A solution is formed by mixing 50.0 mL of 10.0 M NaX with 50.0 mL of 2.0 × 10 −3 M CuNO 3 . Assume that Cu + forms complex ions with X − as follows: Cu + ( a q ) + X − ( a q ) ⇌ C u X ( a q ) K 1 = 1.0 × 10 2 CuX ( a q ) + X − ( a q ) ⇌ C u X 2 − ( a q ) K 2 = 1.0 × 10 4 CuX 2 − ( a q ) + X − ( a q ) ⇌ C u X 3 2 − ( a q ) K 3 = 1.0 × 10 3 with an overall reaction Cu + ( a q ) + 3 X − ( a q ) ⇌ C u X 3 2 − ( a q ) K = 1.0 × 10 9 Calculate the following concentrations at equilibrium. a. Cux 3 2− b. CuX 2 − c. Cu +
A solution is formed by mixing 50.0 mL of 10.0 M NaX with 50.0 mL of 2.0 × 10 −3 M CuNO 3 . Assume that Cu + forms complex ions with X − as follows: Cu + ( a q ) + X − ( a q ) ⇌ C u X ( a q ) K 1 = 1.0 × 10 2 CuX ( a q ) + X − ( a q ) ⇌ C u X 2 − ( a q ) K 2 = 1.0 × 10 4 CuX 2 − ( a q ) + X − ( a q ) ⇌ C u X 3 2 − ( a q ) K 3 = 1.0 × 10 3 with an overall reaction Cu + ( a q ) + 3 X − ( a q ) ⇌ C u X 3 2 − ( a q ) K = 1.0 × 10 9 Calculate the following concentrations at equilibrium. a. Cux 3 2− b. CuX 2 − c. Cu +
Solution Summary: The author explains that the equilibrium constant expression is expressed by the formula, K=Concentration
A solution is formed by mixing 50.0 mL of 10.0 M NaX with 50.0 mL of 2.0 × 10−3M CuNO3. Assume that Cu+ forms complex ions with X− as follows:
Cu
+
(
a
q
)
+
X
−
(
a
q
)
⇌
C
u
X
(
a
q
)
K
1
=
1.0
×
10
2
CuX
(
a
q
)
+
X
−
(
a
q
)
⇌
C
u
X
2
−
(
a
q
)
K
2
=
1.0
×
10
4
CuX
2
−
(
a
q
)
+
X
−
(
a
q
)
⇌
C
u
X
3
2
−
(
a
q
)
K
3
=
1.0
×
10
3
with an overall reaction
Cu
+
(
a
q
)
+
3
X
−
(
a
q
)
⇌
C
u
X
3
2
−
(
a
q
)
K
=
1.0
×
10
9
Calculate the following concentrations at equilibrium.
In the electrode Pt, H2(1 atm) | H+(a=1), if the electrode balance potential is -0.118 V and the interface potential difference is +5 mV. The current voltage will be 0.005 - (-0.118) = 0.123 V ¿Correcto?
In the electrode Pt, H2(1 atm) | H+(a=1) at 298K is 0.79 mA cm-2. If the balance potential of the electrode is -0.118 V and the potential difference of the interface is +5 mV. Determine its potential.
In one electrode: Pt, H2(1 atm) | H+(a=1), the interchange current density at 298K is 0.79 mA·cm-2. If the voltage difference of the interface is +5 mV. What will be the correct intensity at pH = 2?. Maximum transfer voltage and beta = 0.5.
Biochemistry: Concepts and Connections (2nd Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning