Pre-Algebra
1st Edition
ISBN: 9780618800766
Author: Ron Larson, Lee Stiff, Laurie Boswell, Timothy Kanold
Publisher: Houghton Mifflin-High School
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Question
Chapter 1.5, Problem 3C
To determine
To Find: The sum of10+(-5) by using number line.
Expert Solution & Answer
Answer to Problem 3C
The the sum of 10+(-5)=5
Explanation of Solution
Given information: To find the sum of 10+(-5) on a number line and move left 10 unit then move 5 unit right.
Hence we move left 10 unit then move 5 unit right.
So, The final position is 5 . So, 10+(-5)=5.
Chapter 1 Solutions
Pre-Algebra
Ch. 1.1 - Prob. 1CCh. 1.1 - Prob. 2CCh. 1.1 - Prob. 3CCh. 1.1 - Prob. 4CCh. 1.1 - Prob. 1ECh. 1.1 - Prob. 2ECh. 1.1 - Prob. 3ECh. 1.1 - Prob. 4ECh. 1.1 - Prob. 5ECh. 1.1 - Prob. 6E
Ch. 1.1 - Prob. 7ECh. 1.1 - Prob. 8ECh. 1.1 - Prob. 9ECh. 1.1 - Prob. 10ECh. 1.1 - Prob. 11ECh. 1.1 - Prob. 12ECh. 1.1 - Prob. 13ECh. 1.1 - Prob. 14ECh. 1.1 - Prob. 15ECh. 1.1 - Prob. 16ECh. 1.1 - Prob. 17ECh. 1.1 - Prob. 18ECh. 1.1 - Prob. 19ECh. 1.1 - Prob. 20ECh. 1.1 - Prob. 21ECh. 1.1 - Prob. 22ECh. 1.1 - Prob. 23ECh. 1.1 - Prob. 24ECh. 1.1 - Prob. 25ECh. 1.1 - Prob. 26ECh. 1.1 - Prob. 27ECh. 1.1 - Prob. 28ECh. 1.1 - Prob. 29ECh. 1.1 - Prob. 30ECh. 1.1 - Prob. 31ECh. 1.1 - Prob. 32ECh. 1.1 - Prob. 33ECh. 1.1 - Prob. 34ECh. 1.1 - Prob. 35ECh. 1.1 - Prob. 36ECh. 1.1 - Prob. 37ECh. 1.1 - Prob. 38ECh. 1.1 - Prob. 39ECh. 1.1 - Prob. 40ECh. 1.1 - Prob. 41ECh. 1.1 - Prob. 42ECh. 1.1 - Prob. 43ECh. 1.1 - Prob. 44ECh. 1.1 - Prob. 45ECh. 1.1 - Prob. 46ECh. 1.1 - Prob. 47ECh. 1.1 - Prob. 48ECh. 1.1 - Prob. 49ECh. 1.1 - Prob. 50ECh. 1.1 - Prob. 51ECh. 1.1 - Prob. 52ECh. 1.1 - Prob. 53ECh. 1.1 - Prob. 54ECh. 1.1 - Prob. 55ECh. 1.1 - Prob. 56ECh. 1.1 - Prob. 57ECh. 1.1 - Prob. 58ECh. 1.1 - Prob. 59ECh. 1.1 - Prob. 60ECh. 1.1 - Prob. 61ECh. 1.1 - Prob. 62ECh. 1.1 - Prob. 63ECh. 1.1 - Prob. 64ECh. 1.1 - Prob. 65ECh. 1.1 - Prob. 66ECh. 1.1 - Prob. 67ECh. 1.2 - Prob. 1CCh. 1.2 - Prob. 2CCh. 1.2 - Prob. 3CCh. 1.2 - Prob. 4CCh. 1.2 - Prob. 5CCh. 1.2 - Prob. 6CCh. 1.2 - Prob. 7CCh. 1.2 - Prob. 8CCh. 1.2 - Prob. 9CCh. 1.2 - Prob. 10CCh. 1.2 - Prob. 11CCh. 1.2 - Prob. 1ECh. 1.2 - Prob. 2ECh. 1.2 - Prob. 3ECh. 1.2 - Prob. 4ECh. 1.2 - Prob. 5ECh. 1.2 - Prob. 6ECh. 1.2 - Prob. 7ECh. 1.2 - Prob. 8ECh. 1.2 - Prob. 9ECh. 1.2 - Prob. 10ECh. 1.2 - Prob. 11ECh. 1.2 - Prob. 12ECh. 1.2 - Prob. 13ECh. 1.2 - Prob. 14ECh. 1.2 - Prob. 15ECh. 1.2 - Prob. 16ECh. 1.2 - Prob. 17ECh. 1.2 - Prob. 18ECh. 1.2 - Prob. 19ECh. 1.2 - Prob. 20ECh. 1.2 - Prob. 21ECh. 1.2 - Prob. 22ECh. 1.2 - Prob. 23ECh. 1.2 - Prob. 24ECh. 1.2 - Prob. 25ECh. 1.2 - Prob. 26ECh. 1.2 - Prob. 27ECh. 1.2 - Prob. 28ECh. 1.2 - Prob. 29ECh. 1.2 - Prob. 30ECh. 1.2 - Prob. 31ECh. 1.2 - Prob. 32ECh. 1.2 - Prob. 33ECh. 1.2 - Prob. 34ECh. 1.2 - Prob. 35ECh. 1.2 - Prob. 36ECh. 1.2 - Prob. 37ECh. 1.2 - Prob. 38ECh. 1.2 - Prob. 39ECh. 1.2 - Prob. 40ECh. 1.2 - Prob. 41ECh. 1.2 - Prob. 42ECh. 1.2 - Prob. 43ECh. 1.2 - Prob. 44ECh. 1.2 - Prob. 45ECh. 1.2 - Prob. 46ECh. 1.2 - Prob. 47ECh. 1.2 - Prob. 48ECh. 1.2 - Prob. 49ECh. 1.3 - Prob. 1CCh. 1.3 - Prob. 2CCh. 1.3 - Prob. 3CCh. 1.3 - Prob. 4CCh. 1.3 - Prob. 5CCh. 1.3 - Prob. 6CCh. 1.3 - Prob. 7CCh. 1.3 - Prob. 8CCh. 1.3 - Prob. 9CCh. 1.3 - Prob. 10CCh. 1.3 - Prob. 11CCh. 1.3 - Prob. 12CCh. 1.3 - Prob. 1ECh. 1.3 - Prob. 2ECh. 1.3 - Prob. 3ECh. 1.3 - Prob. 4ECh. 1.3 - Prob. 5ECh. 1.3 - Prob. 6ECh. 1.3 - Prob. 7ECh. 1.3 - Prob. 8ECh. 1.3 - Prob. 9ECh. 1.3 - Prob. 10ECh. 1.3 - Prob. 11ECh. 1.3 - Prob. 12ECh. 1.3 - Prob. 13ECh. 1.3 - Prob. 14ECh. 1.3 - Prob. 15ECh. 1.3 - Prob. 16ECh. 1.3 - Prob. 17ECh. 1.3 - Prob. 18ECh. 1.3 - Prob. 19ECh. 1.3 - Prob. 20ECh. 1.3 - Prob. 21ECh. 1.3 - Prob. 22ECh. 1.3 - Prob. 23ECh. 1.3 - Prob. 24ECh. 1.3 - Prob. 25ECh. 1.3 - Prob. 26ECh. 1.3 - Prob. 27ECh. 1.3 - Prob. 28ECh. 1.3 - Prob. 29ECh. 1.3 - Prob. 30ECh. 1.3 - Prob. 31ECh. 1.3 - Prob. 32ECh. 1.3 - Prob. 33ECh. 1.3 - Prob. 34ECh. 1.3 - Prob. 35ECh. 1.3 - Prob. 36ECh. 1.3 - Prob. 37ECh. 1.3 - Prob. 38ECh. 1.3 - Prob. 39ECh. 1.3 - Prob. 40ECh. 1.3 - Prob. 41ECh. 1.3 - Prob. 42ECh. 1.3 - Prob. 43ECh. 1.3 - Prob. 44ECh. 1.4 - Prob. 1CCh. 1.4 - Prob. 2CCh. 1.4 - Prob. 3CCh. 1.4 - Prob. 4CCh. 1.4 - Prob. 5CCh. 1.4 - Prob. 