Chapter 15, Problem 62E

Interpretation Introduction

Interpretation:

The heat of vaporization of an unknown liquid for which the amount of heat released is $\text{58}\text{.2 kJ}$ is to be stated.

Concept Introduction:

Heat of vaporization is defined as the amount of heat required to vaporize $\text{1 g}$ of substance. If “q” is the amount of heat used to vaporize and “m” is the gram of the substance, then the heat of vaporization will be equal to the $\frac{\text{q}}{\text{m}}$.