Bundle: Introductory Chemistry: An Active Learning Approach, 6th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card
6th Edition
ISBN: 9781305717428
Author: Mark S. Cracolice, Ed Peters
Publisher: Cengage Learning
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Question
Chapter 15, Problem 96E
Interpretation Introduction
Interpretation:
The amount of heat required to raise the temperature of solid chromium from
Concept introduction:
The amount of energy required to change the state of a substance is known as enthalpy. It is the different in the energy of final and initial state of a substance. The negative and positive sign of enthalpy indicates the energy released and energy absorbed, respectively, during the phase change.
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Given these reactions, where X represents a generic metal or metalloid
1) H, (g) + ¿0,(g) –→ H,O(g)
AH = -241.8 kJ
2) X(s) + 2 Cl,(g)
> XCl,(s)
ΔΗ
+153.9 kJ
3) H,(g) + ¿Cl, (g) → HCI(g)
AH3 = -92.3 kJ
4) X(s) + O2(g) -
XO,(s)
AH4 = -520.3 kJ
5) Н, О(@) — Н,о)
AH5 = -44.0 kJ
what is the enthalpy, AH, for this reaction?
XCI, (s) + 2 H,O(1) -
· XO,(s) + 4 HCI(g)
-995
ΔΗ-
kJ
Incorrect
The following reaction is endothermic.
KCIO4(s) K(s) + 1/2 Cl₂(g) + 2 0₂(g) ΔΗ(1) = 433 kJ
Calculate the enthalpy change for the reaction of the elements to form one mole of KCIO4(s).
ΔΗ(2) =
K(s) + 1/2 Cl₂(g) + 2 O₂(g)→→KCIO4(s)
KJ
Consider the following reactions:
C2H6 (g) + 7/2 O2 (g) → 2 CO2 (g) + 3 H2O (l) ΔHo = − 1541 kJ
H2 (g) + ½ O2 (g) → H2O (l) ΔHo = − 286 kJ
C (s) + O2 (g) → CO2 (g) ΔHo = − 393 kJ
The enthalpy change, ΔHo, for 2 C (s) + 3 H2 (g) → C2H6 (g) is:
A.
−1541 kJ
B.
469 kJ
C.
862 kJ
D.
−103 kJ
E.
none of the above
Chapter 15 Solutions
Bundle: Introductory Chemistry: An Active Learning Approach, 6th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card
Ch. 15 - Prob. 1ECh. 15 - Prob. 2ECh. 15 - Prob. 3ECh. 15 - Prob. 4ECh. 15 - Prob. 5ECh. 15 - Prob. 6ECh. 15 - Prob. 7ECh. 15 - Prob. 8ECh. 15 - Prob. 9ECh. 15 - Prob. 10E
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