For the reaction CdC 2 O 4 + 4 NH 3 ( a q ) ⇌ Cd ( NH 3 ) 4 2 + ( a q ) + C 2 O 4 2 − ( a q ) (a) calculate K . ( K sp for CdC 2 O 4 is 1.5 × 10 − 8 .) (b) calculate [NH 3 ] at equilibrium when 2.00 g of CdC 2 O 4 are dissolved in 1.00 L of solution.
For the reaction CdC 2 O 4 + 4 NH 3 ( a q ) ⇌ Cd ( NH 3 ) 4 2 + ( a q ) + C 2 O 4 2 − ( a q ) (a) calculate K . ( K sp for CdC 2 O 4 is 1.5 × 10 − 8 .) (b) calculate [NH 3 ] at equilibrium when 2.00 g of CdC 2 O 4 are dissolved in 1.00 L of solution.
Solution Summary: The author explains that the equilibrium constant (K) of the given reaction needs to be calculated.
In the phase diagram of steel (two components Fe and C), region A is the gamma austenite solid and region B contains the gamma solid and liquid. Indicate the degrees of freedom that the fields A and B have,
For a condensed binary system in equilibrium at constant pressure, indicate the maximum number of phases that can exist.
Part V. Label ad match the carbons in compounds Jane and Diane
w/ the corresponding peak no.
in the
Spectra (Note: use the given peak no. To label the carbons, other peak
no are intentionally
omitted)
7 4 2
-0.13
-0.12
-0.11
-0.10
-0.08
8
CI
Jane
1
-0.09
5
210
200
190
180
170
160
150
140
130
120
110
100
-8
90
f1 (ppm)
11
8
172.4
172.0
f1 (ppr
HO
CI
NH
Diane
7
3
11
80
80
-80
-R
70
60
60
2
5
-8
50
40
8.
170
160
150
140
130
120
110
100
90
-0
80
70
20
f1 (ppm)
15
30
-20
20
-60
60
-0.07
-0.06
-0.05
-0.04
-0.03
-0.02
-0.01
-0.00
-0.01
10
-0.17
16
15
56
16
-0.16
-0.15
-0.14
-0.13
-0.12
-0.11
-0.10
-0.09
-0.08
-0.07
-0.06
-0.05
-0.04
17.8 17.6 17.4 17.2 17.0
f1 (ppm)
-0.03
-0.02
550
106
40
30
20
20
-0.01
-0.00
F-0.01
10
0
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell