACBCh. 15.4 - Prob. 15.38ACICh. 15.4 - Prob. 15.39ACICh. 15.4 - Prob. 15.40ACICh. 15.4 - Prob. 15.41ACICh. 15.4 - Prob. 15.42ACICh. 15.5 - Under what circumstances does the 2 distribution...Ch. 15.5 - Data were collected from three populations, A, B....Ch. 15.5 - Prob. 15.45LMCh. 15.5 - Prob. 15.46ACBCh. 15.5 - Prob. 15.47ACBCh. 15.5 - Prob. 15.48ACBCh. 15.5 - Prob. 15.49ACBCh. 15.5 - Prob. 15.50ACICh. 15.5 - Public defenders salaries. Random samples of seven...Ch. 15.5 - Prob. 15.52ACICh. 15.5 - Prob. 15.53ACICh. 15.6 - Prob. 15.54LMCh. 15.6 - Prob. 15.55LMCh. 15.6 - Prob. 15.56LMCh. 15.6 - Prob. 15.57ACBCh. 15.6 - Condit ions impeding farm production. A review of...Ch. 15.6 - Peer mentor training at a firm. Refer to the...Ch. 15.6 - Prob. 15.60ACBCh. 15.6 - Prob. 15.61ACICh. 15.6 - Prob. 15.62ACICh. 15.6 - Prob. 15.63ACICh. 15.6 - Prob. 15.64ACICh. 15.6 - Prob. 15.65ACICh. 15.7 - Prob. 15.66LMCh. 15.7 - Prob. 15.67LMCh. 15.7 - The following sample data were collected on...Ch. 15.7 - Compute Spearman s rank correlation coefficient...Ch. 15.7 - Charisma of top-level leaders. Refer to the...Ch. 15.7 - Prob. 15.71ACBCh. 15.7 - Prob. 15.72ACBCh. 15.7 - Prob. 15.73ACBCh. 15.7 - Prob. 15.74ACICh. 15.7 - Prob. 15.75ACICh. 15.7 - Prob. 15.76ACICh. 15.7 - Prob. 15.77ACICh. 15.7 - Sweetness of orange juice Refer to the orange...Ch. 15.7 - Americas most reputable companies. Forbes magazine...Ch. 15 - The data for three independent random samples are...Ch. 15 - Prob. 15.81LMCh. 15 - Two independent random samples produced the...Ch. 15 - Prob. 15.83LMCh. 15 - Prob. 15.84ACBCh. 15 - Prob. 15.85ACBCh. 15 - Office rental growth rates Real estate market...Ch. 15 - RIF plan to fire older employees. Reducing the...Ch. 15 - Prob. 15.88ACBCh. 15 - Wine-tasting experiment. Two expert wine tasters...Ch. 15 - Employee suggestion system. An employee suggestion...Ch. 15 - Prob. 15.91ACICh. 15 - Prob. 15.92ACICh. 15 - Prob. 15.93ACICh. 15 - Prob. 15.94ACICh. 15 - Cooling method for gas turbines. Refer to the...Ch. 15 - Flexible working hours program. A job-scheduling...Ch. 15 - Fluoride in drinking water. Many water treatment...Ch. 15 - Does fatigue lead to more defectives? A...Ch. 15 - Prob. 15.99ACICh. 15 - Prob. 15.100ACICh. 15 - Prob. 15.101ACICh. 15 - Groundwater contamination of wells. Methyl...
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- 4. (5 pts) Conduct a chi-square contingency test (test of independence) to assess whether there is an association between the behavior of the elderly person (did not stop to talk, did stop to talk) and their likelihood of falling. Below, please state your null and alternative hypotheses, calculate your expected values and write them in the table, compute the test statistic, test the null by comparing your test statistic to the critical value in Table A (p. 713-714) of your textbook and/or estimating the P-value, and provide your conclusions in written form. Make sure to show your work. Did not stop walking to talk Stopped walking to talk Suffered a fall 12 11 Totals 23 Did not suffer a fall | 2 Totals 35 37 14 46 60 Tarrow_forwardQuestion 2 Parts manufactured by an injection molding process are subjected to a compressive strength test. Twenty samples of five parts each are collected, and the compressive strengths (in psi) are shown in Table 2. Table 2: Strength Data for Question 2 Sample Number x1 x2 23 x4 x5 R 1 83.0 2 88.6 78.3 78.8 3 85.7 75.8 84.3 81.2 78.7 75.7 77.0 71.0 84.2 81.0 79.1 7.3 80.2 17.6 75.2 80.4 10.4 4 80.8 74.4 82.5 74.1 75.7 77.5 8.4 5 83.4 78.4 82.6 78.2 78.9 80.3 5.2 File Preview 6 75.3 79.9 87.3 89.7 81.8 82.8 14.5 7 74.5 78.0 80.8 73.4 79.7 77.3 7.4 8 79.2 84.4 81.5 86.0 74.5 81.1 11.4 9 80.5 86.2 76.2 64.1 80.2 81.4 9.9 10 75.7 75.2 71.1 82.1 74.3 75.7 10.9 11 80.0 81.5 78.4 73.8 78.1 78.4 7.7 12 80.6 81.8 79.3 73.8 81.7 79.4 8.0 13 82.7 81.3 79.1 82.0 79.5 80.9 3.6 14 79.2 74.9 78.6 77.7 75.3 77.1 4.3 15 85.5 82.1 82.8 73.4 71.7 79.1 13.8 16 78.8 79.6 80.2 79.1 80.8 79.7 2.0 17 82.1 78.2 18 84.5 76.9 75.5 83.5 81.2 19 79.0 77.8 20 84.5 73.1 78.2 82.1 79.2 81.1 7.6 81.2 84.4 81.6 80.8…arrow_forwardName: Lab Time: Quiz 7 & 8 (Take Home) - due Wednesday, Feb. 26 Contingency Analysis (Ch. 9) In lab 5, part 3, you will create a mosaic plot and conducted a chi-square contingency test to evaluate whether elderly patients who did not stop walking to talk (vs. those who did stop) were more likely to suffer a fall in the next six months. I have tabulated the data below. Answer the questions below. Please show your calculations on this or a separate sheet. Did not stop walking to talk Stopped walking to talk Totals Suffered a fall Did not suffer a fall Totals 12 11 23 2 35 37 14 14 46 60 Quiz 7: 1. (2 pts) Compute the odds of falling for each group. Compute the odds ratio for those who did not stop walking vs. those who did stop walking. Interpret your result verbally.arrow_forward
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