EP CHEMISTRY:CENTRAL SCI.-MOD.MASTERING
EP CHEMISTRY:CENTRAL SCI.-MOD.MASTERING
14th Edition
ISBN: 9780137453535
Author: Brown
Publisher: SAVVAS L
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Chapter 15, Problem 92AE

Consider the hypothetical reaction A(g) + 2B(g) ⇌ 2 C(g), for which Kc = 0.25 at a centain temperature. A 1.00-L reaction vessel is loaded with 1.00 mol of compound C, which is allowed to reach equilibrium. Let the variable x represent the number of mol/L of compound A present at equilibrium.
a. In terms of x, what are the equilibrium concentrations of compounds B and C?
b. What limits must be placed on the value of x so that all concentrations are positive?
c. By putting the equilibrium concentrations (in terms of x ) into the equilibrium- constant expression, derive an equation that can be solved for x.
d. The equation from part(c ) is a cubic equation (one that has the form ax3 + bx2 + cx + d =0). In general, cubic equations cannot be solved in closed form. However, you can estimate the solution by plotting the cubic equation in the allowed range of x that you specified in part (b). The point at which the cubic equation crosses the x-axis is the solution.
e. From the plot in part (d), estimate the equilibrium concentrations of A, B, and C. (Hint : You can check the accuracy of your answer by substituting these concentrations into the equilibrium expression.)

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need help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).   Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%.   Part B - Compare difference in free energy to the thermal…
Please correct answer and don't used hand raiting
need help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).   Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%.   Part B - Compare difference in free energy to the thermal energy Divide the…

