
General Chemistry: Principles and Modern Applications (11th Edition)
11th Edition
ISBN: 9780132931281
Author: Ralph H. Petrucci, F. Geoffrey Herring, Jeffry D. Madura, Carey Bissonnette
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Question
Chapter 15, Problem 85IAE
Interpretation Introduction
Interpretation:
Mole fraction of NO2 in the mixture of NO2 and N2O4 should be determined
Concept introduction:
Equilibrium constant is the ratio between the concentrations of products and reactants of a reversible reaction. Concentrations are raised to the power of coefficient in the balanced equation.
Expert Solution & Answer

Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
6. The equilibrium constant for the reaction
2 HBr (g)
→ H2(g) + Br2(g)
Can be expressed by the empirical formula
11790 K
In K-6.375 + 0.6415 In(T K-¹)
-
T
Use this formula to determine A,H as a function of temperature. Calculate A,-H at 25 °C and at
100 °C.
3. Nitrosyl chloride, NOCI, decomposes according to
2 NOCI (g) → 2 NO(g)
+ Cl2(g)
Assuming that we start with no moles of NOCl (g) and no NO(g) or Cl2(g), derive an expression
for Kp in terms of the equilibrium value of the extent of reaction, Seq, and the pressure, P.
Given that K₂ = 2.00 × 10-4, calculate Seq/
of
29/no when P = 0.080 bar. What is the new value
по
ƒª/ at equilibrium when P = 0.160 bar? Is this result in accord with Le Châtelier's
Principle?
Consider the following chemical equilibrium:
2SO2(g) + O2(g) = 2SO3(g)
•
Write the equilibrium constant expression for this reaction.
Now compare it to the equilibrium constant expression for the related reaction:
•
.
1
SO2(g) + O2(g) = SO3(g)
2
How do these two equilibrium expressions differ?
What important principle about the dependence of equilibrium constants on the stoichiometry of a
reaction can you learn from this comparison?
Chapter 15 Solutions
General Chemistry: Principles and Modern Applications (11th Edition)
Ch. 15 - Based on these descriptions, write a balanced...Ch. 15 - Based on these descriptions, write a balanced...Ch. 15 - Write equilibrium constant expressions, Kg , for...Ch. 15 - Write equilibrium constant expressions, Kg for the...Ch. 15 - Write an equilibrium constant, Kg1 for the...Ch. 15 - Write an equilibrium constant Kg for the formation...Ch. 15 - Determine values of Ks from the Kg values given....Ch. 15 - Determine the values of Kg from the Kg values...Ch. 15 - The vapor pressure of water at 25C is 238 mmHg....Ch. 15 - If Kg=5.12102 for the equilibrium established...
Ch. 15 - Determine Kz for the reaction...Ch. 15 - Given the equilibrium constant values...Ch. 15 - Use the following data to estimate a value of Kg...Ch. 15 - Determine Kg for the reaction...Ch. 15 - An important environmental and physiological...Ch. 15 - Rust Fe2O2(s) , is caused by the oxidation of iron...Ch. 15 - 1.00102 mol PCl3 is introduced into a 250.0 mL...Ch. 15 - A mixture of 1.00gH2 and 1.06gH2S in a 0.500 L...Ch. 15 - The two common chlorides of phosphorus, PCl2 and...Ch. 15 - A 0.682 g sample of ICI(g) is placed in a 625 mL...Ch. 15 - Write the equilibrium constant expression for the...Ch. 15 - Write the equilibrium constant expression for the...Ch. 15 - Equilibrium is established at 1000 K, where Ke=281...Ch. 15 - For the dissociation o l2(g)t about...Ch. 15 - In the Ostwald process for oxidizing ammonia, a...Ch. 15 - At 2000K, Kx=0.154 for the reaction...Ch. 15 - An equilibrium mixture at 1000 K contains 0.276...Ch. 15 - For the reaction CO(g)+H2O(g)CO2(g)+H2(g),Kc=23.2...Ch. 15 - Can a mixture of 2.2 mol O2 , 3.6 mol SO2 , and...Ch. 15 - Is a mixture of 0.0205 mol NO2(g) and...Ch. 15 - In the reaction 2SO2(g)+O2(g)2SO2(g) , 0.455 mol...Ch. 15 - In the reaction CO(g)+H2O(g)CO2(g)+H2(g),Kc=31.4...Ch. 15 - A mixture consisting of 0.150molH2 and 0.150moll2...Ch. 15 - Stating with 0.280 mol Sbcl2 and 0.160mol Cl2 ,...Ch. 15 - Starting with 0.3500 mo CO(g) and 0.05500 mol...Ch. 15 - g each of CO, H2O , and H2 are sealed in a 1.41L...Ch. 15 - Eqilibrium is established in a 2.50 L flask at...Ch. 15 - For the following reaction, Kg=2.00 at 100C ....Ch. 15 - The substances involved in the following in the...Ch. 15 - The N2O4-NO2 equilibrium mixture in the flask on...Ch. 15 - Formamide, used in the manufacture of...Ch. 15 - A mixture of 1.00 mol NaHCO2 (s) and 1.00 mol...Ch. 15 - Cadmium metal is added to 0.350 L of an aqueous...Ch. 15 - Lead metal is added to 0.100 M Cr2+(aq) . What are...Ch. 15 - One sketch below represents an initial...Ch. 15 - One sketch below represents an initial...Ch. 15 - One important reaction in the citric acid cycle is...Ch. 15 - The following reaction is an important reaction in...Ch. 15 - Refer to Example 15-2 H2S(g) at 747.6 mmHg...Ch. 15 - A sample of NH4HS(s) is placed in a 2.58L flask...Ch. 15 - The following reaction is used self-contained...Ch. 15 - Prob. 52ECh. 15 - Exactly 1.00 mol each of CO and Cl2 are introduced...Ch. 15 - For the reaction 2NO2(g)2NO(g)+O2(g),Kg=1.8108 at...Ch. 15 - Continuous removal of one of the products of a...Ch. 15 - We can represent the freezing of H2O(l) at 0C as...Ch. 15 - Explain how each of the following affects the...Ch. 15 - In the gas phase, iodine reacts with cyclopentene...Ch. 15 - The reaction N2(g)+O2(g)2NO(g),rH=+181kJmol-1 ,...Ch. 15 - Use data from Appendix D to determine whether the...Ch. 15 - If the volume of an equilibrium mixture of...Ch. 15 - For the reaction A(s)B(s)+2C(g)+12D(g)tH=0 Will Kc...Ch. 15 - What effect does increasing the volume of the...Ch. 15 - For which of the following reaction would you...Ch. 15 - The following reaction represents the binding of...Ch. 15 - In human body, the enzyme carbon anahydrase...Ch. 15 - A crystal of dinitrogen tetroxide (melting point,...Ch. 15 - When hydrogen iodide is heated, the degree...Ch. 15 - The standard enthalpy of reaction lot the...Ch. 15 - Would you expect at the amount of N2 to increase,...Ch. 15 - The equilibrium constant for the following...Ch. 15 - For the reaction C2H2(g)+3H2(g)2CH4(g) , the...Ch. 15 - The equilibrium constant for the following...Ch. 15 - The equilibrium constant for the following...Ch. 15 - Explain why the percent of molecules that...Ch. 15 - Prob. 76IAECh. 15 - Refer to Example 15-13g. Suppose that 0100 L of...Ch. 15 - In the equilibrium described in Example 15-12, the...Ch. 15 - Starting with SO2(g) at 1.00 atm, what will be the...Ch. 15 - A sample of a with a mole ratio of N2 to O2 , of...Ch. 15 - Derive, by calculation, the equilibrium amounts of...Ch. 15 - The decomposition of salicylic acid to phenol and...Ch. 15 - One of the key reaction in the gasification of...Ch. 15 - A sample of pure PCl2(g) is introduced into an...Ch. 15 - Prob. 85IAECh. 15 - Prob. 86IAECh. 15 - Show that in terms of mole fractions of gases and...Ch. 15 - For the synthesis of ammonia at 500 K,...Ch. 15 - Prob. 89IAECh. 15 - Prob. 90IAECh. 15 - Prob. 91IAECh. 15 - Concerning me reaction in Exercise 26 and the...Ch. 15 - For the reaction 2NO(g)+Cl2(g)2NOCl(g),Kz=3.7108...Ch. 15 - Prob. 94IAECh. 15 - Prob. 95IAECh. 15 - Prob. 96IAECh. 15 - Prob. 97IAECh. 15 - Prob. 98IAECh. 15 - Prob. 99FPCh. 15 - The decomposition of Hl(g) is represented by the...Ch. 15 - Prob. 101FPCh. 15 - Prob. 102FPCh. 15 - Prob. 103FPCh. 15 - Prob. 104SAECh. 15 - Prob. 105SAECh. 15 - Explain the important distinctions between each...Ch. 15 - In the reversible reaction H2(g)+l2(g)2Hl(g) , a...Ch. 15 - Equilibrium is established the reaction...Ch. 15 - The volume of the reaction vessel containing an...Ch. 15 - For the reaction 2NO2(g)=2NO(g)+O2(g),Kg=1.8108 at...Ch. 15 - For the dissociation reaction...Ch. 15 - The following data are given at...Ch. 15 - Equilibrium is established in the reversible...Ch. 15 - The Deacon process for producing chlorine gas fro,...Ch. 15 - For the reaction SO2(g)SO2(aq),K=1.25 at 25C ....Ch. 15 - In the reaction H2O2(g)H2O2(aq),K=1.0104 at 25C ....Ch. 15 - An equilibrium mixture of SO2 , SO2 , and O2 gases...Ch. 15 - Prob. 118SAE
