
To find: The maximum height of the horseshoe.
The maximum height of the horseshoe is equal to 16.1 feet.
Given information:
The graph shows the height h (in feet) after t seconds of a horseshoe tossed during a game of horseshoes. The initial vertical velocity of the horseshoe is 30 feet per second.
Calculation:
The general equation of the
h(t)=at2+bt+c ... (1)
On differentiating with respect to t :
dhdt=2at+bv=2at+b ... (2)
Since the initial vertical velocity of the horseshoe is 30 feet per second, so substitute t=0,v=30 in the equation (2):
30=2a(0)+b 30=0+bb=30
Substitute b=30 in the equation (1):
h(t)=at2+30t+c ... (3)
At t=0,h=2 , substitute t=0,h=2 in the equation (3):
2=a(0)2+30(0)+c2=0+0+cc=2
Substitute c=2 in the above equation:
h(t)=at2+30t+2 ... (4)
Substitute t=1.95,h=0 in the equation (4):
0=a(1.95)2+30(1.95)+20=3.8025a+58.5+23.8025a+60.5=0a=−15.91
Therefore, the equation of the height is below:
h(t)=−15.91t2+30t+2
Now, calculate the vertex points.
t=−b2at=−302(−15.91)t≈0.943
Substitute t=0.943 in the above equation and calculate the maximum height below:
h=−15.91(0.943)2+30(0.943)+2≈16.1
Hence, the maximum height of the horseshoe is 16.1 feet.
Chapter 1 Solutions
Mcdougal Littell Algebra 2: Student Edition (c) 2004 2004
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