6CCh. 1.4 - Prob. 7CCh. 1.4 - Prob. 8CCh. 1.4 - Prob. 9CCh. 1.4 - Prob. 1ECh. 1.4 - Prob. 2ECh. 1.4 - Prob. 3ECh. 1.4 - Prob. 4ECh. 1.4 - Prob. 5ECh. 1.4 - Prob. 6ECh. 1.4 - Prob. 7ECh. 1.4 - Prob. 8ECh. 1.4 - Prob. 9ECh. 1.4 - Prob. 10ECh. 1.4 - Prob. 11ECh. 1.4 - Prob. 12ECh. 1.4 - Prob. 13ECh. 1.4 - Prob. 14ECh. 1.4 - Prob. 15ECh. 1.4 - Prob. 16ECh. 1.4 - Prob. 17ECh. 1.4 - Prob. 18ECh. 1.4 - Prob. 19ECh. 1.4 - Prob. 20ECh. 1.4 - Prob. 21ECh. 1.4 - Prob. 22ECh. 1.4 - Prob. 23ECh. 1.4 - Prob. 24ECh. 1.4 - Prob. 25ECh. 1.4 - Prob. 26ECh. 1.4 - Prob. 27ECh. 1.4 - Prob. 28ECh. 1.4 - Prob. 29ECh. 1.4 - Prob. 30ECh. 1.4 - Prob. 31ECh. 1.4 - Prob. 32ECh. 1.4 - Prob. 33ECh. 1.4 - Prob. 34ECh. 1.4 - Prob. 35ECh. 1.4 - Prob. 36ECh. 1.4 - Prob. 37ECh. 1.4 - Prob. 38ECh. 1.4 - Prob. 39ECh. 1.4 - Prob. 40ECh. 1.4 - Prob. 41ECh. 1.4 - Prob. 42ECh. 1.4 - Prob. 43ECh. 1.4 - Prob. 44ECh. 1.4 - Prob. 45ECh. 1.4 - Prob. 46ECh. 1.4 - Prob. 47ECh. 1.4 - Prob. 48ECh. 1.4 - Prob. 49ECh. 1.4 - Prob. 50ECh. 1.4 - Prob. 51ECh. 1.4 - Prob. 52ECh. 1.4 - Prob. 53ECh. 1.4 - Prob. 54ECh. 1.4 - Prob. 55ECh. 1.4 - Prob. 56ECh. 1.4 - Prob. 57ECh. 1.4 - Prob. 58ECh. 1.4 - Prob. 59ECh. 1.4 - Prob. 60ECh. 1.4 - Prob. 61ECh. 1.4 - Prob. 62ECh. 1.4 - Prob. 63ECh. 1.4 - Prob. 64ECh. 1.4 - Prob. 65ECh. 1.4 - Prob. 66ECh. 1.4 - Prob. 67ECh. 1.4 - Prob. 68ECh. 1.4 - Prob. 69ECh. 1.4 - Prob. 70ECh. 1.4 - Prob. 71ECh. 1.4 - Prob. 72ECh. 1.4 - Prob. 73ECh. 1.4 - Prob. 74ECh. 1.4 - Prob. 75ECh. 1.4 - Prob. 76ECh. 1.5 - Prob. 1CCh. 1.5 - Prob. 2CCh. 1.5 - Prob. 3CCh. 1.5 - Prob. 4CCh. 1.5 - Prob. 5CCh. 1.5 - Prob. 6CCh. 1.5 - Prob. 7CCh. 1.5 - Prob. 8CCh. 1.5 - Prob. 9CCh. 1.5 - Prob. 1ECh. 1.5 - Prob. 2ECh. 1.5 - Prob. 3ECh. 1.5 - Prob. 4ECh. 1.5 - Prob. 5ECh. 1.5 - Prob. 6ECh. 1.5 - Prob. 7ECh. 1.5 - Prob. 8ECh. 1.5 - Prob. 9ECh. 1.5 - Prob. 10ECh. 1.5 - Prob. 11ECh. 1.5 - Prob. 12ECh. 1.5 - Prob. 13ECh. 1.5 - Prob. 14ECh. 1.5 - Prob. 15ECh. 1.5 - Prob. 16ECh. 1.5 - Prob. 17ECh. 1.5 - Prob. 18ECh. 1.5 - Prob. 19ECh. 1.5 - Prob. 20ECh. 1.5 - Prob. 21ECh. 1.5 - Prob. 22ECh. 1.5 - Prob. 23ECh. 1.5 - Prob. 24ECh. 1.5 - Prob. 25ECh. 1.5 - Prob. 26ECh. 1.5 - Prob. 27ECh. 1.5 - Prob. 28ECh. 1.5 - Prob. 29ECh. 1.5 - Prob. 30ECh. 1.5 - Prob. 31ECh. 1.5 - Prob. 32ECh. 1.5 - Prob. 33ECh. 1.5 - Prob. 34ECh. 1.5 - Prob. 35ECh. 1.5 - Prob. 36ECh. 1.5 - Prob. 37ECh. 1.5 - Prob. 38ECh. 1.5 - Prob. 39ECh. 1.5 - Prob. 40ECh. 1.5 - Prob. 41ECh. 1.5 - Prob. 42ECh. 1.5 - Prob. 43ECh. 1.5 - Prob. 44ECh. 1.5 - Prob. 45ECh. 1.5 - Prob. 46ECh. 1.5 - Prob. 47ECh. 1.5 - Prob. 48ECh. 1.5 - Prob. 49ECh. 1.5 - Prob. 50ECh. 1.5 - Prob. 51ECh. 1.5 - Prob. 52ECh. 1.5 - Prob. 53ECh. 1.5 - Prob. 54ECh. 1.5 - Prob. 55ECh. 1.5 - Prob. 56ECh. 1.5 - Prob. 57ECh. 1.5 - Prob. 58ECh. 1.5 - Prob. 59ECh. 1.5 - Prob. 60ECh. 1.5 - Prob. 61ECh. 1.5 - Prob. 62ECh. 1.5 - Prob. 63ECh. 1.5 - Prob. 64ECh. 1.5 - Prob. 65ECh. 1.5 - Prob. 66ECh. 1.5 - Prob. 67ECh. 1.5 - Prob. 68ECh. 1.5 - Prob. 69ECh. 1.6 - Prob. 1CCh. 1.6 - Prob. 2CCh. 1.6 - Prob. 3CCh. 1.6 - Prob. 4CCh. 1.6 - Prob. 5CCh. 1.6 - Prob. 6CCh. 1.6 - Prob. 7CCh. 1.6 - Prob. 8CCh. 1.6 - Prob. 9CCh. 1.6 - Prob. 10CCh. 1.6 - Prob. 11CCh. 1.6 - Prob. 12CCh. 1.6 - Prob. 1ECh. 1.6 - Prob. 2ECh. 1.6 - Prob. 3ECh. 1.6 - Prob. 4ECh. 1.6 - Prob. 5ECh. 1.6 - Prob. 6ECh. 1.6 - Prob. 7ECh. 1.6 - Prob. 8ECh. 1.6 - Prob. 9ECh. 1.6 - Prob. 10ECh. 1.6 - Prob. 11ECh. 1.6 - Prob. 12ECh. 1.6 - Prob. 13ECh. 1.6 - Prob. 14ECh. 1.6 - Prob. 15ECh. 1.6 - Prob. 16ECh. 1.6 - Prob. 17ECh. 1.6 - Prob. 18ECh. 1.6 - Prob. 19ECh. 1.6 - Prob. 20ECh. 1.6 - Prob. 21ECh. 1.6 - Prob. 22ECh. 1.6 - Prob. 23ECh. 1.6 - Prob. 24ECh. 1.6 - Prob. 25ECh. 1.6 - Prob. 26ECh. 1.6 - Prob. 27ECh. 1.6 - Prob. 28ECh. 1.6 - Prob. 29ECh. 1.6 - Prob. 30ECh. 1.6 - Prob. 31ECh. 1.6 - Prob. 32ECh. 1.6 - Prob. 33ECh. 1.6 - Prob. 34ECh. 1.6 - Prob. 35ECh. 1.6 - Prob. 36ECh. 1.6 - Prob. 37ECh. 1.6 - Prob. 38ECh. 1.6 - Prob. 39ECh. 1.6 - Prob. 40ECh. 1.6 - Prob. 41ECh. 1.6 - Prob. 42ECh. 1.6 - Prob. 43ECh. 1.6 - Prob. 44ECh. 1.6 - Prob. 45ECh. 1.6 - Prob. 46ECh. 1.6 - Prob. 47ECh. 1.6 - Prob. 48ECh. 1.6 - Prob. 49ECh. 1.6 - Prob. 50ECh. 1.6 - Prob. 51ECh. 1.6 - Prob. 52ECh. 1.6 - Prob. 53ECh. 1.6 - Prob. 54ECh. 1.6 - Prob. 55ECh. 1.6 - Prob. 56ECh. 