Explanation Given data: The water is at 212 ° F . Weight of the water ( w ) is 11.0 lb. Formula used: Write the expression for heat of vaporization as follows. L v = Q w (1) Here, Q is the quantity of heat, and w is the weight of the water. Calculation of heat required to vaporize the water at 212 ° F ( Q ) : Refer to the Table 15 in Appendix C for heat of vaporization for the water. From the table, the heat of vaporization for the water is 2.26 × 10 6 J / kg . L v = 2.26 × 10 6 J / kg (2) Write the conversion factor between Btu / lb to J / kg as follows. 1 Btu / lb = 2326 J / kg Rearrange the expression as follows. 1 J / kg = 1 2326 Btu / lb Substitute 1 2326 Btu / lb for J / kg in equation (2) as follows

11th Edition

ISBN: 9780134159386

Author: Dale Ewen, Neill Schurter, Erik Gundersen

Publisher: PEARSON

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Calorimetry

Measuring the heat transferred during chemical reactions or other physical processes is known as calorimetry. It comes under the branch of thermochemistry.

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Chapter 14.8, Problem 3P

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Calculate the quantity of heat (in terms of Btu) required to vaporize 11.0 lb of water at 212°F.

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Chapter 14.8, Problem 2P

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Chapter 14 Solutions

Applied Physics (11th Edition)

Ch. 14.1 - Find each temperature as indicated. 1. TF=77F,...Ch. 14.1 - Find each temperature as indicated. 2. TF=113F,...Ch. 14.1 - Find each temperature as indicated. 3. TF=257F,...Ch. 14.1 - Find each temperature as indicated. 4. TC=15C,...Ch. 14.1 - Find each temperature as indicated. 5. TC=145C,...Ch. 14.1 - Find each temperature as indicated. 6. TC=35C,...Ch. 14.1 - Prob. 7P Ch. 14.1 - Prob. 8P Ch. 14.1 - Find each temperature as indicated. 9. TC=95C,...Ch. 14.1 - Prob. 10P

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Calculate the quantity of heat (in terms of Btu) required to vaporize 11.0 lb of water at 212 ° F .

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Calculate the quantity of heat (in terms of Btu) required to vaporize 11.0 lb of water at 212°F.

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