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Science Chemistry Organic Chemistry: Principles And Mechanisms

In Section 6.2d, we saw that pK a of an acid is equal to the pH of the solution at which half the acid has dissociated into its conjugate base. UV–vis spectroscopy can be used to measure the relative concentrations involved if the acid or conjugate base absorbs UV–vis light. With this in mind, suppose that a particular acid has λ max of 312 nm. The given figure shows the absorbance at that wavelength as a function of pH . pK a of the acid is to be determined. Concept introduction: If the given absorbance corresponds to the concentration of acid present, half the absorbance shows the acid which is dissociated in the equal concentration of its conjugate base. pK a of an acid is equal to the pH of the solution at which half the acid has dissociated into its conjugate base.

In Section 6.2d, we saw that pK a of an acid is equal to the pH of the solution at which half the acid has dissociated into its conjugate base. UV–vis spectroscopy can be used to measure the relative concentrations involved if the acid or conjugate base absorbs UV–vis light. With this in mind, suppose that a particular acid has λ max of 312 nm. The given figure shows the absorbance at that wavelength as a function of pH . pK a of the acid is to be determined. Concept introduction: If the given absorbance corresponds to the concentration of acid present, half the absorbance shows the acid which is dissociated in the equal concentration of its conjugate base. pK a of an acid is equal to the pH of the solution at which half the acid has dissociated into its conjugate base.

Solution Summary: The author explains that UV–vis spectroscopy can be used to measure the relative concentrations involved if the acid or conjugate base absorbs UV-vis light.

Organic Chemistry: Principles And Mechanisms

Organic Chemistry: Principles And Mechanisms

2nd Edition

ISBN: 9780393663549

Author: KARTY, Joel

Publisher: W. W. Norton and Company

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Chapter 15, Problem 15.39P

Interpretation Introduction

Interpretation:

In Section 6.2d, we saw that pKa of an acid is equal to the pH of the solution at which half the acid has dissociated into its conjugate base. UV–vis spectroscopy can be used to measure the relative concentrations involved if the acid or conjugate base absorbs UV–vis light. With this in mind, suppose that a particular acid has λmax of 312 nm. The given figure shows the absorbance at that wavelength as a function of pH. pKa of the acid is to be determined.

Concept introduction:

If the given absorbance corresponds to the concentration of acid present, half the absorbance shows the acid which is dissociated in the equal concentration of its conjugate base. pKa of an acid is equal to the pH of the solution at which half the acid has dissociated into its conjugate base.

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Chapter 15, Problem 15.38P

Chapter 15, Problem 15.40P

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For a titration of 40.00 mL of 0.0500 M oxalic acid H2C2O4 with 0.1000 M KOH, calculate the pH at each of the following volume of KOH used in the titration: 1) before the titration begin;2) 15 mL; 3) 20 mL; 4) 25 mL; 5) 40 mL; 6) 50 mL. Ka1 = 5.90×10^-2, Ka2 = 6.50×10^-5 for oxalic acid.

Predict the major organic product(s), if any, of the following reactions. Assume all reagents are in excess unless otherwise indicated.

Chapter 15 Solutions

Organic Chemistry: Principles And Mechanisms

Ch. 15 - Prob. 15.1P Ch. 15 - Prob. 15.2P Ch. 15 - Prob. 15.3P Ch. 15 - Prob. 15.4P Ch. 15 - Prob. 15.5P Ch. 15 - Prob. 15.6P Ch. 15 - Prob. 15.7P Ch. 15 - Prob. 15.8P Ch. 15 - Prob. 15.9P Ch. 15 - Prob. 15.10P

Ch. 15 - Prob. 15.11P Ch. 15 - Prob. 15.12P Ch. 15 - Prob. 15.13P Ch. 15 - Prob. 15.14P Ch. 15 - Prob. 15.15P Ch. 15 - Prob. 15.16P Ch. 15 - Prob. 15.17P Ch. 15 - Prob. 15.18P Ch. 15 - Prob. 15.19P Ch. 15 - Prob. 15.20P Ch. 15 - Prob. 15.21P Ch. 15 - Prob. 15.22P Ch. 15 - Prob. 15.23P Ch. 15 - Prob. 15.24P Ch. 15 - Prob. 15.25P Ch. 15 - Prob. 15.26P Ch. 15 - Prob. 15.27P Ch. 15 - Prob. 15.28P Ch. 15 - Prob. 15.29P Ch. 15 - Prob. 15.30P Ch. 15 - Prob. 15.31P Ch. 15 - Prob. 15.32P Ch. 15 - Prob. 15.33P Ch. 15 - Prob. 15.34P Ch. 15 - Prob. 15.35P Ch. 15 - Prob. 15.36P Ch. 15 - Prob. 15.37P Ch. 15 - Prob. 15.38P Ch. 15 - Prob. 15.39P Ch. 15 - Prob. 15.40P Ch. 15 - Prob. 15.41P Ch. 15 - Prob. 15.42P Ch. 15 - Prob. 15.43P Ch. 15 - Prob. 15.44P Ch. 15 - Prob. 15.45P Ch. 15 - Prob. 15.46P Ch. 15 - Prob. 15.47P Ch. 15 - Prob. 15.48P Ch. 15 - Prob. 15.49P Ch. 15 - Prob. 15.50P Ch. 15 - Prob. 15.51P Ch. 15 - Prob. 15.52P Ch. 15 - Prob. 15.53P Ch. 15 - Prob. 15.54P Ch. 15 - Prob. 15.55P Ch. 15 - Prob. 15.56P Ch. 15 - Prob. 15.57P Ch. 15 - Prob. 15.58P Ch. 15 - Prob. 15.59P Ch. 15 - Prob. 15.60P Ch. 15 - Prob. 15.61P Ch. 15 - Prob. 15.62P Ch. 15 - Prob. 15.63P Ch. 15 - Prob. 15.64P Ch. 15 - Prob. 15.65P Ch. 15 - Prob. 15.66P Ch. 15 - Prob. 15.67P Ch. 15 - Prob. 15.68P Ch. 15 - Prob. 15.1YT Ch. 15 - Prob. 15.2YT Ch. 15 - Prob. 15.3YT Ch. 15 - Prob. 15.4YT Ch. 15 - Prob. 15.5YT Ch. 15 - Prob. 15.6YT Ch. 15 - Prob. 15.7YT Ch. 15 - Prob. 15.8YT Ch. 15 - Prob. 15.9YT Ch. 15 - Prob. 15.10YT Ch. 15 - Prob. 15.11YT Ch. 15 - Prob. 15.12YT Ch. 15 - Prob. 15.13YT Ch. 15 - Prob. 15.14YT Ch. 15 - Prob. 15.15YT Ch. 15 - Prob. 15.16YT Ch. 15 - Prob. 15.17YT Ch. 15 - Prob. 15.18YT Ch. 15 - Prob. 15.19YT Ch. 15 - Prob. 15.20YT Ch. 15 - Prob. 15.21YT Ch. 15 - Prob. 15.22YT Ch. 15 - Prob. 15.23YT Ch. 15 - Prob. 15.24YT Ch. 15 - Prob. 15.25YT Ch. 15 - Prob. 15.26YT Ch. 15 - Prob. 15.27YT Ch. 15 - Prob. 15.28YT Ch. 15 - Prob. 15.29YT Ch. 15 - Prob. 15.30YT

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