1.6 - Prob. 57ECh. 1.6 - Prob. 58ECh. 1.6 - Prob. 59ECh. 1.6 - Prob. 60ECh. 1.6 - Prob. 61ECh. 1.6 - Prob. 62ECh. 1.6 - Prob. 63ECh. 1.6 - Prob. 64ECh. 1.6 - Prob. 65ECh. 1.6 - Prob. 66ECh. 1.7 - Prob. 1CCh. 1.7 - Prob. 2CCh. 1.7 - Prob. 3CCh. 1.7 - Prob. 4CCh. 1.7 - Prob. 5CCh. 1.7 - Prob. 6CCh. 1.7 - Prob. 7CCh. 1.7 - Prob. 8CCh. 1.7 - Prob. 1ECh. 1.7 - Prob. 2ECh. 1.7 - Prob. 3ECh. 1.7 - Prob. 4ECh. 1.7 - Prob. 5ECh. 1.7 - Prob. 6ECh. 1.7 - Prob. 7ECh. 1.7 - Prob. 8ECh. 1.7 - Prob. 9ECh. 1.7 - Prob. 10ECh. 1.7 - Prob. 11ECh. 1.7 - Prob. 12ECh. 1.7 - Prob. 13ECh. 1.7 - Prob. 14ECh. 1.7 - Prob. 15ECh. 1.7 - Prob. 16ECh. 1.7 - Prob. 17ECh. 1.7 - Prob. 18ECh. 1.7 - Prob. 19ECh. 1.7 - Prob. 20ECh. 1.7 - Prob. 21ECh. 1.7 - Prob. 22ECh. 1.7 - Prob. 23ECh. 1.7 - Prob. 24ECh. 1.7 - Prob. 25ECh. 1.7 - Prob. 26ECh. 1.7 - Prob. 27ECh. 1.7 - Prob. 28ECh. 1.7 - Prob. 29ECh. 1.7 - Prob. 30ECh. 1.7 - Prob. 31ECh. 1.7 - Prob. 32ECh. 1.7 - Prob. 33ECh. 1.7 - Prob. 34ECh. 1.7 - Prob. 35ECh. 1.7 - Prob. 36ECh. 1.7 - Prob. 37ECh. 1.7 - Prob. 38ECh. 1.7 - Prob. 39ECh. 1.7 - Prob. 40ECh. 1.7 - Prob. 41ECh. 1.7 - Prob. 42ECh. 1.7 - Prob. 43ECh. 1.7 - Prob. 44ECh. 1.7 - Prob. 45ECh. 1.7 - Prob. 46ECh. 1.7 - Prob. 47ECh. 1.7 - Prob. 48ECh. 1.7 - Prob. 49ECh. 1.7 - Prob. 50ECh. 1.7 - Prob. 51ECh. 1.7 - Prob. 52ECh. 1.8 - Prob. 1CCh. 1.8 - Prob. 2CCh. 1.8 - Prob. 3CCh. 1.8 - Prob. 4CCh. 1.8 - Prob. 5CCh. 1.8 - Prob. 6CCh. 1.8 - Prob. 7CCh. 1.8 - Prob. 1ECh. 1.8 - Prob. 2ECh. 1.8 - Prob. 3ECh. 1.8 - Prob. 4ECh. 1.8 - Prob. 5ECh. 1.8 - Prob. 6ECh. 1.8 - Prob. 7ECh. 1.8 - Prob. 8ECh. 1.8 - Prob. 9ECh. 1.8 - Prob. 10ECh. 1.8 - Prob. 11ECh. 1.8 - Prob. 12ECh. 1.8 - Prob. 13ECh. 1.8 - Prob. 14ECh. 1.8 - Prob. 15ECh. 1.8 - Prob. 16ECh. 1.8 - Prob. 17ECh. 1.8 - Prob. 18ECh. 1.8 - Prob. 19ECh. 1.8 - Prob. 20ECh. 1.8 - Prob. 21ECh. 1.8 - Prob. 22ECh. 1.8 - Prob. 23ECh. 1.8 - Prob. 24ECh. 1.8 - Prob. 25ECh. 1.8 - Prob. 26ECh. 1.8 - Prob. 27ECh. 1.8 - Prob. 28ECh. 1.8 - Prob. 29ECh. 1.8 - Prob. 30ECh. 1.8 - Prob. 31ECh. 1.8 - Prob. 32ECh. 1.8 - Prob. 33ECh. 1.8 - Prob. 34ECh. 1.8 - Prob. 35ECh. 1.8 - Prob. 36ECh. 1.8 - Prob. 37ECh. 1.8 - Prob. 38ECh. 1.8 - Prob. 39ECh. 1.8 - Prob. 40ECh. 1.8 - Prob. 41ECh. 1.8 - Prob. 42ECh. 1.8 - Prob. 43ECh. 1.8 - Prob. 44ECh. 1 - Prob. 1PSQCh. 