In the presence of CN − , Fe 3+ forms the complex ion Fe(CN) 6 3− . The equilibrium concentrations of Fe 3+ and Fe(CN) 6 3− are 8.5 × 10 −40 M and 1.5 × 10 −3 M , respectively, in a 0.11- M KCN solution. Calculate the value for the overall formation constant of Fe(CN) 6 3− . Fe 3+ ( a q ) + 6 CN − ( a q ) ⇌ F e ( C N ) 6 3 − ( a q ) K overall = ?
In the presence of CN − , Fe 3+ forms the complex ion Fe(CN) 6 3− . The equilibrium concentrations of Fe 3+ and Fe(CN) 6 3− are 8.5 × 10 −40 M and 1.5 × 10 −3 M , respectively, in a 0.11- M KCN solution. Calculate the value for the overall formation constant of Fe(CN) 6 3− . Fe 3+ ( a q ) + 6 CN − ( a q ) ⇌ F e ( C N ) 6 3 − ( a q ) K overall = ?
Solution Summary: The author explains the equilibrium concentration of Fe3+ in a solution.
In the presence of CN−, Fe3+ forms the complex ion Fe(CN)63−. The equilibrium concentrations of Fe3+ and Fe(CN)63− are 8.5 × 10−40M and 1.5 × 10−3M, respectively, in a 0.11-M KCN solution. Calculate the value for the overall formation constant of Fe(CN)63−.
Fe
3+
(
a
q
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+
6
CN
−
(
a
q
)
⇌
F
e
(
C
N
)
6
3
−
(
a
q
)
K
overall
=
?
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General, Organic, and Biological Chemistry - 4th edition
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell