Chapter 15, Problem 15.117QP

Interpretation Introduction

Interpretation:

Calculate the equilibrium constant values (Kc) for given the statement of standard entropy values at ${\text{20}}^{\text{0}}\text{C}$.

Concept Introduction:

Chemical equilibrium: The term applied to reversible chemical reactions. It is the point at which the rate of the forward reaction is equal to the rate of the reverse reaction. The equilibrium is achieved; the concentrations of reactant and products become constant.

Entropy $({\text{ΔG}}^0)$: The entropy is second law of thermodynamics it indicated for $({\text{ΔG}}^0)$ symbol, the many of chemical reactions cause changes in entropy and it plays on important role in determining in which direction (forward and backward) a chemical reaction spontaneously proceeds.

Standard free energy $({\text{ΔG}}_{\text{f}}^{\text{0}})$: This thermodynamic function associated with a chemical reaction that can be used to do work. The standard free energy of formation of a compound change of Gibbs free energy the formation of 1 mole of substance from its component elements, at their standard states (For example the obtained product is more stable at 25⁰C).

Equilibrium constant: Concentration of the products to the respective molar concentration of reactants it is called equilibrium constant. If the K value is less than one the reaction will move to the left side and the K values is higher (or) greater than one the reaction will move to the right side of reaction.

To find: Calculate the equilibrium constant $(Kp)$ values for given the statement.