Explanation The first step of a mechanism involving the reaction of bromine is, Br 2 ( g ) ⇌ k − 1 k 1 2 Br ( g ) (fast,equilibrium) The rate of the forward reaction is, Rate = k 1 [ Br 2 ] Where, k 1 is the rate constant for the forward reaction. [ Br 2 ] is the concentration of Br 2 . The rate of the reverse reaction is, Rate = k − 1 [ Br ] 2 Where, k − 1 is the rate constant for the reverse reaction. [ Br ] is the concentration of Br . 2 is the order of Br . As both the forward and reverse reactions are in equilibrium. So, the rate of the forward reaction will be equal to the rate of the reverse reaction

Chemistry: The Central Science (14th Edition)

14th Edition

ISBN: 9780134414232

Author: Theodore E. Brown, H. Eugene LeMay, Bruce E. Bursten, Catherine Murphy, Patrick Woodward, Matthew E. Stoltzfus

Publisher: PEARSON

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Chapter 14.6, Problem 14.15.2PE

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To determine: The expression that relates the concentration of Br(g) to that of Br2(g) .

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Chapter 14.6, Problem 14.15.1PE

Chapter 14, Problem 1DE

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Chapter 14 Solutions

Chemistry: The Central Science (14th Edition)

Ch. 14.2 - If the experiment in Figure 14.2 is run for 60 s,...Ch. 14.2 - Prob. 14.1.2PE Ch. 14.2 - Which of the following could be the instantaneous...Ch. 14.2 - Using Figure 14.3, determine the instantaneous...Ch. 14.2 - At a certain time in a reaction, substance A is...Ch. 14.2 - Prob. 14.3.2PE Ch. 14.3 - Suppose the rate law for the reaction in this...Ch. 14.3 - Assuming that rate = k[A][B], rank the mixtures...Ch. 14.3 - Prob. 14.5.1PE Ch. 14.3 - Prob. 14.5.2PE

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The expression that relates the concentration of Br ( g ) to that of Br 2 ( g ) .

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To determine: The expression that relates the concentration of Br(g) to that of Br2(g) .

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Chapter 14 Solutions