A string with both ends held fixed is vibrating in its third harmonic. The waves have a speed of 192 m/s and a frequency of 240 Hz. The amplitude of the standing wave at an antinode is 0.400 cm. (a) Calculate the amplitude at points on the string a distance of (i) 40.0 cm; (ii) 20.0 cm; and (iii) 10.0 cm from the left end of the string. (b) At each point in part (a), how much time does it take the string to go from its largest upward displacement to its largest downward displacement? (c) Calculate the maximum transverse velocity and the maximum transverse acceleration of the string at each of the points in part (a).
A string with both ends held fixed is vibrating in its third harmonic. The waves have a speed of 192 m/s and a frequency of 240 Hz. The amplitude of the standing wave at an antinode is 0.400 cm. (a) Calculate the amplitude at points on the string a distance of (i) 40.0 cm; (ii) 20.0 cm; and (iii) 10.0 cm from the left end of the string. (b) At each point in part (a), how much time does it take the string to go from its largest upward displacement to its largest downward displacement? (c) Calculate the maximum transverse velocity and the maximum transverse acceleration of the string at each of the points in part (a).
A string with both ends held fixed is vibrating in its third harmonic. The waves have a speed of 192 m/s and a frequency of 240 Hz. The amplitude of the standing wave at an antinode is 0.400 cm. (a) Calculate the amplitude at points on the string a distance of (i) 40.0 cm; (ii) 20.0 cm; and (iii) 10.0 cm from the left end of the string. (b) At each point in part (a), how much time does it take the string to go from its largest upward displacement to its largest downward displacement? (c) Calculate the maximum transverse velocity and the maximum transverse acceleration of the string at each of the points in part (a).
Required information
An object is placed 20.0 cm from a converging lens with focal length 15.0 cm (see the figure, not drawn to scale). A
concave mirror with focal length 10.0 cm is located 76.5 cm to the right of the lens. Light goes through the lens, reflects
from the mirror, and passes through the lens again, forming a final image.
Converging
lens
Object
Concave
mirror
15.0 cm
-20.0 cm-
10.0 cm
d cm
d = 76.5.
What is the location of the final image?
cm to the left of the lens
!
Required information
A man requires reading glasses with +2.15-D refractive power to read a book held 40.0 cm away with a relaxed eye.
Assume the glasses are 1.90 cm from his eyes.
His uncorrected near point is 1.00 m. If one of the lenses is the one for distance vision, what should the refractive power of the other
lens (for close-up vision) in his bifocals be to give him clear vision from 25.0 cm to infinity?
2.98 D
!
Required information
Assume that the magnifier is held close to the eye. Use the standard near point of 25.0 cm to find the angular
magnification. An insect that is 4.10 mm long is placed 10.3 cm from a simple magnifier with a focal length of 13.0 cm.
What is the angular magnification?
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