If you were in a high-speed spaceship traveling away from Earth at a speed close to that of light, would you measure your normal pulse to be slower, the same, or faster? How would your measurements of pulses of friends back on Earth be if you could monitor them from your ship? Explain.
![Check Mark](/static/check-mark.png)
Whether the normal pulse rate of person faster, slower or remain same when travelling away from earth in high-speed spaceship.
To Explain: The measurement of pulse of friend who is on the earth when person moving in spaceship.
Explanation of Solution
Introduction:
According to Einstein’s special theory of relativity, time is not absolute. When object moves with speed comparable to the speed of light, time in the moving frameslows down.
According to the first postulate of Einstein’s special theory of relativity, all the laws of physics are invariant in allthe inertial frames of reference. The inertial frame is a reference frame in which Newton’s laws of motion are valid. In another words, inertial frame is non-accelerating frame. Person who standing on the earth, observed the person in spaceship is moving. The normal heart rate of person in spaceship remains same measured inside the spaceship, because person is in inertial frame of reference.
The difference in reading observed because of the nature of observer’s frame of reference. Similarly,when person’s friend is on the earth and person on the spaceship monitored his pulse rate, person in spaceship observed that the earth is moving with respect to spaceship and heart rate of his friend found out to be slower. This is because with respect to person in spaceship, frame of reference of his friend is moving.
Chapter 15 Solutions
EP CONCEPTUAL PHYSICS-ONLINE ACCESS
Additional Science Textbook Solutions
Laboratory Experiments in Microbiology (12th Edition) (What's New in Microbiology)
Human Physiology: An Integrated Approach (8th Edition)
Cosmic Perspective Fundamentals
Campbell Biology (11th Edition)
Microbiology: An Introduction
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
- The velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed.arrow_forwardThe velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed.arrow_forwardThe velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed. NOT AI PLSarrow_forward
- The velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed.arrow_forwardThe velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed.arrow_forwardPlease don't use Chatgpt will upvote and give handwritten solutionarrow_forward
- No chatgpt pls will upvote Already got wrong chatgpt answerarrow_forwardAn electron and a proton are each accelerated through a potential difference of 21.0 million volts. Find the momentum (in MeV/c) and the kinetic energy (in MeV) of each, and compare with the results of using the classical formulas. Momentum (MeV/c) relativistic classical electron proton Kinetic Energy (MeV)arrow_forwardFour capacitors are connected as shown in the figure below. (Let C = 20.0 µF.) (a) Find the equivalent capacitance between points a and b. µF (b) Calculate the charge on each capacitor, taking ΔVab = 14.0 V. 20.0 µF capacitor µC 6.00 µF capacitor µC 3.00 µF capacitor µC capacitor C µCarrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305952300/9781305952300_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780133969290/9780133969290_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781107189638/9781107189638_smallCoverImage.jpg)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337553278/9781337553278_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780321820464/9780321820464_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780134609034/9780134609034_smallCoverImage.gif)