Mcdougal Littell Algebra 2: Student Edition (c) 2004 2004
4th Edition
ISBN: 9780618250202
Author: Ron Larson, Laurie Boswell, Timothy D. Kanold, Lee Stiff
Publisher: Mcdougal Littell / Houghton Mifflin
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Expert Solution & Answer
Chapter 1.5, Problem 3MRPS
Solution
a.
To write: An expression for w in terms of h .
An expression for w in terms of h is w=43h
Given:
The diagonal of the screen on a laptop computer measures 15 inches. The ratio of the screen's width w to its height h is 4:3 .
Calculations:
The ratio of w to h is given as 4:3 . Thus, wh=43
Find the cross products and solve for w .
w⋅3=4⋅hw⋅33=4⋅h3w=43h
b.
To write: An equation that you can use to find h .
An equation that you can use to find h is h2=81 .
Given:
The diagonal of the screen on a laptop computer measures 15 inches. The ratio of the screen's width w to its height h is 4:3 .
Calculations:
Consider the following figure.
Apply the Pythagorean Theorem.
h2+w2=152
Substitute for w obtained in part a.
h2+(43h)2=225h2+169h2=225
Simplify to get an equation for h .
259h2=225259h2⋅925=225⋅925h2=81
c.
To solve: An equation from part (b).
Solution is 9 .
Given:
The diagonal of the screen on a laptop computer measures 15 inches. The ratio of the screen's width w to its height h is 4:3 .
Calculations:
For solving the equation, take the square root on each side.
√h2=±√81h=±9
Since height cannot be negative, reject the solution h=−9 . Thus, the possible solution is 9 .
d.
To find: Height, width, and area of the laptop screen.
The height of the laptop screen is 9 inches, the width of the screen is 12 inches and the area of the screen is 108 square inches.
Given:
The diagonal of the screen on a laptop computer measures 15 inches. The ratio of the screen's width w to its height h is 4:3 .
Calculations:
The height of the laptop screen is 9 inches.
For finding the width, substitute 9 for h in the expression for w and evaluate.
w=43(9)=12
The width of the screen is 12 inches.
Since the screen is in the shape of a rectangle, its area is the product of the width and the height.
Area=9(12)=108
Therefore, the area of the screen is 108 square inches.
Chapter 1 Solutions
Mcdougal Littell Algebra 2: Student Edition (c) 2004 2004
