Chemistry: An Atoms-Focused Approach (Second Edition)
Chemistry: An Atoms-Focused Approach (Second Edition)
2nd Edition
ISBN: 9780393614053
Author: Thomas R. Gilbert, Rein V. Kirss, Stacey Lowery Bretz, Natalie Foster
Publisher: W. W. Norton & Company
Question
Book Icon
Chapter 15, Problem 15.54QA
Interpretation Introduction

To find:

The acid dissociation constant value (Ka) for butanoic acid.

Expert Solution & Answer
Check Mark

Answer to Problem 15.54QA

Solution:

The acid dissociation constant value (Ka) for butanoic acid is 1.53 ×10-5

Explanation of Solution

1) Concept:

We are asked to determine the Ka value for the butanoic acid (C3H7COO-H) from known initial concentration of the acid and percent ionization. Structural formula for butanoic acid indicates that only one H atom per molecule is ionisable in aqueous solution.

The ionization reaction of butanoic acid can be written as

C3H7COOH aq+H2OlC3H7COO-aq+H3O+(aq)

And the equilibrium constant expression can be written as

Ka=C3H7COO-H3O+[C3H7COOH]

2) Formulae:

i) Percent ionization=A-equilibriumHAinitial ×100

ii) Ka=C3H7COO-H3O+[C3H7COOH]

3) Given:

i) Initial concentration of butanoic acid is 0.100M

ii) Percent ionization of the acid is 1.23%

4) Calculations:

From the given percent dissociation, we can find the C3H7COO-equilibrium using the percent dissociation formula as

Percent ionization=C3H7COO-equilibriumC3H7COOHinitial ×100

1.23%=C3H7COO-equilibrium0.100 M ×100

0.0123=C3H7COO-equilibrium0.100 M

C3H7COO-equilibrium=0.0123 ×0.100 M=0.00123M=1.23×10-3M

The equilibrium concentration of C3H7COO- is calculated as 1.23×10-3M

We can set up the RICE table to solve this problem.

Reaction C3H7COOH aq+H2OlC3H7COO-aq+H3O+(aq) C3H7COOH  (M) C3H7COO-(M) H3O+ (M)
Initial (I) 0.100 0.00 0.00
Change (C) -x +x +x
Equilibrium (E) 0.100-x x x

At equilibrium, H3O+=C3H7COO-=1.23×10-3M

The equilibrium concentration for the acid is

C3H7COOHequilibrium=C3H7COOHinitial-H3O+equilibrium

C3H7COOHequilibrium=0.100-1.23×10-3M= 0.09877M

Inserting the equilibrium values for all the species in the Ka expression, we get

Ka=C3H7COO-H3O+[C3H7COOH]

Ka=1.23×10-31.23×10-30.09877 =1.53 ×10-5

Thus, the acid dissociation constant value for butanoic acid is 1.53 ×10-5

Conclusion:

Ka value is calculated from the initial concentration and percent ionization of butanoic acid.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Calculate the flux of oxygen between the ocean and the atmosphere, given that: Temp = 18°C Salinity = 35 ppt Density = 1025 kg/m3 Oxygen concentration measured in bulk water = 263.84 mmol/m3 Wind speed = 7.4 m/s Oxygen is observed to be about 10% initially supersaturated
( ME EX1) Prblm 27-28: Can you explain to me both prblms in detail and for prblm 28 what do you mean bi conjugated bi ponds and those structures I'm confused...
A. Determine the number of electrons in a system of cyclic conjugation (zero if no cyclic conjugation). B. Specify whether the species is "a"-aromatic, "aa"-anti-aromatic, or "na"-non-aromatic (neither aromatic nor anti-aromatic). (Presume rings to be planar unless structure obviously prevents planarity. If there is more than one conjugated ring, count electrons in the largest.) 1. A.Electrons in a cyclic conjugated system. 18 B.The compound is (a, aa, or na) a 2. A.Electrons in a cyclic conjugated system. 10 B.The compound is (a, aa, or na) na

Chapter 15 Solutions

Chemistry: An Atoms-Focused Approach (Second Edition)

