Chapter 15, Problem 52E

Interpretation Introduction

Interpretation:

The direction of net reaction, if KO_2(s) and K₂CO_3(s) are maintained in contact within air at 1.00 atm and 25° needs to be determined.

Concept introduction:

According to the given information, KO_2(s) is reacted with CO_2(g). This is equilibrated with ${\text{K}}_{\text{2}}{\text{CO}}_3\left(s\right)$ and $O_2\left(g\right)$. The direction of the net reaction can be calculated by comparing the value of $Q_p$ and $K_p$. Q is the reaction quotient which uses to determine the direction of a reaction. If $Q_p>K_p$, a reaction will proceed to reverse, while $Q_P<K_P$, a reaction will proceed in the forward direction. And, if $Q_P=K_P$, a reaction will be at equilibrium.