Chapter 15, Problem 6RQ

A design for a synchronous divide-by-six Gray counter isrequired which meets the following specification.The system has 2 inputs, PAUSE and SKIP:• While PAUSE and SKIP are not asserted (logic 0), thecounter continually loops through the Gray coded binarysequence {0002, 0012, 0112, 0102, 1102, 1112}.• If PAUSE is asserted (logic 1) when the counter is onnumber 0102, it stays here until it becomes unasserted (atwhich point it continues counting as before).• While SKIP is asserted (logic 1), the counter misses outodd numbers, i.e. it loops through the sequence {0002,0112, 1102}.The system has 4 outputs, BIT3, BIT2, BIT1, and WAITING:• BIT3, BIT2, and BIT1 are unconditional outputsrepresenting the current number, where BIT3 is the mostsignificant-bit and BIT1 is the least-significant-bit.• An active-high conditional output WAITING should beasserted (logic 1) whenever the counter is paused at 0102.(a) Draw an ASM chart for a synchronous system to providethe functionality described above.(b)…

S A B D FL I C J E G H T K L Figure 1: Search tree 1. Uninformed search algorithms (6 points) Based on the search tree in Figure 1, provide the trace to find a path from the start node S to a goal node T for the following three uninformed search algorithms. When a node has multiple successors, use the left-to-right convention. a. Depth first search (2 points) b. Breadth first search (2 points) c. Iterative deepening search (2 points)

We want to get an idea of how many tickets we have and what our issues are. Print the ticket ID number, ticket description, ticket priority, ticket status, and, if the information is available, employee first name assigned to it for our records. Include all tickets regardless of whether they have been assigned to an employee or not. Sort it alphabetically by ticket status, and then numerically by ticket ID, with the lower ticket IDs on top.