Concept explainers
To infer:
The benefit a primitive cell would get from a symbiotic relationship with a mitochondrion
Introduction: The endosymbiont theory was proposed by Lynn Margulis. In 1966, Margulis proposed that the ancestors of eukaryotic cells lived in association with prokaryotic cells. In some cases prokaryotes might have lived inside eukaryotes. Prokaryotes might have entered as undigested prey or could have been internal

Answer to Problem 14STP
The primitive cell got chemical energy from mitochondria as a result of symbiotic relation with them.
Explanation of Solution
The endosymbiont theory proposed by Lynn Margulis suggests that an early eukaryotic cell or a primitive cell might have been parasitized by or ingested some aerobic prokaryotes. The aerobic prokaryotes established symbiotic relationship with the primitive cell. The prokaryotes got protection from the cell and in return the cell got chemical energy from them. The aerobic prokaryotes, over millions of years became mitochondria. They were no longer able to live on their own. So they became organelles (mitochondria) within all eukaryotic cells.
Chapter 15 Solutions
EP BIOLOGY 2012-STUDENTWORKS ONLINE
Additional Science Textbook Solutions
Anatomy & Physiology (6th Edition)
Campbell Biology (11th Edition)
Genetic Analysis: An Integrated Approach (3rd Edition)
Microbiology with Diseases by Body System (5th Edition)
Cosmic Perspective Fundamentals
Organic Chemistry (8th Edition)
- 8. Aerobic respiration of a 5 mM solution of tripeptide that is composed of the following three amino acids; alanine, leucine and isoleucine. Alanine breaks down to pyruvate, leucine breaks down to Acetyl-CoA and isoleucine breaks down to succinyl-CoA. Alanine NADH FADH2 OP ATP SLP ATP Total ATP Leucine Isoleucine Totals Show your work using dimensional analysis here: 4arrow_forward9. Aerobic respiration of one lipid molecule. The lipid is composed of one glycerol molecule connected to two fatty acid tails. One fatty acid is 12 carbons long and the other fatty acid is 18 carbons long in the figure below. Use the information below to determine how much ATP will be produced from the glycerol part of the lipid. Then, in part B, determine how much ATP is produced from the 2 fatty acids of the lipid. Finally put the NADH and ATP yields together from the glycerol and fatty acids (part A and B) to determine your total number of ATP produced per lipid. Assume no other carbon source is available. fatty acids glycerol 18 carbons 12 carbons 0=arrow_forwardinfluences of environment on the phenotype.arrow_forward
- What is the difference between codominance and phenotypic plasticity?arrow_forwardExplain the differences between polygeny and pleiotropy,arrow_forwardIf using animals in medical experiments could save human lives, is it ethical to do so? In your answer, apply at least one ethical theory in support of your position.arrow_forward
- You aim to test the hypothesis that the Tbx4 and Tbx5 genes inhibit each other's expression during limb development. With access to chicken embryos and viruses capable of overexpressing Tbx4 and Tbx5, describe an experiment to investigate whether these genes suppress each other's expression in the limb buds. What results would you expect if they do repress each other? What results would you expect if they do not repress each other?arrow_forwardYou decide to delete Fgf4 and Fgf8 specifically in the limb bud. Explain why you would not knock out these genes in the entire embryo instead.arrow_forwardYou implant an FGF10-coated bead into the anterior flank of a chicken embryo, directly below the level of the wing bud. What is the phenotype of the resulting ectopic limb? Briefly describe the expected expression domains of 1) Shh, 2) Tbx4, and 3) Tbx5 in the resulting ectopic limb bud.arrow_forward
- Design a grafting experiment to determine if limb mesoderm determines forelimb / hindlimb identity. Include the experiment, a control, and an interpretation in your answer.arrow_forwardThe Snapdragon is a popular garden flower that comes in a variety of colours, including red, yellow, and orange. The genotypes and associated phenotypes for some of these flowers are as follows: aabb: yellow AABB, AABb, AaBb, and AaBB: red AAbb and Aabb: orange aaBB: yellow aaBb: ? Based on this information, what would the phenotype of a Snapdragon with the genotype aaBb be and why? Question 21 options: orange because A is epistatic to B yellow because A is epistatic to B red because B is epistatic to A orange because B is epistatic to A red because A is epistatic to B yellow because B is epistatic to Aarrow_forwardA sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forward
- Human Anatomy & Physiology (11th Edition)BiologyISBN:9780134580999Author:Elaine N. Marieb, Katja N. HoehnPublisher:PEARSONBiology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStaxAnatomy & PhysiologyBiologyISBN:9781259398629Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa StouterPublisher:Mcgraw Hill Education,
- Molecular Biology of the Cell (Sixth Edition)BiologyISBN:9780815344322Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter WalterPublisher:W. W. Norton & CompanyLaboratory Manual For Human Anatomy & PhysiologyBiologyISBN:9781260159363Author:Martin, Terry R., Prentice-craver, CynthiaPublisher:McGraw-Hill Publishing Co.Inquiry Into Life (16th Edition)BiologyISBN:9781260231700Author:Sylvia S. Mader, Michael WindelspechtPublisher:McGraw Hill Education





