Explanation Given info: The radius of the venturi meter is half that of pipe, oil flow through unconstricted pipe is 1.9 m / s and pressure difference between unconstricted flow and venturi is 16 kPa . Consider point (2) in unconstricted pipe and point (1) in venturi and these points are at same height. Let h 1 be the height of the points. Apply Bernoulli’s equation at point (1) and (2). p 1 + 1 2 ρ v 1 2 = p 2 + 1 2 ρ v 2 2 (1) p 1 is the pressure of the water through unconstricted pipe at point (1) p 2 is the pressure of the water through the venturi at point (2) v 1 is the flow speed of the water through unconstricted pipe at point (2) v 2 is the flow speed of the water through venture at point (1) Write the continuity equation at point (1) and (2). v 1 A 1 = v 2 A 2 Here, A 1 is the area of the unconstricted pipe A 2 is the area of the venture Rearrange the above equation to get v 2 . v 2 = A 1 A 2 v 1 Substitute A 1 A 2 v 1 for v 2 in equation (1) to get ρ . p 1 + 1 2 ρ v 1 2 = p 2 + 1 2 ρ ( A 1 A 2 v 1 ) 2 ρ = 2 ( p 1 − p 2 ) v 1 2 ( A 1 2 A 2 2 − 1 ) Substitute π r 1 2 for A 1 and π r 2 2 for A 2 in the above equation and simplify the equation to get v 1

Essential University Physics (3rd Edition)

3rd Edition

ISBN: 9780134202709

Author: Richard Wolfson

Publisher: PEARSON

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Variation of pressure

From the equation of pressure, pressure is directly proportional to the applied force.

Question

Chapter 15, Problem 60P

To determine

The density of the oil.

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Chapter 15, Problem 59P

Chapter 15, Problem 61P

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Chapter 15 Solutions

Essential University Physics (3rd Edition)

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The density of the oil.

Solution Summary: The author explains the density of the oil and the pressure difference between unconstricted flow and venturi.

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Chapter 15 Solutions