Leonhard Euler was able to find the exact sum of the series in Problem 5. In 1736 he proved that ∑ n − 1 ∞ 1 n 2 = π 2 6 In this problem we ask you to prove this fact by evaluating the double integral in Problem 5. Start by making the change of variables x = u − v 2 y = u + v 2 This gives a rotation about the origin through the angle π / 4 . You will need to sketch the corresponding region in the uv -plane. [ Hint: If, in evaluating the integral, you encounter either of the expressions (1 – sin θ )/cos θ or (cos θ )/(1 + sin θ ), you might like to use the identity cos θ = sin(( π / 2 ) − θ ) and the corresponding identity for sin θ. ]
Leonhard Euler was able to find the exact sum of the series in Problem 5. In 1736 he proved that ∑ n − 1 ∞ 1 n 2 = π 2 6 In this problem we ask you to prove this fact by evaluating the double integral in Problem 5. Start by making the change of variables x = u − v 2 y = u + v 2 This gives a rotation about the origin through the angle π / 4 . You will need to sketch the corresponding region in the uv -plane. [ Hint: If, in evaluating the integral, you encounter either of the expressions (1 – sin θ )/cos θ or (cos θ )/(1 + sin θ ), you might like to use the identity cos θ = sin(( π / 2 ) − θ ) and the corresponding identity for sin θ. ]
Solution Summary: The author evaluates the integral by using change of variables. The value of the double integral is pi26.
Leonhard Euler was able to find the exact sum of the series in Problem 5. In 1736 he proved that
∑
n
−
1
∞
1
n
2
=
π
2
6
In this problem we ask you to prove this fact by evaluating the double integral in Problem 5. Start by making the change of variables
x
=
u
−
v
2
y
=
u
+
v
2
This gives a rotation about the origin through the angle
π
/
4
. You will need to sketch the corresponding region in the uv-plane.
[Hint: If, in evaluating the integral, you encounter either of the expressions (1 – sin θ)/cos θ or (cos θ)/(1 + sin θ), you might like to use the identity cos θ = sin((
π
/
2
) − θ) and the corresponding identity for sin θ.]
Equations that give the relation between different trigonometric functions and are true for any value of the variable for the domain. There are six trigonometric functions: sine, cosine, tangent, cotangent, secant, and cosecant.
4. Use method of separation of variable to solve the following wave equation
მłu
J²u
subject to
u(0,t) =0, for t> 0,
u(л,t) = 0, for t> 0,
=
t> 0,
at²
ax²'
u(x, 0) = 0,
0.01 x,
ut(x, 0) =
Π
0.01 (π-x),
0
Solve the following heat equation by method of separation variables:
ди
=
at
subject to
u(0,t) =0, for
-16024
ძx2 •
t>0, 0 0,
ux (4,t) = 0, for
t> 0,
u(x, 0) =
(x-3,
\-1,
0 < x ≤2
2≤ x ≤ 4.
ex
5.
important aspects.
Graph f(x)=lnx. Be sure to make your graph big enough to easily read (use the space given.) Label all
6
33
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