Ch. 1.1 - Prob. 1GPCh. 1.1 - Prob. 2GPCh. 1.1 - Prob. 3GPCh. 1.1 - Prob. 4GPCh. 1.1 - Prob. 5GPCh. 1.1 - Prob. 6GPCh. 1.1 - Prob. 7GPCh. 1.1 - Prob. 8GPCh. 1.1 - Prob. 1ECh. 1.1 - Prob. 2E
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Prob. 1ECh. 1.6 - Prob. 2ECh. 1.6 - Prob. 3ECh. 1.6 - Prob. 4ECh. 1.6 - Prob. 5ECh. 1.6 - Prob. 6ECh. 1.6 - Prob. 7ECh. 1.6 - Prob. 8ECh. 1.6 - Prob. 9ECh. 1.6 - Prob. 10ECh. 1.6 - Prob. 11ECh. 1.6 - Prob. 12ECh. 1.6 - Prob. 13ECh. 1.6 - Prob. 14ECh. 1.6 - Prob. 15ECh. 1.6 - Prob. 16ECh. 1.6 - Prob. 17ECh. 1.6 - Prob. 18ECh. 1.6 - Prob. 19ECh. 1.6 - Prob. 20ECh. 1.6 - Prob. 21ECh. 1.6 - Prob. 22ECh. 1.6 - Prob. 23ECh. 1.6 - Prob. 24ECh. 1.6 - Prob. 25ECh. 1.6 - Prob. 26ECh. 1.6 - Prob. 27ECh. 1.6 - Prob. 28ECh. 1.6 - Prob. 29ECh. 1.6 - Prob. 30ECh. 1.6 - Prob. 31ECh. 1.6 - Prob. 32ECh. 1.6 - Prob. 33ECh. 1.6 - Prob. 34ECh. 1.6 - Prob. 35ECh. 1.6 - Prob. 36ECh. 1.6 - Prob. 37ECh. 1.6 - Prob. 38ECh. 1.6 - Prob. 39ECh. 1.6 - Prob. 40ECh. 1.6 - Prob. 41ECh. 1.6 - Prob. 42ECh. 1.6 - Prob. 43ECh. 1.6 - Prob. 44ECh. 1.6 - Prob. 45ECh. 1.6 - Prob. 46ECh. 1.6 - Prob. 47ECh. 1.6 - Prob. 48ECh. 1.6 - Prob. 49ECh. 1.6 - Prob. 50ECh. 1.6 - Prob. 51ECh. 1.6 - Prob. 52ECh. 1.6 - Prob. 53ECh. 1.6 - Prob. 54ECh. 1.6 - 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Prob. 67PSCh. 1.7 - Prob. 68PSCh. 1.7 - Prob. 1QCh. 1.7 - Prob. 2QCh. 1.7 - Prob. 3QCh. 1.7 - Prob. 4QCh. 1.7 - Prob. 5QCh. 1.7 - Prob. 6QCh. 1.7 - Prob. 7QCh. 1.7 - Prob. 8QCh. 1.7 - Prob. 9QCh. 1.7 - Prob. 10QCh. 1.7 - Prob. 11QCh. 1.7 - Prob. 12QCh. 1.7 - Prob. 13QCh. 1.7 - Prob. 14QCh. 1.7 - Prob. 15QCh. 1.7 - Prob. 16QCh. 1.7 - Prob. 17QCh. 1.7 - Prob. 18QCh. 1.7 - Prob. 19QCh. 1.8 - Prob. 1GPCh. 1.8 - Prob. 2GPCh. 1.8 - Prob. 3GPCh. 1.8 - Prob. 4GPCh. 1.8 - Prob. 5GPCh. 1.8 - Prob. 6GPCh. 1.8 - Prob. 7GPCh. 1.8 - Prob. 8GPCh. 1.8 - Prob. 9GPCh. 1.8 - Prob. 10GPCh. 1.8 - Prob. 1ECh. 1.8 - Prob. 2ECh. 1.8 - Prob. 3ECh. 1.8 - Prob. 4ECh. 1.8 - Prob. 5ECh. 1.8 - Prob. 6ECh. 1.8 - Prob. 7ECh. 1.8 - Prob. 8ECh. 1.8 - Prob. 9ECh. 1.8 - Prob. 10ECh. 1.8 - Prob. 11ECh. 1.8 - Prob. 12ECh. 1.8 - Prob. 13ECh. 1.8 - Prob. 14ECh. 1.8 - Prob. 15ECh. 1.8 - Prob. 16ECh. 1.8 - Prob. 17ECh. 1.8 - Prob. 18ECh. 1.8 - Prob. 19ECh. 1.8 - Prob. 20ECh. 1.8 - Prob. 21ECh. 1.8 - Prob. 