Chapter 15, Problem 89P

The spring is not stretched or compressed when “s=0.8m" and the 11 kg block which is subjected to a force of 105 N has a speed of 5.5 m/s down the smooth plane. Using "THE PRINCIPLE OF WORK AND ENERGY", find the distance "s" when the block STOPS. k = 200 N/m 5 m/s F = 100 N 30°

The weight of the spring held follower AB is 0.381 kg and moves back and forth as its end rolls on the contoured surface of the cam, where r = 0.2 ft and z = (0.1sin20) ft. If the cam is rotating at a constant rate of 6 rad/s, determine the force, in Ib, at the end A of the follower where e = 45°. In this position, the spring is compressed 0.4 ft. Neglect friction at the bearing C. Round your answer to 3 decimal places. z = 0.1 sin 20 0.2 ft e = 6 rad/s A k = 12 lb/ft

400 mm The spring attached to the mass of m = 0. 5 kg sliding collar has a stiffness of k = 0.21 kN/m and a free length of 150 mm. If the speed of the collar in position A is 4 m/s to the right, determine the total energy and the speed of the collar in position B, Neglecet 100 mm friction. 200

The box with a weight of 6 lb slides down the smooth surface that has a circular portion AB. If the speed of the box is 8 ft/sec at A, calculate the magnitude of the normal force acting on the box at C. Present your answer in lb using 3 significant figures. The following relations may be useful: sin(A + B)=sin A c ·cos B±cos A-sin B cos(A + B) = cos A cos B sin A-sin B 45° B 0=30° 20 ft 8 ft/s A 45°

M = A frisbee is thrown such that its final angular velocity is w = 9 after being in flight for t = 2 s. As it rad S flies, the wind applies a constant moment, causing the frisbee to rotate faster. If the frisbee was initially at rest, determine the moment of the wind and the work done by said moment. Assume the frisbee can be modelled as a disk with mass m = = 0.15 kg and that it rotates about its center of gravity G. The frisbee has a radius of r = 0.12 m. UM = N.m r J G M

The sports car, having a mass of 1700 kg, travels horizontally along a 20° banked track which is circular and has a radius of curvature of p = 100 m. Determine the normal force of the car in Newton.

The weight of the spring held follower AB is 0.375 kg and moves back and forth as its end rolls on the contoured surface of the cam, where r = 0.2 ft and z = (0.1sin20) ft. If the cam is rotating at a constant rate of 6 rad/s, determine the force, in Ib, at the end A of the follower where 0 = 45°. In this position, the spring is compressed 0.4 ft. Neglect friction at the bearing C. Round your answer to 3 decimal places. z = 0.1 sin 20 C 0.2 ft B 6 = 6 rad/s k = 12 lb/ft

When the 10 lbm box reaches point F it has a speed vF=3o ft/s. Determine the normal force the box exerts on the surface when it reaches point M. Neglect friction and the size of the box

The 0.36-Mg car travels over the hill having the shape of a parabola. When the car is at point A, it is traveling at 25.06 m/s and increasing its speed at 499 mva? Deformine the resultant normal force (kN) at this instant. Neglect the size of the car. 20 (1) 60 m Seve A 6400