ENGINEERING ECONOMIC ENHANCED EBOOK
ENGINEERING ECONOMIC ENHANCED EBOOK
14th Edition
ISBN: 9780190931940
Author: NEWNAN
Publisher: OXF
Question
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Chapter 15, Problem 29P
To determine

(a)

The projects that should be approved.

Expert Solution
Check Mark

Answer to Problem 29P

The projects B, C, D, E, H, and J should be approved.

Explanation of Solution

Given:

Salvage Value is 0.

Duration is 5 years.

Calculation:

Write the expression to calculate the present worth.

PW=P+A(1+i)n1(1+i)n×i ...... (I)

Substitute 14% for i and 5 for n in Equation (I)

PW=P+A(1+0.14)51(1+0.14)5×0.14=P+A(3.433) ...... (II)

Find the table to calculate the present worth.

Project PV(thousand)(COST) Uniform annual benefits Rate of return PW PW/COST
A $10 $2.98 15% $0.01 0.001
B $15 $5.58 25% $0.006 0.0004
C $5 $1.53 16% $0.0096 0.00192
D $20 $5.55 12% $.0065 0.000325
E $15 $4.37 14% $0.0026 0.000173
F $30 $9.81 19% $0.0046 0.000153
G $25 $7.81 17% $0.013 $0.00052
H $10 $3.49 22% $5.86 $0.586
I $5 $1.67 20% $0.0056 0.00112
J $10 $3.20 18% $0.00694 $0.000694

Here, the present worth has been calculated using Equation (I).

Conclusion:

Therefore, the projects B, C, D, E, H, and J should be approved.

To determine

(b)

The ranking order of all the acceptable projects.

Expert Solution
Check Mark

Answer to Problem 29P

The ranking has been shown below.

Project PW/COST Ranking
H $0.586 1
C 0.00192 2
J $0.000694 3
B 0.0004 4
D 0.000325 5
E 0.000173 6
F 0.000153 7
G $0.00052 8
A 0.001 9
I 0.00112 10

Explanation of Solution

Calculation:

Rank the project according to the PW/COST

Project PW/COST Ranking
H $0.586 1
C 0.00192 2
J $0.000694 3
B 0.0004 4
D 0.000325 5
E 0.000173 6
F 0.000153 7
G $0.00052 8
A 0.001 9
I 0.00112 10

Conclusion:

Rank the project according to the PW/COST

Project PW/COST Ranking
H $0.586 1
C 0.00192 2
J $0.000694 3
B 0.0004 4
D 0.000325 5
E 0.000173 6
F 0.000153 7
G $0.00052 8
A 0.001 9
I 0.00112 10
To determine

(c)

The projects to be approve if only $70000 is available.

Expert Solution
Check Mark

Answer to Problem 29P

The project to be approve if only $70000 available are H, C, J, B, D, and A.

Explanation of Solution

Calculation:

Project PW/COST Ranking
H $0.586 1
C 0.00192 2
J $0.000694 3
B 0.0004 4
D 0.000325 5
E 0.000173 6
F 0.000153 7
G $0.00052 8
A 0.001 9
I 0.00112 10

If the project budget is $70000 then the project with best return should be selected.

The project to be approve if only $70000 available are H, C, J, B, D, and A.

Sum=$10000+$5000+$10000+$15000+$20000+$10000=$70000

Hence, the chosen project is correct.

Conclusion:

Therefore, the project to be approve if only $70000 available are H, C, J, B, D, and A.

To determine

(d)

If the result will be the same if the projects are ranked on IRR and calculate the opportunity cost of capital.

Expert Solution
Check Mark

Answer to Problem 29P

No, there will be change in the rank of the project if they are ranked on IRR.

The opportunity cost of capital is 20%.

Explanation of Solution

Make the table to calculate the present worth.

Project PV(thousand)(COST) Uniform annual benefits Rate of return PW PW/COST
A $10 $2.98 15% $0.01 0.001
B $15 $5.58 25% $0.006 0.0004
C $5 $1.53 16% $0.0096 0.00192
D $20 $5.55 12% $.0065 0.000325
E $15 $4.37 14% $0.0026 0.000173
F $30 $9.81 19% $0.0046 0.000153
G $25 $7.81 17% $0.013 $0.00052
H $10 $3.49 22% $5.86 $0.586
I $5 $1.67 20% $0.0056 0.00112
J $10 $3.20 18% $0.00694 $0.000694

Here, the present worth has been calculated using Equation (I).

The project with highest PW is project H and the opportunity cost will be equal to its rate of return that is 22%.

Conclusion: No, there will be change in the rank of the project if they are ranked on IRR.

The opportunity cost of capital is 20%.

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