1 - Prob. 2PSQCh. 1 - Prob. 3PSQCh. 1 - Prob. 4PSQCh. 1 - Prob. 5PSQCh. 1 - Prob. 6PSQCh. 1 - Prob. 7PSQCh. 1 - Prob. 8PSQCh. 1 - Prob. 9PSQCh. 1 - 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Prob. 26CTCh. 1 - Prob. 27CTCh. 1 - Prob. 28CTCh. 1 - Prob. 29CTCh. 1 - Prob. 30CTCh. 1 - Prob. 31CTCh. 1 - Prob. 32CTCh. 1 - Prob. 33CTCh. 1 - Prob. 34CTCh. 1 - Prob. 35CTCh. 1 - Prob. 36CTCh. 1 - Prob. 37CTCh. 1 - Prob. 38CTCh. 1 - Prob. 39CTCh. 1 - Prob. 1CSTCh. 1 - Prob. 2CSTCh. 1 - Prob. 3CSTCh. 1 - Prob. 4CSTCh. 1 - Prob. 5CSTCh. 1 - Prob. 6CSTCh. 1 - Prob. 7CSTCh. 1 - Prob. 8CSTCh. 1 - Prob. 9CSTCh. 1 - Prob. 10CSTCh. 1 - Prob. 11CSTCh. 1 - Prob. 12CSTCh. 1 - Prob. 13CSTCh. 1 - Prob. 1PSPCh. 1 - Prob. 2PSPCh. 1 - Prob. 3PSPCh. 1 - Prob. 4PSPCh. 1 - Prob. 5PSPCh. 1 - Prob. 6PSPCh. 1 - Prob. 7PSP
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- 2. Write a system of linear equations in slope-intercept form has exactly one solution at the point (3, 4), such that both lines have negative slope (but neither one has slope of 1). Also write your system of equations with both equations written in standard form without any fractions. B 0 5 4 3 -2 1 -8-7-6-5-4-3-2 -1 12 3 -1 2 -3 -5 6 -7 -8arrow_forward4. Write a system of linear equations in slope-intercept form that has no solution, such that (3, 4), and (3,8) are solutions to the first equation, and (0, 4) is a solution to the second equation. Also write your system of equations with both equations written in standard form with out any fractions B 0 5 4 3 -2 + -8-7-6-5-4-3-2 -1 |- 1 2 3 -1 2 -3 4 -5 6 -7arrow_forwardShow how you can solve the system of equations by manipulating the algebra tiles while maintaining the balances. On this side of the page, use the addition (elimination) method. Keep track of what you did at each step by writing down the corresponding equivalent equations, as well as what you did to go from one equation to the next. 1. x + 2y = 5 x-2y=1 2. 2x+y=2 x-2y= 6arrow_forward
- e) x24 1) Which of these are equivalent to x³? For each expression that is equivalent to x², prove it by using the definition of exponents. For each that is not equivalent to x³, give an example using a specific value for x that shows that it represents a different number. a) (x5) d) f) 10-2 b) (x²) *|*arrow_forwardNow show how you can solve the system of equations by manipulating the algebra tiles while maintaining the balances, using the substitution method. Keep track of what you did at each step by writing down the corresponding equivalent equations, as well as what you did to go from one equation to the next. Δ 1. x + 2y = 5 x-2y=1 2. 2x + y = 2 x-2y= 6arrow_forward1. Write a system of two linear equations in slope-intercept form that has exactly one solution at the point (3, 4), such that both lines have positive slope (but neither one has slope of 1) Also write your system of equations with both equations written in standard form without any fractions. 8- 7 8 5 4 3 -2- + -8-7-6-5-4-3-2-1 1 2 3 -1 2 - 4 -5 -7 -8arrow_forward
- The original idea for creating this applet comes from Steve Phelps' Graph the Line applet. Directions: 1) Examine the equation shown on the right side of the screen. 2) Reposition the 2 big points so that the line is the graph of the displayed equation. 3) Click the "Check Answer" checkbox to check. If you're correct, the app will inform you. If you're not, you'll know this as well. If you're not correct, keep trying until you position the gray line correctly. 4) After correctly graphing the line, click the "Generate New Line" button.arrow_forwardProblem 1 & 2 answers 1. One diagonal has 11 squares, then total square in total for two diagonal line is 11 + 11 - 1 = 21 . 2. Each part has 5 squares.(except middle)Multiply by 4: 5 × 4 = 20.Add the middle square: 20 + 1 = 21.arrow_forward2. Now Figure out a different way you could determine how many squares there are in the figure, again without counting them all one-by-one. Briefly describe this other method:arrow_forward
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