Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 15, Problem 21PDQ
In maize, a Ds or Ac transposon can alter the function of genes at or near the site of transposon insertion. It is possible for these elements to transpose away from their original insertion site, causing a reversion of the mutant phenotype. In some cases, however, even more severe
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When the organization of adjacent genes with highly similar sequences is in an inverted orientation, this can reduce the expression of other genes that have similar sequence and are located on other chromosomes. Explain the mechanism of how this generally occurs.
In a particular strain of Neurospora, a poky mutation exhibits biparental inheritance, whereas poky mutations in other strains are inherited only from the maternal parent. Explain these results.
Genes with highly similar sequence are often located adjacent one another in the genome. Gene duplication commonly arises from errors in replication. When the organization of such adjacent genes is in an inverted orientation, this can reduce the expression of other genes that have similar sequence and are located on other chromosomes. Explain the mechanism of how this generally occurs.
Chapter 15 Solutions
Concepts of Genetics (12th Edition)
Ch. 15 - If a point mutation occurs within a human egg cell...Ch. 15 - One of the most famous cases of an X-linked...Ch. 15 - The cancer drug melphalan is an alkylating agent...Ch. 15 - Geneticists often use the alkylating agent...Ch. 15 - Six months pregnant, an expectant mother had a...Ch. 15 - Six months pregnant, an expectant mother had a...Ch. 15 - HOW DO WE KNOW? In this chapter, we focused on how...Ch. 15 - CONCEPT QUESTION Review the Chapter Concepts list...Ch. 15 - What is a spontaneous mutation, and why are...Ch. 15 - Prob. 4PDQ
Ch. 15 - Prob. 5PDQCh. 15 - Why is a random mutation more likely to be...Ch. 15 - Most mutations in a diploid organism are...Ch. 15 - What is the difference between a silent mutation...Ch. 15 - Describe a tautomeric shift and how it may lead to...Ch. 15 - Contrast and compare the mutagenic effects of...Ch. 15 - Why are frameshift mutations likely to be more...Ch. 15 - Why are X rays more potent mutagens than UV...Ch. 15 - DNA damage brought on by a variety of natural and...Ch. 15 - Contrast the various types of DNA repair...Ch. 15 - Mammography is an accurate screening technique for...Ch. 15 - A significant number of mutations in the HBB gene...Ch. 15 - Describe how the Ames test screens for potential...Ch. 15 - Prob. 18PDQCh. 15 - Compare DNA transposons and retrotransposons. What...Ch. 15 - Prob. 20PDQCh. 15 - In maize, a Ds or Ac transposon can alter the...Ch. 15 - Prob. 22PDQCh. 15 - In a bacterial culture in which all cells are...Ch. 15 - Presented here are hypothetical findings from...Ch. 15 - Prob. 25ESPCh. 15 - Prob. 26ESPCh. 15 - What evidence indicates that mutations in human...Ch. 15 - Among Betazoids in the world of Star Trek, the...Ch. 15 - Skin cancer carries a lifetime risk nearly equal...Ch. 15 - It has been noted that most transposons in humans...Ch. 15 - Mutations in the IL2RG gene cause approximately 30...
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- In McCune-Albright syndrome, fibrous connective tissue replaces bone, tan patches (café-au-lait spots) dot the skin, and hormone abnormalities cause early puberty and malfunction of the thyroid, pituitary, and adrenal glands. The phenotype is highly variable, and all patients are somatic mosaics for the mutation, which is in the gene GNAS1. Why is the condition seen only in mosaics?arrow_forwardLeber Congenital Amaurosis (LCA) causes progressive vision loss due to defects in the gene that encodes RPE65 isomerase. Affected individuals are homozygous recessive for mutant alleles of the RPE65 gene. You are trying to determine the molecular nature of the mutations in three individuals with LCA. For ease of analysis, you may assume that each individual is homozygous for the same mutant allele (though the three individuals have different mutations than each other). You use the polymerase chain reaction to amplify DNA from each patient and you determine the sequence of the DNA and compare it to unaffected individuals. You identify the following differences. Note that the non-template strand of DNA is given and the changes are highlighted using red boldface. You can assume that the sequences are in the first reading frame (eg. the first three nucleotides of each sequence is a codon). The coding region of the gene is 1602 bp and the position of the sequences shown below is…arrow_forwardSuppose a researcher has three different Drosophila strains that have mutations in the bicoid gene called bicoid-A, bicoid-B, and bicoid-C; the wild type is designated bicoid +. To study these mutations, phenotypically normal female flies that are homozygous for the given bicoid mutation were obtained, and their oocytes were analyzed using a Northern blot to determine the size and/or amount of the bicoid mRNA and in situ hybridization to determine the bicoid mRNA location within the oocyte. A wild-type strain was also analyzed as a control. In both cases, the probe was complementary to the bicoid mRNA and the results are shown below. (Anterior is on the left; posterior is on the right.) Northern blot 1 2 - 3 4 In situ hybridization Wild type Lane 1. Wild type (bicoid*) Lane 2. bicoid-A Lane 3. bicoid-B Lane 4. bicoid-C bicoid-B bicoid-A bicoid-C Which mutation is likely to cause the embryo to develop two "anterior" ends? bicoid-B Obicoid-A bicoid-Carrow_forward
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Mitochondrial mutations; Author: Useful Genetics;https://www.youtube.com/watch?v=GvgXe-3RJeU;License: CC-BY