Chapter 15 Solutions

EP CHEMISTRY:CENTRAL SCI.-MOD.MASTERING

Ch. 15.4 - Practice Exercise 1 If 8.0 g of NH4HS(s)...Ch. 15.4 - Prob. 15.6.2PECh. 15.5 - Practice Exercise 1 A mixture of gaseous sulfur...Ch. 15.5 - Prob. 15.7.2PECh. 15.5 - Practice Exercise 1 In Section 15.1, we discussed...Ch. 15.5 - Practice Exercise 2 The gaseous compound BrCl...Ch. 15.6 - Prob. 15.9.1PECh. 15.6 - Practice Exercise 2 At 1000 k, the value of Kp for...Ch. 15.6 - Prob. 15.10.1PECh. 15.6 - Prob. 15.10.2PECh. 15.6 - Practice Exercise 1 For the equilibrium Br2(g) +...Ch. 15.6 - Prob. 15.11.2PECh. 15.7 - Practice Exercise 1 For the reaction 4 NH3(g) + 5...Ch. 15.7 - Prob. 15.12.2PECh. 15 - Prob. 1DECh. 15 - Based on the following energy profile, predict...Ch. 15 - 15.2 The following diagrams represent a...Ch. 15 - Prob. 3ECh. 15 - Prob. 4ECh. 15 - Prob. 5ECh. 15 - 15.6 Ethene (C2H4) reacts with healogens (X2) by...Ch. 15 - When lead(IV) oxide is heated above 300 O C, it...Ch. 15 - Prob. 8ECh. 15 - The reactin A2(g) + B(g) + A(g) + AB(g) has an...Ch. 15 - Prob. 10ECh. 15 - Prob. 11ECh. 15 - The following graph represents the yield of the...Ch. 15 - Suppose that the gas-phase reactions A B and B A...Ch. 15 - Prob. 14ECh. 15 - Prob. 15ECh. 15 - Write the expression for KC for the following...Ch. 15 - When the following reaction come to equilibrium,...Ch. 15 - Prob. 18ECh. 15 - Prob. 19ECh. 15 - Prob. 20ECh. 15 - If Kc = 0.042 for PC13(g) + C12 (g) PC15 (g) at...Ch. 15 - Prob. 22ECh. 15 - 15.23 The equilibrium constant for the...Ch. 15 - Prob. 24ECh. 15 - Prob. 25ECh. 15 - Prob. 26ECh. 15 - The following equilibria were attained at 823 K:...Ch. 15 - Consider the equilibrium N2(g) + O2(g) + Br2(g) 2...Ch. 15 - Mercury(I) oxide decomposes into elemental mercury...Ch. 15 - Prob. 30ECh. 15 - Prob. 31ECh. 15 - Prob. 32ECh. 15 - Prob. 33ECh. 15 - Phosphorus trichloride gas and chlorine gas react...Ch. 15 - A mixture of 0.10 mol of NO, 0.050 mol of H2, and...Ch. 15 - Prob. 36ECh. 15 - A mixture of 0.2000 mol of CO2, 0.1000 mol of H2,...Ch. 15 - 15.38 A flask is charged with 1.500 atm of N2O4(g)...Ch. 15 - Prob. 39ECh. 15 - Prob. 40ECh. 15 - a. If QC KC, in which direction will a reaction...Ch. 15 - Prob. 42ECh. 15 - At 100 OC , the equilibrium constant for the...Ch. 15 - 15.44 As shown in Table 15.2, KP for the...Ch. 15 - At 100 C, K = 0.078 for the reaction SO2Cl2 (g) ...Ch. 15 - Prob. 46ECh. 15 - Prob. 47ECh. 15 - Prob. 48ECh. 15 - At 800 k, the equilibrium constant for I2 (g) ...Ch. 15 - Prob. 50ECh. 15 - At 2000 OC, the equilibrium constant for the...Ch. 15 - For the equilibrium Br2 (g) + Cl2 (g) 2BrCl(g) At...Ch. 15 - At 373 k, Kp = 0.416 for the equilibrium 2NOBr (g)...Ch. 15 - At 218 oC, KC= 1.2 X 10-4 for the equilibrium NH4...Ch. 15 - Prob. 55ECh. 15 - At 80 oC, K =1.87 X 10-3 for the reaction PH3 BCl3...Ch. 15 - Prob. 57ECh. 15 - Prob. 58ECh. 15 - Prob. 59ECh. 15 - Prob. 60ECh. 15 - Consider the following equilibrium for which H<0...Ch. 15 - Prob. 62ECh. 15 - 15.63 How do the following changes affect the...Ch. 15 - Prob. 64ECh. 15 - Consider the following equilibrium between oxides...Ch. 15 - Prob. 66ECh. 15 - Ozone, O3, decomposes to molecular oxygen in the...Ch. 15 - Prob. 68ECh. 15 - Prob. 69ECh. 15 - 15.70 True or false: When the temperature of an...Ch. 15 - Prob. 71AECh. 15 - Prob. 72AECh. 15 - 15.73 A mixture of CH4 and H2O is passed over a...Ch. 15 - Prob. 74AECh. 15 - Prob. 75AECh. 15 - Prob. 76AECh. 15 - Prob. 77AECh. 15 - Prob. 78AECh. 15 - Prob. 79AECh. 15 - For the equilibrium PH3BCI3 (s) PH3 (g) + BCI3...Ch. 15 - Prob. 81AECh. 15 - Prob. 82AECh. 15 - Prob. 83AECh. 15 - At 900 o C, Kc = 0.0108 for the reaction CaCO3(g) ...Ch. 15 - Prob. 85AECh. 15 - The equilibrium constant Kc for C(s) +CO2 2CO(g)...Ch. 15 - Prob. 87AECh. 15 - Le Chatelier noted that many industrial processes...Ch. 15 - Prob. 89AECh. 15 - Prob. 90AECh. 15 - [15.91] An equilibrium mixture of H2, I2, and HI...Ch. 15 - Consider the hypothetical reaction A(g) + 2B(g) 2...Ch. 15 - Prob. 93AECh. 15 - Prob. 94AECh. 15 - Prob. 95IECh. 15 - The following equilibria were measured at 823 K:...Ch. 15 - Prob. 97IECh. 15 - Prob. 98IECh. 15 - At 800 K, the equilibrium constant for the...Ch. 15 - Prob. 100IECh. 15 - Prob. 101IECh. 15 - Prob. 102IE
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