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Given Kp for 2 reactions. Find the Kp for the following reaction: BrCl(g)+ 1/2 I2(g) ->IBr(g) + 1/2 Cl2(g)arrow_forwardFor a certain gas-phase reaction at constant pressure, the equilibrium constant Kp is observed to double when the temperature increases from 300 K to 400 K. Calculate the enthalpy change of the reaction, Ah, using this information.arrow_forwardHydrogen bonding in water plays a key role in its physical properties. Assume that the energy required to break a hydrogen bond is approximately 8 kJ/mol. Consider a simplified two-state model where a "formed" hydrogen bond is in the ground state and a "broken" bond is in the excited state. Using this model: • Calculate the fraction of broken hydrogen bonds at T = 300 K, and also at T = 273 K and T = 373 K. • At what temperature would approximately 50% of the hydrogen bonds be broken? • What does your result imply about the accuracy or limitations of the two-state model in describing hydrogen bonding in water? Finally, applying your understanding: • Would you expect it to be easier or harder to vaporize water at higher temperatures? Why? If you were to hang wet laundry outside, would it dry more quickly on a warm summer day or on a cold winter day, assuming humidity is constant?arrow_forward
- (3 pts) Use the Kapustinskii equation to calculate the lattice enthalpy for MgBr2 anddiscuss any differences between this result and that from #4.arrow_forward(3 pts) Silver metal adopts a fcc unit cell structure and has an atomic radius of 144 pm. Fromthis information, calculate the density of silver. Show all work.arrow_forward4. (3 pts) From the information below, determine the lattice enthalpy for MgBr2. Show all work. AH/(kJ mol-¹) Sublimation of Mg(s) +148 lonization of Mg(g) +2187 to Mg2+(g) Vaporization of Br₂(1) +31 Dissociation of Br,(g) +193 Electron gain by Br(g) -331 Formation of MgBr₂(s) -524arrow_forward
- 1. (4 pts-2 pts each part) Consider the crystal structures of NaCl, ZnS, and CsCl (not necessarily shown in this order). a. For one of the three compounds, justify that the unit cell is consistent with stoichiometry of the compound. b. In each of the crystal structures, the cations reside in certain holes in the anions' packing structures. For each compound, what type of holes are occupied by the cations and explain why those particular types of holes are preferred.arrow_forward(2 pts) What do you expect to happen in a Na2O crystal if a Cl− ion replaces one of the O2−ions in the lattice?arrow_forward(2 pts) WSe2 is an ionic compound semiconductor that can be made to be p-type or n-type.What must happen to the chemical composition for it to be p-type? What must happen tothe chemical composition for it to be n-type?arrow_forward
- 8. (2 pts) Silicon semiconductors have a bandgap of 1.11 eV. What is the longest photon wavelength that can promote an electron from the valence band to the conduction band in a silicon-based photovoltaic solar cell? Show all work. E = hv = hc/λ h = 6.626 x 10-34 Js c = 3.00 x 108 m/s 1 eV 1.602 x 10-19 Jarrow_forwardA solution containing 100.0 mL of 0.155 M EDTA buffered to pH 10.00 was titrated with 100.0 mL of 0.0152 M Hg(ClO4)2 in a cell: calomel electrode (saturated)//titration solution/Hg(l) Given the formation constant of Hg(EDTA)2-, logKf= 21.5, and alphaY4-=0.30, find out the cell voltage E. Hg2+(aq) + 2e- = Hg(l) E0= 0.852 V E' (calomel electrode, saturated KCl) = 0.241 Varrow_forwardFrom the following reduction potentials I2 (s) + 2e- = 2I- (aq) E0= 0.535 V I2 (aq) + 2e- = 2I- (aq) E0= 0.620 V I3- (aq) + 2e- = 3I- (aq) E0= 0.535 V a) Calculate the equilibrium constant for I2 (aq) + I- (aq) = I3- (aq). b) Calculate the equilibrium constant for I2 (s) + I- (aq) = I3- (aq). c) Calculate the solubility of I2 (s) in water.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStaxChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning

Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning

Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning

General Chemistry - Standalone book (MindTap Cour...
Chemistry
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Cengage Learning

Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning

Chemistry by OpenStax (2015-05-04)
Chemistry
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:OpenStax

Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Chemical Equilibria and Reaction Quotients; Author: Professor Dave Explains;https://www.youtube.com/watch?v=1GiZzCzmO5Q;License: Standard YouTube License, CC-BY