DATABASE SYSTEM CONCEPTS LCPO
7th Edition
ISBN: 9781265586577
Author: SILBERSCHATZ
Publisher: MCG
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Expert Solution & Answer
Chapter 15, Problem 20E
Explanation of Solution
a.
Nested-loop join:
Use R1 outer relation we need,
...
Explanation of Solution
b.
Block nested-loop join:
- If R1 is outer relation, we need ceiling (800 / (M−1)) ∗ 1500 + 800 disk accesses...
Explanation of Solution
c.
Merge join:
Let R1 and R2 be unsorted relation, and M be the pages of memory.
If M>800, then it is easy to do join in 2300(800+1500) disks.
Therefore, we will only take case where M<=800 pages...
Explanation of Solution
d.
Hash join:
Let us assume that there is no overflow in the join then R1 is smaller than R2, there for e will use R2 as probe relation and R1 as build relation...
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Students have asked these similar questions
How to develop a C program that receives the message sent by the provided program and displays the name and email included in the message on the screen?Here is the code of the program that sends the message for reference:
typedef struct { long tipo; struct { char nome[50]; char email[40]; } dados;} MsgStruct;
int main() { int msg_id, status; msg_id = msgget(1000, 0600 | IPC_CREAT); exit_on_error(msg_id, "Creation/Connection"); MsgStruct msg; msg.tipo = 5; strcpy(msg.dados.nome, "Pedro Silva"); strcpy(msg.dados.email, "pedro@sapo.pt"); status = msgsnd(msg_id, &msg, sizeof(msg.dados), 0); exit_on_error(status, "Send"); printf("Message sent!\n");}
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L= {a":n≥1}
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S→ABλ,
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is not context free.
Chapter 15 Solutions
DATABASE SYSTEM CONCEPTS LCPO
Knowledge Booster
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