22ECh. 1.8 - Prob. 23ECh. 1.8 - Prob. 24ECh. 1.8 - Prob. 25ECh. 1.8 - Prob. 26ECh. 1.8 - Prob. 27ECh. 1.8 - Prob. 28ECh. 1.8 - Prob. 29ECh. 1.8 - Prob. 30ECh. 1.8 - Prob. 31ECh. 1.8 - Prob. 32ECh. 1.8 - Prob. 33ECh. 1.8 - Prob. 34ECh. 1.8 - Prob. 35ECh. 1.8 - Prob. 36ECh. 1.8 - Prob. 37ECh. 1.8 - Prob. 38ECh. 1.8 - Prob. 39ECh. 1.8 - Prob. 40ECh. 1.8 - Prob. 41ECh. 1.8 - Prob. 42ECh. 1.8 - Prob. 43ECh. 1.8 - Prob. 44ECh. 1.8 - Prob. 45ECh. 1.8 - Prob. 46ECh. 1.8 - Prob. 47ECh. 1.8 - Prob. 48ECh. 1.8 - Prob. 49ECh. 1.8 - Prob. 50ECh. 1.8 - Prob. 51ECh. 1.8 - Prob. 52ECh. 1.8 - Prob. 53ECh. 1.8 - Prob. 54ECh. 1.8 - Prob. 55ECh. 1.8 - Prob. 56ECh. 1.8 - Prob. 57ECh. 1.8 - Prob. 58ECh. 1.8 - Prob. 59ECh. 1.8 - Prob. 60ECh. 1.8 - Prob. 61ECh. 1.8 - Prob. 62ECh. 1.8 - Prob. 63ECh. 1.8 - Prob. 64ECh. 1.8 - Prob. 65ECh. 1.8 - Prob. 66ECh. 1.8 - Prob. 67ECh. 1.8 - Prob. 68PSCh. 1.8 - Prob. 69PSCh. 1.8 - Prob. 70PSCh. 1.8 - Prob. 71PSCh. 1.8 - Prob. 72PSCh. 1.8 - Prob. 73PSCh. 1.8 - Prob. 74PSCh. 1.9 - Prob. 1GPCh. 1.9 - Prob. 2GPCh. 1.9 - Prob. 3GPCh. 1.9 - Prob. 4GPCh. 1.9 - Prob. 5GPCh. 1.9 - Prob. 6GPCh. 1.9 - Prob. 7GPCh. 1.9 - Prob. 1ECh. 1.9 - Prob. 2ECh. 1.9 - Prob. 3ECh. 1.9 - Prob. 4ECh. 1.9 - Prob. 5ECh. 1.9 - Prob. 6ECh. 1.9 - Prob. 7ECh. 1.9 - Prob. 8ECh. 1.9 - Prob. 9ECh. 1.9 - Prob. 10ECh. 1.9 - Prob. 11ECh. 1.9 - Prob. 12ECh. 1.9 - Prob. 13ECh. 1.9 - Prob. 14ECh. 1.9 - Prob. 15ECh. 1.9 - Prob. 16ECh. 1.9 - Prob. 17ECh. 1.9 - Prob. 18ECh. 1.9 - Prob. 19ECh. 1.9 - Prob. 20ECh. 1.9 - Prob. 21ECh. 1.9 - Prob. 22ECh. 1.9 - Prob. 23ECh. 1.9 - Prob. 24ECh. 1.9 - Prob. 25ECh. 1.9 - Prob. 26ECh. 1.9 - Prob. 27ECh. 1.9 - Prob. 28ECh. 1.9 - Prob. 29ECh. 1.9 - Prob. 30ECh. 1.9 - Prob. 31ECh. 1.9 - Prob. 32ECh. 1.9 - Prob. 33ECh. 1.9 - Prob. 34ECh. 1.9 - Prob. 35ECh. 1.9 - Prob. 36ECh. 1.9 - Prob. 37ECh. 1.9 - Prob. 38ECh. 1.9 - Prob. 39ECh. 1.9 - Prob. 40ECh. 1.9 - Prob. 41ECh. 1.9 - Prob. 42ECh. 1.9 - Prob. 43ECh. 1.9 - Prob. 44ECh. 1.9 - Prob. 45ECh. 1.9 - Prob. 46ECh. 1.9 - Prob. 47ECh. 1.9 - Prob. 48ECh. 1.9 - Prob. 49ECh. 1.9 - Prob. 50ECh. 1.9 - Prob. 51ECh. 1.9 - Prob. 52ECh. 1.9 - Prob. 53ECh. 1.9 - Prob. 54ECh. 1.9 - Prob. 55ECh. 1.9 - Prob. 56ECh. 1.9 - Prob. 57ECh. 1.9 - Prob. 58ECh. 1.9 - Prob. 59ECh. 1.9 - Prob. 60ECh. 1.9 - Prob. 