EBK FUNDAMENTALS OF ELECTRIC CIRCUITS
6th Edition
ISBN: 8220102801448
Author: Alexander
Publisher: YUZU
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Chapter 15, Problem 3RQ
To determine
Choose the correct option to find the Laplace transform of
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The Laplace Transform for f"(t) is *
s^2F(s) - sf(0) - f'(0)
F(s-a)
sF(s) - f(0)
-F'(s)
Find the Laplace Transform of the following functions
6) f(t) = e2" cos(t)
Ans. F(s) =
S+2
(s+2)° +1
Chapter 15 Solutions
EBK FUNDAMENTALS OF ELECTRIC CIRCUITS
Ch. 15.2 - Prob. 1PPCh. 15.2 - Prob. 2PPCh. 15.3 - Prob. 3PPCh. 15.3 - Prob. 4PPCh. 15.3 - Prob. 5PPCh. 15.3 - Prob. 6PPCh. 15.3 - Obtain the initial and the final values of...Ch. 15.4 - Prob. 8PPCh. 15.4 - Find f(t) if F(s)=48(s+2)(s+1)(s+3)(s+4)Ch. 15.4 - Obtain g(t) if G(s)=s3+2s+6s(s+1)2(s+3)
Ch. 15.4 - Find g(t) given that G(s)=20(s+1)(s2+4s+13)Ch. 15.5 - Graphically convolve the two functions in Fig....Ch. 15.5 - Given g(t) and f(t) in Fig. 15.20, graphically...Ch. 15.5 - Use convolution to find vo(t) in the circuit of...Ch. 15.6 - Prob. 15PPCh. 15.6 - Prob. 16PPCh. 15 - Prob. 1RQCh. 15 - Prob. 2RQCh. 15 - Prob. 3RQCh. 15 - Prob. 4RQCh. 15 - Prob. 5RQCh. 15 - If F(s) = 1/(s + 2), then f(t) is (a) e2t u(t) (b)...Ch. 15 - Prob. 7RQCh. 15 - Prob. 8RQCh. 15 - Prob. 9RQCh. 15 - Prob. 10RQCh. 15 - Prob. 1PCh. 15 - Prob. 2PCh. 15 - Prob. 3PCh. 15 - Prob. 4PCh. 15 - Prob. 5PCh. 15 - Prob. 6PCh. 15 - Prob. 7PCh. 15 - Prob. 8PCh. 15 - Prob. 9PCh. 15 - Prob. 10PCh. 15 - Find F(s) if: (a) ft=6etcosh2t (b) ft=3te2tsinh4t...Ch. 15 - If g(t) = 4e 2t cos 4t, find G(s).Ch. 15 - Prob. 13PCh. 15 - Prob. 14PCh. 15 - Prob. 15PCh. 15 - Prob. 16PCh. 15 - Prob. 17PCh. 15 - Prob. 18PCh. 15 - Prob. 19PCh. 15 - Prob. 20PCh. 15 - Prob. 21PCh. 15 - Prob. 22PCh. 15 - Prob. 23PCh. 15 - Design a problem to help other students better...Ch. 15 - Let F(s)=18(s+1)(s+2)(s+3) (a) Use the initial and...Ch. 15 - Determine the initial and final values of f(t), if...Ch. 15 - Prob. 27PCh. 15 - Prob. 28PCh. 15 - Prob. 29PCh. 15 - Prob. 30PCh. 15 - Find f(t) for each F(s): (a) 10ss+1s+2s+3 (b)...Ch. 15 - Prob. 32PCh. 15 - Prob. 33PCh. 15 - Prob. 34PCh. 15 - Obtain f(t) for the following transforms: (a)...Ch. 15 - Prob. 36PCh. 15 - Prob. 37PCh. 15 - Prob. 38PCh. 15 - Determine f(t) if: (a)...Ch. 15 - Show that...Ch. 15 - Prob. 41PCh. 15 - Design a problem to help other students better...Ch. 15 - Prob. 43PCh. 15 - Prob. 44PCh. 15 - Given h(t) = 4e2tu(t) and x(t) = (t) 2e 2tu(t),...Ch. 15 - Given the following functions...Ch. 15 - A system has the transfer function...Ch. 15 - Find f(t) using convolution given that: (a)...Ch. 15 - Prob. 49PCh. 15 - Prob. 50PCh. 15 - Given that v(0) = 5 and dv(0)/dt = 10, solve...Ch. 15 - Prob. 52PCh. 15 - Prob. 53PCh. 15 - Design a problem to help other students better...Ch. 15 - Prob. 55PCh. 15 - Solve for v(t) in the integrodifferential equation...Ch. 15 - Prob. 57PCh. 15 - Given that dvdt+2v+50tv()d=4u(t) with v(0) = 1,...Ch. 15 - Solve the integrodifferential equation...Ch. 15 - Prob. 60P
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- Determine y(t) such that y(t) = x(t) * h(t) for the signals shown in the figure. h(t) 1 hr 0 x(1) 1 0 1 1 The expressions for y(t) are: For the time interval 0 2, y(t) is 12, /2) t+ ( |),arrow_forwardFind the value of x(t) for t= 0, if it has the Laplace transform: O 8 00 8 1 X (s) (s+ 4) (s+2) s³ +2s² + sarrow_forwardThe inverse Laplace transform of the following function is: F(s)= s-3 O a. f(t) = 5e-3tu(t) O b. None of the answers O c. f(t) = 5e³u(t) С. d. f(t) = 5e3su(t) = 5e3$u(t) O e. f(t) = 5e-38u(t)arrow_forward
- Please answer all subpart please I will like it pleasearrow_forwardHello. I'm working on solving with laplace. I apreciate the help. Thank youarrow_forwardThe inverse Laplace transform of the following function is: F(s) = (s+4)2 O a. (e)t O b. None of the answers O c. (e-4t)t-1 O d. (et)t+2 O e. (e-4t+2)tarrow_forward
- Calculate the value of X (2), where the Laplace transform of the following x(t) is X(s). a(t) = 1.7e-" u(t) + 4.4(1 +t)e-*u(t) -2t -3tarrow_forward6. Do not use MatLab or Octavearrow_forwardThe Inverse Laplace transform of F(s) = Select one: O f(t)=[0.5-0.5e-4(t-3) ]u(t-3) O f(t) = (0.5-0.5e-4(+3)]u(t+3) O f(t) = [0.5-0.5e4(+3) Ju(t+3) O f(t) = [1-e-4(+3)]u(t+3) 2e³ 8(8-+-4) is:arrow_forward
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