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Concept explainers
(a1)
To determine: The reason why do blood glucose and galactose increase and then decrease in healthy individuals during the lactose intolerance test in case A.
Introduction:
Lactose intolerance is a condition in which the people are unable to digest and process lactose (sugar in the milk.) This is because of the lack of an enzyme called as lactase. In this condition, the patient develops diarrhea and vomiting after ingestion of milk. This is because the patients cannot process the lactose into glucose and galactose.
(a2)
To determine: The reason behind the rise in blood galactose and glucose in lactose intolerant patients in case A.
Introduction: Lactose intolerance is a condition in which the peoples are unable to digest and process lactose (sugar in the milk.) This is because of the lack of an enzyme called as lactase. In this condition, the patient develops vomiting and diarrhea after ingestion of milk. This is because the patients cannot process the lactose into glucose and galactose.
(b1)
To determine: The reason behind the higher concentration of reducing sugars in patients after milk ingestion in case B.
Introduction:
Galactose-1-phosphate uridylyltransferase deficiency (GALT) deficiency is a condition in which an individual lacks the enzyme called as galactose-1-phosphate uridylyltransferase that is responsible for the production of the glucose from the reducing sugars such as galactose.
(b2)
To determine: The reason behind the appearance of galactose in urine in the patients in case B.
Introduction: Galactose-1-phosphate uridylyltransferase deficiency (GALT) deficiency is a condition in which an individual lacks the enzyme called as galactose-1-phosphate uridylyltransferase that is responsible for the production of the glucose from the reducing sugars such as galactose.
(c)
To determine: The reason for the accumulation of high concentration of glycogen in patient due to performing strenuous physical exercise in case C.
Introduction:
Glycogen storage disease type V is a deficiency disorder affecting the muscle in which glycogen phosphorylase enzymes are lacked in the muscle cells. The glycogen phosphorylase enzyme that is present in the muscle cells helps to covert glycogen into glucose molecule. Glucose is responsible for functioning of muscle cells.
(d)
To determine: The reason behind the low blood glucose level in case D patient.
Introduction:
Glycogen storage disease type VI deficiency is a disorder that affects the liver in which glycogen phosphorylase enzymes are lacked in the liver cells. The patient is lethargic with enlarged liver. Biopsy reveals large amount of excess glycogen but lower level of blood glucose.
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Chapter 15 Solutions
SaplingPlus for Lehninger Principles of Biochemistry (Six-Month Access)
- 1:30 5G 47% Problem 10 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a competitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' s mM¹ with 10 mg pe 20 V' 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forwardProblem 14 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:36 CO Problem 9 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of the catalytic efficiency (specificity constant) given that the enzyme concentration in this experiment is 5.0 μ.Μ. 1 [S] ¨‚ μM-1 1 V sμM-1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| O Гarrow_forward
- Problem 11 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a noncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forwardProblem 13 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 8 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of kcat given that the enzyme concentration in this experiment is 5.0 μM. 1 [S] , мм -1 1 V₁ s μM 1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward
- 1:33 5G. 46% Problem 12 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without an uncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 7 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of Vmax. Report your answer to three significant figures. 1 , mM-1 1 [S] V' sμM-¹ 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward12:33 CO Problem 5 of 15 4G 54% Done On the following Lineweaver-Burk 1 plot, identify the by dragging the Vmax point to the appropriate value on the line. NI 35 30- 25 20- 15- 10 5. 1 Vmax -15 10 -5 0 5 10 15 20 20 ||| で Г 25 30 1/[S]arrow_forward
- 12:20 V 0.1- 0:09. 0.08 0:07 0.06 -0.05- 0:04- -0.03- -0.02- 4G 56% Problem 1 of 15 Done On the following Michaelis-Menten plot, estimate the value of - Vmax by 1 2 dragging the line to the appropriate value on the y-axis. 0.01 V max 0 0.5 ||| 1.5 2.5 3.5 4 ISLarrow_forward12:33 CO 4G 54% Problem 6 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the Km. 1 mM-1 1 [S]' " s mM-1 V 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forwardV 0.1- 0:09 0:08 0:07- -0.06 -0.05 0:04- 0:03 0:02 0:01- Problem 2 of 15 Done On the following Michaelis-Menten plot, estimate the value of Kм by dragging the point to the appropriate value on the x-axis. I T | 0 0.5 1.5 2 KM -0:01- ||| 25 2.5 3 3.5 4 Г [S] powered by desmosarrow_forward
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