61ECh. 1.9 - Prob. 62ECh. 1.9 - Prob. 63ECh. 1.9 - Prob. 64ECh. 1.9 - Prob. 65ECh. 1.9 - Prob. 66ECh. 1.9 - Prob. 67ECh. 1.9 - Prob. 68ECh. 1.9 - Prob. 69ECh. 1.9 - Prob. 70PSCh. 1.9 - Prob. 71PSCh. 1.9 - Prob. 72PSCh. 1.9 - Prob. 73PSCh. 1.9 - Prob. 74PSCh. 1.9 - Prob. 75PSCh. 1.9 - Prob. 76PSCh. 1.9 - Prob. 77PSCh. 1.9 - Prob. 1QCh. 1.9 - Prob. 2QCh. 1.9 - Prob. 3QCh. 1.9 - Prob. 4QCh. 1.9 - Prob. 5QCh. 1.9 - Prob. 6QCh. 1.9 - Prob. 7QCh. 1.9 - Prob. 8QCh. 1.9 - Prob. 9QCh. 1.9 - Prob. 10QCh. 1.9 - Prob. 11QCh. 1.9 - Prob. 12QCh. 1.9 - Prob. 13QCh. 1.9 - Prob. 1MRPSCh. 1.9 - Prob. 2MRPSCh. 1.9 - Prob. 3MRPSCh. 1.9 - Prob. 4MRPSCh. 1.9 - Prob. 5MRPSCh. 1.9 - Prob. 6MRPSCh. 1.9 - Prob. 7MRPSCh. 1.9 - Prob. 8MRPSCh. 1.9 - Prob. 9MRPSCh. 1 - Prob. 1VECh. 1 - Prob. 2VECh. 1 - Prob. 3VECh. 1 - Prob. 4VECh. 1 - Prob. 5REAECh. 1 - Prob. 6REAECh. 1 - Prob. 7REAECh. 1 - Prob. 8REAECh. 1 - Prob. 9REAECh. 1 - Prob. 10REAECh. 1 - Prob. 11REAECh. 1 - Prob. 12REAECh. 1 - Prob. 13REAECh. 1 - Prob. 14REAECh. 1 - Prob. 15REAECh. 1 - Prob. 16REAECh. 1 - Prob. 17REAECh. 1 - Prob. 18REAECh. 1 - Prob. 19REAECh. 1 - Prob. 20REAECh. 1 - Prob. 21REAECh. 1 - Prob. 22REAECh. 1 - Prob. 23REAECh. 1 - Prob. 24REAECh. 1 - Prob. 25REAECh. 1 - Prob. 26REAECh. 1 - Prob. 27REAECh. 1 - Prob. 28REAECh. 1 - Prob. 29REAECh. 1 - Prob. 30REAECh. 1 - Prob. 31REAECh. 1 - Prob. 32REAECh. 1 - Prob. 33REAECh. 1 - Prob. 34REAECh. 1 - Prob. 35REAECh. 1 - Prob. 36REAECh. 1 - Prob. 37REAECh. 1 - Prob. 38REAECh. 1 - Prob. 39REAECh. 1 - Prob. 40REAECh. 1 - Prob. 41REAECh. 1 - Prob. 42REAECh. 1 - Prob. 43REAECh. 1 - Prob. 44REAECh. 1 - Prob. 1TCh. 1 - Prob. 2TCh. 1 - Prob. 3TCh. 1 - Prob. 4TCh. 1 - Prob. 5TCh. 1 - Prob. 6TCh. 1 - Prob. 7TCh. 1 - Prob. 8TCh. 1 - Prob. 9TCh. 1 - Prob. 10TCh. 1 - Prob. 11TCh. 1 - Prob. 12TCh. 1 - Prob. 13TCh. 1 - Prob. 14TCh. 1 - Prob. 15TCh. 1 - Prob. 16TCh. 1 - Prob. 17TCh. 1 - Prob. 18TCh. 1 - Prob. 19TCh. 1 - Prob. 20TCh. 1 - Prob. 21TCh. 1 - Prob. 22TCh. 1 - Prob. 23TCh. 1 - Prob. 24TCh. 1 - Prob. 25TCh. 1 - Prob. 26TCh. 1 - Prob. 27TCh. 1 - Prob. 28TCh. 1 - Prob. 29TCh. 1 - Prob. 30TCh. 1 - Prob. 31TCh. 1 - Prob. 1PCh. 1 - Prob. 2PCh. 1 - Prob. 1TPCh. 1 - Prob. 2TPCh. 1 - Prob. 3TPCh. 1 - Prob. 4TPCh. 1 - Prob. 5TPCh. 1 - Prob. 6TPCh. 1 - Prob. 7TPCh. 1 - Prob. 8TPCh. 1 - Prob. 9TPCh. 1 - Prob. 10TPCh. 1 - Prob. 11TPCh. 1 - Prob. 12TPCh. 1 - Prob. 13TPCh. 1 - Prob. 14TPCh. 1 - Prob. 15TPCh. 1 - Prob. 16TPCh. 1 - Prob. 17TPCh. 1 - Prob. 18TPCh. 1 - Prob. 19TPCh. 1 - Prob. 20TPCh. 1 - Prob. 21TPCh. 1 - Prob. 22TP