Ch. 15 - Prob. 15.11QACh. 15 - Prob. 15.12QACh. 15 - Prob. 15.13QACh. 15 - Prob. 15.14QACh. 15 - Prob. 15.15QACh. 15 - Prob. 15.16QACh. 15 - Prob. 15.17QACh. 15 - Prob. 15.18QACh. 15 - Prob. 15.19QACh. 15 - Prob. 15.20QACh. 15 - Prob. 15.21QACh. 15 - Prob. 15.22QACh. 15 - Prob. 15.23QACh. 15 - Prob. 15.24QACh. 15 - Prob. 15.25QACh. 15 - Prob. 15.26QACh. 15 - Prob. 15.27QACh. 15 - Prob. 15.28QACh. 15 - Prob. 15.29QACh. 15 - Prob. 15.30QACh. 15 - Prob. 15.31QACh. 15 - Prob. 15.32QACh. 15 - Prob. 15.33QACh. 15 - Prob. 15.34QACh. 15 - Prob. 15.35QACh. 15 - Prob. 15.36QACh. 15 - Prob. 15.37QACh. 15 - Prob. 15.38QACh. 15 - Prob. 15.39QACh. 15 - Prob. 15.40QACh. 15 - Prob. 15.41QACh. 15 - Prob. 15.42QACh. 15 - Prob. 15.43QACh. 15 - Prob. 15.44QACh. 15 - Prob. 15.45QACh. 15 - Prob. 15.46QACh. 15 - Prob. 15.47QACh. 15 - Prob. 15.48QACh. 15 - Prob. 15.49QACh. 15 - Prob. 15.50QACh. 15 - Prob. 15.51QACh. 15 - Prob. 15.52QACh. 15 - Prob. 15.53QACh. 15 - Prob. 15.54QACh. 15 - Prob. 15.55QACh. 15 - Prob. 15.56QACh. 15 - Prob. 15.57QACh. 15 - Prob. 15.58QACh. 15 - Prob. 15.59QACh. 15 - Prob. 15.60QACh. 15 - Prob. 15.61QACh. 15 - Prob. 15.62QACh. 15 - Prob. 15.63QACh. 15 - Prob. 15.64QACh. 15 - Prob. 15.65QACh. 15 - Prob. 15.66QACh. 15 - Prob. 15.67QACh. 15 - Prob. 15.68QACh. 15 - Prob. 15.69QACh. 15 - Prob. 15.70QACh. 15 - Prob. 15.71QACh. 15 - Prob. 15.72QACh. 15 - Prob. 15.73QACh. 15 - Prob. 15.74QACh. 15 - Prob. 15.75QACh. 15 - Prob. 15.76QACh. 15 - Prob. 15.77QACh. 15 - Prob. 15.78QACh. 15 - Prob. 15.79QACh. 15 - Prob. 15.80QACh. 15 - Prob. 15.81QACh. 15 - Prob. 15.82QACh. 15 - Prob. 15.83QACh. 15 - Prob. 15.84QACh. 15 - Prob. 15.85QACh. 15 - Prob. 15.86QACh. 15 - Prob. 15.87QACh. 15 - Prob. 15.88QACh. 15 - Prob. 15.89QACh. 15 - Prob. 15.90QACh. 15 - Prob. 15.91QACh. 15 - Prob. 15.92QACh. 15 - Prob. 15.93QACh. 15 - Prob. 15.94QACh. 15 - Prob. 15.95QACh. 15 - Prob. 15.96QACh. 15 - Prob. 15.97QACh. 15 - Prob. 15.98QACh. 15 - Prob. 15.99QACh. 15 - Prob. 15.100QACh. 15 - Prob. 15.101QACh. 15 - Prob. 15.102QACh. 15 - Prob. 15.103QACh. 15 - Prob. 15.104QACh. 15 - Prob. 15.105QACh. 15 - Prob. 15.106QACh. 15 - Prob. 15.107QACh. 15 - Prob. 15.108QACh. 15 - Prob. 15.109QACh. 15 - Prob. 15.110QA
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY