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(III) A cord stretched to a tension FT consists of two sections (as in Fig. 15–19) whose linear densities are in μ1 and μ2. Take x = 0 to be the point (a knot) where they are joined, with μ1 referring to that section of cord to the left and μ2 that to the right. A sinusoidal wave, D = A sin[k1(x – v1t)], starts at the left end of the cord. When it reaches the knot, part of it is reflected and part is transmitted. Let the equation of the reflected wave be DR = AR sin[k1(x + v1t)] and that for the transmitted wave be DT = AT sin[k2(x – v2t)]. Since the frequency must be the same in both sections, we have ω1 = ω2 or k1v1 = k1v2. (a) Because the cord is continuous, a point an infinitesimal distance to the left of the knot has the same displacement at any moment (due to incident plus reflected waves) as a point just to the right of the knot (due to the transmitted wave). Thus show that A = AT + AR. (b) Assuming that the slope (∂D/∂x) of the cord just to the left of the knot is the same as the slope just to the right of the knot, show that the amplitude of the reflected wave is given by
(c) What is AT in terms of A?
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Pearson eText -- Physics for Scientists and Engineers with Modern Physics -- Instant Access (Pearson+)
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