Owlv2 With Mindtap Reader, 1 Term (6 Months) Printed Access Card For Tro's Chemistry In Focus: A Molecular View Of Our World, 7th
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Chapter 15, Problem 1SC
Interpretation Introduction

Interpretation:

The change that will make the detergent more soluble in water is to be determined.

Concept introduction:

Detergent is a synthetic water-soluble or liquid organic formation that combines with impurities and dirt to make them more soluble. It is chemically different from soaps in not forming scum, but is able to emulsify oils, hold dirt in suspension, and act as wetting agents. Nonionic detergents are nonpolar and help the compound to be more soluble in water.

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Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following: (a) match structures of isomers given their mass spectra below (spectra A and spectra B) (b) Draw the fragments given the following prominent peaks from each spectrum: Spectra A m/2 =43 and 1/2-57 spectra B m/2 = 43 (c) why is 1/2=57 peak in spectrum A more intense compared to the same peak in spectrum B. Relative abundance Relative abundance 100 A 50 29 29 0 10 -0 -0 100 B 50 720 30 41 43 57 71 4-0 40 50 60 70 m/z 43 57 8-0 m/z = 86 M 90 100 71 m/z = 86 M -O 0 10 20 30 40 50 60 70 80 -88 m/z 90 100
Part IV. C6H5 CH2CH2OH is an aromatic compound which was subjected to Electron Ionization - mass spectrometry (El-MS) analysis. Prominent m/2 values: m/2 = 104 and m/2 = 9) was obtained. Draw the structures of these fragments.
For each reaction shown below follow the curved arrows to complete each equationby showing the structure of the products. Identify the acid, the base, the conjugated acid andconjugated base. Consutl the pKa table  and choose the direciton theequilibrium goes. However show the curved arrows. Please explain if possible.

Chapter 15 Solutions

Owlv2 With Mindtap Reader, 1 Term (6 Months) Printed Access Card For Tro's Chemistry In Focus: A Molecular View Of Our World, 7th

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