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- Kate, Luke, Mary and Nancy are sharing a cake. The cake had previously been divided into four slices (s1, s2, s3 and s4). The following table shows the values of the slices in the eyes of each player. What is fair share to nancy? S1 S2 S3 S4 Kate $4.00 $6.00 $6.00 $4.00 Luke $5.30 $5.00 $5.25 $5.45 Mary $4.25 $4.50 $3.50 $3.75 Nancy $6.00 $4.00 $4.00 $6.00arrow_forwardKate, Luke, Mary and Nancy are sharing a cake. The cake had previously been divided into four slices (s1, s2, s3 and s4). The following table shows the values of the slices in the eyes of each player. S1 S2 S3 S4 Kate $4.00 $6.00 $6.00 $4.00 Luke $5.30 $5.00 $5.25 $5.45 Mary $4.25 $4.50 $3.50 $3.75 Nancy $6.00 $4.00 $4.00 $6.00 how much is the cak worth to maryarrow_forwardKate, Luke, Mary and Nancy are sharing a cake. The cake had previously been divided into four slices (s1, s2, s3 and s4). The following table shows the values of the slices in the eyes of each player. What is the threshold of fair share for Luke? S1 S2 S3 S4 Kate $4.00 $6.00 $6.00 $4.00 Luke $5.30 $5.00 $5.25 $5.45 Mary $4.25 $4.50 $3.50 $3.75 Nancy $6.00 $4.00 $4.00 $6.00arrow_forward
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- Can you help me solve this?arrow_forwardName Assume there is the following simplified grade book: Homework Labs | Final Exam | Project Avery 95 98 90 100 Blake 90 96 Carlos 83 79 Dax 55 30 228 92 95 79 90 65 60 Assume that the weights used to compute the final grades are homework 0.3, labs 0.2, the final 0.35, and the project 0.15. | Write an explicit formula to compute Avery's final grade using a single inner product. Write an explicit formula to compute everyone's final grade simultane- ously using a single matrix-vector product.arrow_forward1. Explicitly compute by hand (with work shown) the following Frobenius inner products 00 4.56 3.12 (a) ((º º º). (156 (b) 10.9 -1 0 2)), Fro 5')) Froarrow_forward
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