Owlv2 With Mindtap Reader, 1 Term (6 Months) Printed Access Card For Tro's Chemistry In Focus: A Molecular View Of Our World, 7th
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Chapter 15, Problem 64E
Interpretation Introduction

Interpretation:

The given detergent molecules which are biodegradable are to be determined.

Concept Introduction:

Detergent molecules have polar and non-polar sides which help in the dissolution of non-polar molecules to the non-polar side and polar molecules to the polar sides.

The detergent molecules having straight chain can be decomposed and are biodegradable.

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Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following: (a) match structures of isomers given their mass spectra below (spectra A and spectra B) (b) Draw the fragments given the following prominent peaks from each spectrum: Spectra A m/2 =43 and 1/2-57 spectra B m/2 = 43 (c) why is 1/2=57 peak in spectrum A more intense compared to the same peak in spectrum B. Relative abundance Relative abundance 100 A 50 29 29 0 10 -0 -0 100 B 50 720 30 41 43 57 71 4-0 40 50 60 70 m/z 43 57 8-0 m/z = 86 M 90 100 71 m/z = 86 M -O 0 10 20 30 40 50 60 70 80 -88 m/z 90 100
Part IV. C6H5 CH2CH2OH is an aromatic compound which was subjected to Electron Ionization - mass spectrometry (El-MS) analysis. Prominent m/2 values: m/2 = 104 and m/2 = 9) was obtained. Draw the structures of these fragments.
For each reaction shown below follow the curved arrows to complete each equationby showing the structure of the products. Identify the acid, the base, the conjugated acid andconjugated base. Consutl the pKa table  and choose the direciton theequilibrium goes. However show the curved arrows. Please explain if possible.

Chapter 15 Solutions

Owlv2 With Mindtap Reader, 1 Term (6 Months) Printed Access Card For Tro's Chemistry In Focus: A Molecular View Of Our World, 7th

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