Program Explanation Given information: Differential equation is d y d x = 1 + 2 x y Formula used: If differential equation is, y ′ + p ( x ) y = q ( x ) Then integrating factor is, I . F . = e ∫ p ( x ) d x Then general solution of the differential equation is, y ( I . F . ) = ∫ q ( x ) ( I . F . ) d x + C Calculation: Consider, given differential equation as, d y d x = 1 + 2 x y ..........(1) This equation can be rewritten as, d y d x − 2 x y = 1 ..........(2) Now, integrating factor of the equation is, I . F . = e − ∫ 2 x d x = e − x 2 Now, general solution of the equation is, y ( e − x 2 ) = ∫ 1

MyLab Math with Pearson eText -- 24-Month Standalone Access Card -- For Differential Equations and Boundary Value Problems: Computing and Modeling Tech Update

5th Edition

ISBN: 9780134872971

Author: Edwards, C., Penney, David, Calvis

Publisher: PEARSON

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Chapter 1.5, Problem 29P

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To find: The general solution of the differential equation dydx=1+2xy and express the general solution in terms of the error function erf(x)=2π∫0xe− t 2dt

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Chapter 1.5, Problem 28P

Chapter 1.5, Problem 30P

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Chapter 1 Solutions

MyLab Math with Pearson eText -- 24-Month Standalone Access Card -- For Differential Equations and Boundary Value Problems: Computing and Modeling Tech Update

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Show that the substitution...Ch. 1.6 - Prob. 57P Ch. 1.6 - Prob. 58P Ch. 1.6 - Solve the differential equation dydx=xy1x+y+3 by...Ch. 1.6 - Prob. 60P Ch. 1.6 - Prob. 61P Ch. 1.6 - Prob. 62P Ch. 1.6 - Prob. 63P Ch. 1.6 - Prob. 64P Ch. 1.6 - Prob. 65P Ch. 1.6 - Prob. 66P Ch. 1.6 - Prob. 67P Ch. 1.6 - Prob. 68P Ch. 1.6 - Prob. 69P Ch. 1.6 - As in the text discussion, suppose that an...Ch. 1.6 - Prob. 71P Ch. 1.6 - Prob. 72P Ch. 1 - Prob. 1RP Ch. 1 - Prob. 2RP Ch. 1 - Prob. 3RP Ch. 1 - Prob. 4RP Ch. 1 - Prob. 5RP Ch. 1 - Prob. 6RP Ch. 1 - Prob. 7RP Ch. 1 - Prob. 8RP Ch. 1 - Prob. 9RP Ch. 1 - Prob. 10RP Ch. 1 - Prob. 11RP Ch. 1 - Prob. 12RP Ch. 1 - Prob. 13RP Ch. 1 - Prob. 14RP Ch. 1 - Prob. 15RP Ch. 1 - Prob. 16RP Ch. 1 - Prob. 17RP Ch. 1 - Prob. 18RP Ch. 1 - Prob. 19RP Ch. 1 - Prob. 20RP Ch. 1 - Prob. 21RP Ch. 1 - Prob. 22RP Ch. 1 - Prob. 23RP Ch. 1 - Prob. 24RP Ch. 1 - Prob. 25RP Ch. 1 - Prob. 26RP Ch. 1 - Prob. 27RP Ch. 1 - Prob. 28RP Ch. 1 - Prob. 29RP Ch. 1 - Prob. 30RP Ch. 1 - Prob. 31RP Ch. 1 - Prob. 32RP Ch. 1 - Prob. 33RP Ch. 1 - Prob. 34RP Ch. 1 - Prob. 35RP Ch. 1 - Prob. 36RP

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The general solution of the differential equation d y d x = 1 + 2 x y and express the general solution in terms of the error function e r f ( x ) = 2 π ∫ 0 x e − t 2 d t

Solution Summary: The author explains how the general solution of the differential equation can be rewritten as dy-dx=1+2xy.

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To find: The general solution of the differential equation dydx=1+2xy and express the general solution in terms of the error function erf(x)=2π∫0xe− t 2dt

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Chapter 1 Solutions