Calculus: Early Transcendentals
3rd Edition
ISBN: 9781464114885
Author: Jon Rogawski, Colin Adams
Publisher: W. H. Freeman
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Chapter 15.1, Problem 49E
To determine
To prove: Using Fubini's Theorem, the mathematical proof of the statement stating that the solid shown in figure has volume AL, where A is the area of the front face of the solid.
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Total marks 15
4.
:
Let f R2 R be defined by
f(x1, x2) = 2x²- 8x1x2+4x+2.
Find all local minima of f on R².
[10 Marks]
(ii) Give an example of a function f R2 R which is neither
bounded below nor bounded above, and has no critical point. Justify
briefly your answer.
[5 Marks]
4.
Let F RNR be a mapping.
(i)
x ЄRN ?
(ii)
:
What does it mean to say that F is differentiable at a point
[1 Mark]
In Theorem 5.4 in the Lecture Notes we proved that if F
is differentiable at a point x E RN then F is continuous at x.
Proof. Let (n) CRN be a sequence such that xn → x ЄERN as n → ∞. We
want to show that F(xn) F(x), which means F is continuous at x.
Denote hnxn - x, so that ||hn|| 0. Thus we find
||F(xn) − F(x)|| = ||F(x + hn) − F(x)|| * ||DF (x)hn + R(hn) ||
(**)
||DF(x)hn||+||R(hn)||| → 0,
because the linear mapping DF(x) is continuous and for all large nЄ N,
(***) ||R(hn) ||
||R(hn) || ≤
→ 0.
||hn||
(a)
Explain in details why ||hn|| → 0.
[3 Marks]
(b)
Explain the steps labelled (*), (**), (***).
[6 Marks]
4.
In Theorem 5.4 in the Lecture Notes we proved that if F: RN → Rm
is differentiable at x = RN then F is continuous at x.
Proof. Let (xn) CRN be a sequence such that x → x Є RN as n → ∞. We want
F(x), which means F is continuous at x.
to show that F(xn)
Denote hn
xnx, so that ||hn||| 0. Thus we find
||F (xn) − F(x) || (*) ||F(x + hn) − F(x)|| = ||DF(x)hn + R(hn)||
(**)
||DF(x)hn|| + ||R(hn) || → 0,
because the linear mapping DF(x) is continuous and for all large n = N,
|||R(hn) || ≤
(***) ||R(hn)||
||hn||
→ 0.
Explain the steps labelled (*), (**), (***)
[6 Marks]
(ii)
Give an example of a function F: RR such that F is contin-
Total marks 10
uous at x=0 but F is not differentiable at at x = 0.
[4 Marks]
Chapter 15 Solutions
Calculus: Early Transcendentals
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