Bundle: Physical Chemistry, 2nd + Student Solutions Manual
Bundle: Physical Chemistry, 2nd + Student Solutions Manual
2nd Edition
ISBN: 9781285257594
Author: David W. Ball
Publisher: Cengage Learning
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Chapter 15, Problem 15.22E
Interpretation Introduction

Interpretation:

The total number of states in an atom which has d6 electron configuration for its valence subshell is to be predicted.

Concept introduction:

A term symbol describes the orbital, spin, and total angular momenta of an electronic state. The symbol, L, represents the vector sum of orbital angular momentum. The symbol, S, represents the vector sum of spin angular momentum. The symbol, J, represents the total angular momentum. Therefore, the term symbol is represented as given below.

2S+1LJ

Expert Solution & Answer
Check Mark

Answer to Problem 15.22E

The total number of states in an atom which has d6 electron configuration for its valence subshell is 208.

Explanation of Solution

The value of an azimuthal quantum number, l, for each d electron is 2. The possible term symbols for d6 electron configuration is 1S, 1S, 1D, 1D, 1F, 1F, 1G, 1G, 1I, 3P, 3P, 3D, 3F, 3F, 3G, 3H, and 5D from Table 15.1. For the complete term symbols, the value of J is calculated first. The value of J can be calculated by the formula shown below.

J=L+S|LS|

Where J, L, and S are quantum numbers.

Each spin can contribute s=1/2. The value of S can be calculated from the superscript of the term symbols, which is 2S+1. The values of 2S+1 in the given term symbols are 1, 3, and 5. The values of S for the given term symbols are calculated as shown below.

2S+1=1S=02S+1=3S=12S+1=5S=2

The value of J for the 1S term symbol is shown below.

J=0+0|00|J=0

The value of J for the 1S term symbol is 0. The term symbol is 1S0.

The value of J for the 1D term symbol is shown below.

J=2+0|20|J=2

The value of J for the 1D term symbol is 2. The term symbol is 1D2.

The value of J for the 1F term symbol is shown below.

J=3+0|30|J=3

The value of J for the 1F term symbol is 3. The term symbol is 1F3.

The value of J for the 1G term symbol is shown below.

J=4+0|40|J=4

The value of J for the 1G term symbol is 4. The term symbol is 1G4.

The value of J for the 1I term symbol is shown below.

J=6+0|60|J=6

The value of J for the 1I term symbol is 6. The term symbol is 1I6.

The value of J for the 3P term symbol is shown below.

J=1+1|11|J=20

The value of J for the 3P term symbol is 2,1, and 0. The term symbols are 3P2, 3P1 and 3P0.

The value of J for the 3D term symbol is shown below.

J=2+1|21|J=31

The value of J for the 3D term symbol is 3,2, and 1. The term symbols are 3D3, 3D2, and 3D1.

The value of J for the 3F term symbol is shown below.

J=3+1|31|J=42

The value of J for the 3F term symbol is 4,3 and 2. The term symbols are 3F4, 3F3, and 3F2.

The value of J for the 3G term symbol is shown below.

J=4+1|41|J=53

The value of J for the 3G term symbol is 5,4, and 3. The term symbols are 3G5, 3G4, and 3G3.

The value of J for the 3H term symbol is shown below.

J=5+1|51|J=64

The value of J for the 3H term symbol is 6,5, and 4. The term symbols are 3H6, 3H5, and 3H4.

The value of J for the 5D term symbol is shown below.

J=2+2|22|J=40

The value of J for the 5D term symbol is 4,3,2,1, and 0. The term symbols are 5D4, 5D3, 5D2, 5D1, and 5D0.

The degeneracy is calculated by the formula 2J+1. The total term symbols are 1S0, 1S0, 1D2, 1D2, 1F3, 1F3, 1G4, 1G4, 1I6, 3P2, 3P1, 3P0, 3P2, 3P1, 3P0 3D3, 3D2, 3D1, 3F4, 3F3, 3F2, 3F4, 3F3, 3F2, 3G5, 3G4, 3G3, 3H6, 3H5, 3H4 5D4, 5D3, 5D2, 5D1, and 5D0. The degeneracy of the term symbols are 1, 1, 5, 5, 7, 7, 9, 9, 13, 5, 3, 1, 7, 5, 3, 9, 7, 5, 9, 7, 5, 11, 9, 7, 13, 11, 9, 9, 7, 5, 3, and 1 The total number of states is calculated by taking the sum of the degeneracy of each state. The total number of states are 208.

Conclusion

The total number of states in an atom which has d6 electron configuration for its valence subshell is 208.

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Chapter 15 Solutions

Bundle: Physical Chemistry, 2nd + Student Solutions Manual

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