Explanation Approach: A permutation of a set of objects is an ordering of these objects. If the set has n objects, then the number of ways of ordering the r -element subsets of the set is denoted P ( n , r ) and is called the number of permutations of n objects taken r at a time. P ( n , r ) = n ! ( n − r ) ! …… ( 1 ) Calculation: Consider the given word. RANDOM The number of letters are 6 and number of letters to be ordered are 6 . Substitute 6 for n and 6 for r in equation ( 1 )

Algebra and Trigonometry (MindTap Course List)

4th Edition

ISBN: 9781305071742

Author: James Stewart, Lothar Redlin, Saleem Watson

Publisher: Cengage Learning

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Counting Principles

In statistics, the counting principle can be said to be the concept in which the quantity of an item is determined. There can be a single item, or a group of items, or items that are related to each other. In every possible set of items, the quantity of …

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Chapter 14.CR, Problem 19E

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The number of different anagrams of the word “RANDOM”.

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Chapter 14.CR, Problem 18E

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Algebra and Trigonometry (MindTap Course List)

Ch. 14.1 - CONCEPTS The Fundamental Counting Principle says...Ch. 14.1 - CONCEPTS The number of ways of arranging r objects...Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E Ch. 14.1 - Prob. 5E Ch. 14.1 - Prob. 6E Ch. 14.1 - Prob. 7E Ch. 14.1 - Prob. 8E Ch. 14.1 - Prob. 9E Ch. 14.1 - Prob. 10E

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The number of different anagrams of the word “RANDOM”.

Solution Summary: The author explains how the number of different anagrams of the word "RANDOM" is 720.

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Chapter 14 Solutions

To find:

The number of different anagrams of the word “RANDOM”.