Chapter 14.8, Problem 9PPS

To determine

To calculate: The factors of the trinomial $b^2-9b+20$ .

Answer to Problem 9PPS

The factors of the trinomial $b^2-9b+20$ are $b-5\text{and}b-4$ .

Explanation of Solution

Given Information:

The trinomial expression is $b^2-9b+20$ .

Calculation:

The given trinomial is $b^2-9b+20$ .

Split $-9b$ into two parts such that their product is equal to the product of $b^2$ and 20.

  $\begin{array}{c}{b}^2-9b+20=b^2-4b-5b+20\\ =b\left(b-4\right)-5\left(b-4\right)\\ =\left(b-4\right)\left(b-5\right)\end{array}$

Hence, the factors of the trinomial $b^2-9b+20$ are $b-5\text{and}b-4$ .